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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#430280 | #6325. Peaceful Results | do_while_true | TL | 0ms | 0kb | C++20 | 4.6kb | 2024-06-03 17:13:01 | 2024-06-03 17:13:01 |
answer
#include<cstdio>
#include<vector>
#include<queue>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<set>
#include<map>
#include<ctime>
#include<random>
#include<array>
#include<assert.h>
#define pb emplace_back
#define mp make_pair
#define fi first
#define se second
#define dbg(x) cerr<<"In Line "<< __LINE__<<" the "<<#x<<" = "<<x<<'\n'
#define dpi(x,y) cerr<<"In Line "<<__LINE__<<" the "<<#x<<" = "<<x<<" ; "<<"the "<<#y<<" = "<<y<<'\n'
#define DE(fmt,...) fprintf(stderr, "Line %d : " fmt "\n",__LINE__,##__VA_ARGS__)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int>pii;
typedef pair<ll,int>pli;
typedef pair<ll,ll>pll;
typedef pair<int,ll>pil;
typedef vector<int>vi;
typedef vector<ll>vll;
typedef vector<pii>vpii;
typedef vector<pll>vpll;
template<typename T>T cmax(T &x, T y){return x=x>y?x:y;}
template<typename T>T cmin(T &x, T y){return x=x<y?x:y;}
template<typename T>
T &read(T &r){
r=0;bool w=0;char ch=getchar();
while(ch<'0'||ch>'9')w=ch=='-'?1:0,ch=getchar();
while(ch>='0'&&ch<='9')r=r*10+(ch^48),ch=getchar();
return r=w?-r:r;
}
template<typename T1,typename... T2>
void read(T1 &x,T2& ...y){read(x);read(y...);}
const int mod=998244353;
inline void cadd(int &x,int y){x=(x+y>=mod)?(x+y-mod):(x+y);}
inline void cdel(int &x,int y){x=(x-y<0)?(x-y+mod):(x-y);}
inline int add(int x,int y){return (x+y>=mod)?(x+y-mod):(x+y);}
inline int del(int x,int y){return (x-y<0)?(x-y+mod):(x-y);}
int qpow(int x,int y){
int s=1;
while(y){
if(y&1)s=1ll*s*x%mod;
x=1ll*x*x%mod;
y>>=1;
}
return s;
}
const int N=2000010;
namespace MyPoly{
int *getw(int n, int type) {
static int w[N/2];
w[0]=1;w[1]=qpow(type==1?3:332748118,(mod-1)/n);
for(int i=2;i<n/2;i++)w[i]=1ll*w[i-1]*w[1]%mod;
return w;
}
struct Poly{
vi a;
Poly(){vi().swap(a);}
Poly(int x){vi().swap(a);a.resize(x);}
int size(){return a.size();}
void resize(int x){a.resize(x);}
int &operator[](int i){return a[i];}
};
void DFT(Poly &a){//转置
int n=a.size();
for(int i=n/2;i;i>>=1){
int *w=getw(i<<1,1);
for(int j=0;j<n;j+=i<<1){
for(int k=0;k<i;++k){
int u=a[j+k],v=a[j+i+k];
a[j+k]=add(u,v);
a[j+i+k]=del(1ll*u*w[k]%mod,1ll*v*w[k]%mod);
}
}
}
}
void IDFT(Poly &a){
int n=a.size();
for(int i=1;i<n;i<<=1){
int *w=getw(i<<1,-1);
for(int j=0;j<n;j+=i<<1){
for(int k=0;k<i;++k){
int v=1ll*a[j+i+k]*w[k]%mod;
a[j+i+k]=del(a[j+k],v);
cadd(a[j+k],v);
}
}
}
int inv=qpow(n,mod-2);
for(int i=0;i<n;i++)a[i]=1ll*a[i]*inv%mod;
}
Poly operator*(Poly f,Poly g){
int n=f.size(),m=g.size();
int len=1,ct=0;
while(len<=n+m)len<<=1,++ct;
f.resize(len);g.resize(len);
DFT(f);
DFT(g);
for(int i=0;i<len;i++)f[i]=1ll*f[i]*g[i]%mod;
IDFT(f);
f.resize(n+m-1);
return f;
}
}
using namespace MyPoly;
int n,A[4],B[4],C[4];
int fac[N],inv[N];
void solve(){
read(n);
for(int i=1;i<=3;i++)read(A[i]);
for(int i=1;i<=3;i++)read(B[i]);
for(int i=1;i<=3;i++)read(C[i]);
int a[6][7]={
{1,0,1,0,1,0,A[2]-A[1]},
{0,1,0,1,0,1,A[3]-A[1]},
{1,0,0,-1,-1,1,B[2]-B[1]},
{0,1,1,-1,-1,0,B[3]-B[1]},
{1,0,-1,1,0,-1,C[2]-C[1]},
{0,1,-1,0,1,-1,C[3]-C[1]}
};
for(int i=0;i<6;i++){
int p=-1;
for(int j=i;j<6;j++)
if(a[j][i]){
p=j;
break;
}
if(p==-1){puts("0");return ;}
swap(a[i],a[p]);
for(int j=i+1;j<7;j++)
if(a[i][j]%a[i][i]){
puts("0");
return ;
}
else a[i][j]/=a[i][i];
a[i][i]=1;
for(int j=0;j<6;j++)if(i!=j){
int t=a[j][i];
for(int k=0;k<7;k++)
a[j][k]-=a[i][k]*t;
}
}
int coef=fac[n];
for(int i=0;i<6;i++){
n-=a[i][6];
}
if(n<0 || n%3){
puts("0");
return ;
}
n/=3;
int lim[3];
lim[0]=max({0,-a[0][6],-a[1][6]});
lim[1]=max({0,-a[2][6],-a[3][6]});
lim[2]=max({0,-a[4][6],-a[5][6]});
Poly f(n+1),g(n+1),h(n+1);
for(int i=lim[0];i<=n;i++)f[i]=1ll*inv[i]*inv[i+a[0][6]]%mod*inv[i+a[1][6]]%mod;
for(int i=lim[1];i<=n;i++)g[i]=1ll*inv[i]*inv[i+a[2][6]]%mod*inv[i+a[3][6]]%mod;
for(int i=lim[2];i<=n;i++)h[i]=1ll*inv[i]*inv[i+a[4][6]]%mod*inv[i+a[5][6]]%mod;
f=f*g*h;
int ans=1ll*f[n]*coef%mod;
cout<<ans<<'\n';
}
signed main(){
int tid;read(tid);
n=500000;
fac[0]=1;for(int i=1;i<=n;i++)fac[i]=1ll*fac[i-1]*i%mod;
inv[n]=qpow(fac[n],mod-2);for(int i=n-1;~i;--i)inv[i]=1ll*inv[i+1]*(i+1)%mod;
int T=1;
read(T);
while(T--)solve();
#ifdef do_while_true
// cerr<<'\n'<<"Time:"<<1.0*clock()/CLOCKS_PER_SEC*1000<<" ms"<<'\n';
#endif
return 0;
}
详细
Test #1:
score: 0
Time Limit Exceeded
input:
2 2 0 0 1 1 0 1 0 1