QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#432614#1813. Joy with PermutationsunputdownableRE 1ms3888kbC++172.4kb2024-06-07 13:59:002024-06-07 13:59:00

Judging History

你现在查看的是最新测评结果

  • [2024-06-07 13:59:00]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:3888kb
  • [2024-06-07 13:59:00]
  • 提交

answer

// #pragma GCC optimize("Ofast")
// #pragma GCC optimize("unroll-loops")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2")
#include <bits/stdc++.h>
// #define int long long
#define i64 long long
#define pii pair <int, int> 
using namespace std;
inline int read(void) {
    int x=0,sgn=1; char ch=getchar();
    while(ch<48||57<ch) {if(ch==45)sgn=0;ch=getchar();}
    while(47<ch&&ch<58) {x=x*10+ch-48;   ch=getchar();}
    return sgn? x:-x;
}
void write(int x) {
    if(x<0) putchar('-'),x=-x;
    if(x>9) write(x/10);
    putchar(x%10+'0');
}
/*
    write((Ans%p+p)%p); pls
*/
// int a[100005];
int n;
int res[100005],a1,a2,b1,b2,A,B;
inline int Ask(int x,int y,int z) {
    printf("? 1 %d %d %d\n",x,y,z); fflush(stdout);
    int res; scanf("%d",&res);
    // res=a[x]+a[y]+a[z]-min({a[x],a[y],a[z]})-max({a[x],a[y],a[z]});
    return res;
}
inline int Ask2(int x,int y) {
    printf("? 2 %d %d\n",x,y); fflush(stdout);
    int res; scanf("%d",&res);
    //  res=(a[x]<a[y] ? x : y); 
    return res;
}
inline void init() {
    int val[4],rnk[4];
    val[0]=rnk[0]=Ask(1,2,3),val[1]=rnk[1]=Ask(1,2,4),val[2]=rnk[2]=Ask(1,3,4),val[3]=rnk[3]=Ask(2,3,4);
    sort(rnk,rnk+4);
    A=rnk[0]; B=rnk[2];
    if(val[0]==A) {
        if(val[1]==A) a1=1,a2=2,b1=3,b2=4; 
        else if(val[2]==A) a1=1,a2=3,b1=2,b2=4;
        else a1=2,a2=3,b1=1,b2=4;
    } else if(val[1]==A) {
        if(val[2]==A) a1=1,a2=4,b1=2,b2=3;
        else a1=2,a2=4,b1=1,b2=3;
    } else a1=3,a2=4,b1=1,b2=2;
}
signed main() {
    // freopen("localinput","r",stdin);
    // freopen("localoutput","w",stdout);
    scanf("%d",&n); init();
    for(int i=5; i<=n; ++i) {
        int v=Ask(a1,b1,i);
        if(v<A) {
            res[a2]=A; A=v;
            a2=i;
        } else if(v==A) {
            res[a1]=A;
            a1=i; A=Ask(a1,a2,b1);
        } else if(A<v&&v<B) {
            res[i]=v;
        } else if(v==B) {
            res[b1]=B;
            b1=i; A=Ask(a1,b1,b2);
        } else if(v>B) {
            res[b2]=B; B=v;
            b2=i;
        } else assert(0);
    }
    int r=Ask2(a1,a2);
    res[r]=1; res[a1^a2^r]=2; assert(A==2);
    r=Ask2(b1,b2);
    res[r]=n-1; res[b1^b2^r]=n; assert(B==n-1);
    printf("!"); for(int i=1; i<=n; ++i) printf(" %d",res[i]); printf("\n"); fflush(stdout);
    // fprintf(stderr,"%.4lf\n",1.0*clock()/CLOCKS_PER_SEC);
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 3888kb

input:

5
4
3
3
4
3
2
4
3

output:

? 1 1 2 3
? 1 1 2 4
? 1 1 3 4
? 1 2 3 4
? 1 1 2 5
? 1 5 4 2
? 2 5 4
? 2 2 3
! 3 5 4 1 2

result:

ok OK (6 2)

Test #2:

score: -100
Runtime Error

input:

60000
2
2
3
3
3
4
4
4
5
5
6
6
6
7
7
8
8
8
9
9
10
10
10
11
11
12
12
12
13
13
14
14
14
15
15
16
16
16
17
17
18
18
18
19
19
20
20
20
21
21
22
22
22
23
23
24
24
24
25
25
26
26
26
27
27
28
28
28
29
29
30
30
30
31
31
32
32
32
33
33
34
34
34
35
35
36
36
36
37
37
38
38
38
39
39
40
40
40
41
41
42
42
42
43
43...

output:

? 1 1 2 3
? 1 1 2 4
? 1 1 3 4
? 1 2 3 4
? 1 1 3 5
? 1 1 5 4
? 1 1 5 6
? 1 6 2 5
? 1 6 5 7
? 1 6 5 8
? 1 6 8 7
? 1 6 8 9
? 1 9 2 8
? 1 9 8 10
? 1 9 8 11
? 1 9 11 10
? 1 9 11 12
? 1 12 2 11
? 1 12 11 13
? 1 12 11 14
? 1 12 14 13
? 1 12 14 15
? 1 15 2 14
? 1 15 14 16
? 1 15 14 17
? 1 15 17 16
? 1 15 17...

result: