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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#43122#4513. Slide Paradexiaoyaowudi0 7185ms27668kbC++144.1kb2022-08-08 11:05:262022-08-08 11:05:26

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-08-08 11:05:26]
  • 评测
  • 测评结果:0
  • 用时:7185ms
  • 内存:27668kb
  • [2022-08-08 11:05:26]
  • 提交

answer

#include <cstdio>
#include <algorithm>
#include <vector>
#include <cstring>
using namespace std;
constexpr int N=210,M=5010,inf=1e9;
vector<int> es[N];
int eds[M][3],n,m,ind[N],otd[N];
bool vis[N];
void clear()
{
	memset(vis,0,sizeof(vis));
	memset(ind,0,sizeof(ind));
	memset(otd,0,sizeof(otd));
	for(int i(1);i<=n;++i)
		es[i].clear();
}
void dfs(int u){
	vis[u]=true;
	for(int v:es[u])
	if(!vis[v])
		dfs(v);
}
namespace flow
{
	constexpr int N=410,M=5010+(N<<1);
	int hd[N],nxt[M<<1],cur[N],tv[M<<1],ecnt=1,tag[N],w[M<<1];
	void clear()
	{
		ecnt=1;
		memset(hd,0,sizeof(hd));
	}
	int add_edge(int u,int v,int c)
	{
		nxt[++ecnt]=hd[u];
		tv[ecnt]=v;
		hd[u]=ecnt;
		w[ecnt]=c;
		return ecnt;
	}
	int bfs(int s,int t)
	{
		memset(tag,0,sizeof(tag));
		static int qq[N];int l(1),r(1);
		qq[r++]=s;tag[s]=1;
		while(l<r)
		{
			int u=qq[l++];
			for(int p(hd[u]);p;p=nxt[p]) if(w[p] && !tag[tv[p]])
			{
				tag[tv[p]]=tag[u]+1;
				qq[r++]=tv[p];
			}
		}
		return tag[t]!=0;
	}
	int dfs(int u,int t,int fl)
	{
		if(u==t) return fl;
		int ret(0);
		for(int (&p)(cur[u]);p;p=nxt[p])
		if(w[p] && tag[tv[p]]==tag[u]+1)
		{
			int k=dfs(tv[p],t,min(w[p],fl));
			fl-=k;ret+=k;
			w[p]-=k;w[p^1]+=k;
			if(!fl)
				break;
		}
		return ret;
	}
	int dinic(int s,int t)
	{
		int ans(0);
		while(bfs(s,t))
		{
			memcpy(cur,hd,sizeof(cur));
			ans+=dfs(s,t,inf);
		}
		return ans;
	}
}
namespace euler_cycle
{
	constexpr int N=1000010;
	int hd[N],nxt[N],tv[N],ecnt=1,mk[N];bool vis[N];
	void clear()
	{
		ecnt=1;
		memset(hd,0,sizeof(hd));
	}
	void add_edge(int u,int v)
	{
		// printf("u %d v %d\n",u,v);
		nxt[++ecnt]=hd[u];
		tv[ecnt]=v;
		hd[u]=ecnt;
	}
	void dfs(int u)
	{
		// printf("u %d mk[u] %d\n",u,mk[u]);
		vis[u]=true;
		for(int p(hd[u]);p;p=nxt[p])
		if(!vis[tv[p]])
		{
			mk[tv[p]]=p^1;
			dfs(tv[p]);
		}
	}
	void dfs(int u,vector<int> &ans)
	{
		// printf("dfs %d\n",u);
		if(hd[u]==mk[u])
			hd[u]=nxt[hd[u]];
		if(!hd[u] && mk[u])
		{
			ans.push_back(tv[mk[u]]);
			dfs(tv[mk[u]],ans);
		}
		else if(hd[u])
		{
			int v=tv[hd[u]];hd[u]=nxt[hd[u]];
			ans.push_back(v);
			dfs(v,ans);
		}
	}
	vector<int> calc(int s=1)
	{
		memset(vis,0,sizeof(vis));
		memset(mk,0,sizeof(mk));
		dfs(s);
		vector<int> ret;
		dfs(s,ret);
		return ret;
	}
}
int calc(int k)
{
	int s(n*2+1),t(s+1);
	flow::clear();
	int tot(0);
	for(int i(1);i<=n;++i)
	{
		flow::add_edge(s,i,k-otd[i]);
		flow::add_edge(i,s,0);
		flow::add_edge(i+n,t,k-ind[i]);
		flow::add_edge(t,i+n,0);
		tot+=(k-ind[i]);
	}
	for(int i(1);i<=m;++i)
	{
		flow::add_edge(eds[i][0],eds[i][1]+n,inf);
		eds[i][2]=flow::add_edge(eds[i][1]+n,eds[i][0],0);
	}
	return flow::dinic(s,t)-tot;
}
bool check(int mid)
{
	return calc(mid)>=calc(mid-1);
}
int main()
{
	// freopen("GC.in","r",stdin);
	// freopen("GC.out","w",stdout);
	int TC;
	scanf("%d",&TC);
	for(int ti(1);ti<=TC;++ti)
	{
		printf("Case #%d: ",ti);
		scanf("%d%d",&n,&m);
		for(int i(1),u,v;i<=m;++i)
		{
			scanf("%d%d",&u,&v);
			es[u].push_back(v);
			++ind[v];++otd[u];
			eds[i][0]=u;eds[i][1]=v;
		}
		dfs(1);
		bool ok(true);
		for(int i(1);i<=n && ok;++i)
		if(!vis[i])
			ok=false;
		if(!ok)
		{
			printf("IMPOSSIBLE\n");
			clear();
			continue;
		}
		// int bl(0),br(1000000/n);
		// for(int i(1);i<=n;++i)
		// 	bl=max(bl,max(ind[i],otd[i]));
		// int ans(bl),mid;
		// ++bl;
		// while(bl<=br){
		// 	mid=(bl+br)>>1;
		// 	if(check(mid))
		// 	{
		// 		ans=mid;
		// 		bl=mid+1;
		// 	}else
		// 		br=mid-1;
		// }
		int ans(1000000/n);
		int k(calc(ans));
		// printf("%d %d\n",ans,k);
		if(k!=0)
		{
			printf("IMPOSSIBLE\n");
			clear();
			continue;
		}
		euler_cycle::clear();
		for(int i(1);i<=m;++i)
		{
			int c=flow::w[eds[i][2]]+1;
			for(int j(1);j<=c;++j)
				euler_cycle::add_edge(eds[i][0],eds[i][1]);
		}
		auto ap=euler_cycle::calc();
		int l=ap.size();
		printf("%d\n1 ",l+1);
		for(int i(0);i<l;++i)
			printf("%d%c",ap[i]," \n"[i==l-1]);
		clear();
	}
	return 0;
}

詳細信息

Test #1:

score: 0
Wrong Answer
time: 7185ms
memory: 27584kb

input:

100
5 8
1 2
1 3
1 4
1 5
2 1
3 1
4 1
5 1
5 10
1 3
1 4
2 3
2 5
3 1
3 4
3 5
4 2
5 1
5 3
5 10
1 4
2 3
2 5
3 1
3 5
4 2
4 3
4 5
5 1
5 2
3 6
1 2
1 3
2 1
2 3
3 1
3 2
5 10
1 2
1 5
2 3
2 4
3 1
4 3
4 5
5 2
5 3
5 4
4 10
1 2
1 3
1 4
2 1
2 3
2 4
3 1
3 4
4 2
4 3
5 10
1 2
1 3
2 1
2 4
3 1
3 5
4 2
4 5
5 3
5 4
5 10
1 ...

output:

Case #1: IMPOSSIBLE
Case #2: 1000001
1 4 2 5 3 5 3 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1 4 2 5 3 1...

result:

wrong answer the slide from 5 to 2 hasn't be used (test case 18)

Test #2:

score: 0
Wrong Answer
time: 4044ms
memory: 27668kb

input:

100
199 4980
1 95
1 96
1 105
1 124
1 130
1 131
1 135
1 137
1 139
1 140
1 141
1 147
1 155
1 172
1 174
1 179
1 183
1 188
1 193
1 196
1 197
2 3
2 5
2 13
2 14
2 17
2 20
2 24
2 26
2 30
2 41
2 44
2 45
2 52
2 56
2 67
2 70
2 71
2 74
2 78
2 84
2 85
2 90
2 92
2 93
2 97
2 107
2 111
2 113
2 122
2 124
2 128
2 13...

output:

Case #1: IMPOSSIBLE
Case #2: IMPOSSIBLE
Case #3: 999995
1 193 195 197 200 169 196 195 197 200 169 191 195 197 200 169 178 196 195 197 200 169 174 195 197 200 169 164 198 193 194 182 197 200 169 164 193 194 182 197 200 169 164 174 194 182 197 200 169 164 162 198 193 194 182 197 200 169 164 162 197 20...

result:

wrong answer the slide from 7 to 4 hasn't be used (test case 3)