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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#429327 | #8130. Yet Another Balanced Coloring Problem | lmeowdn# | WA | 5ms | 17604kb | C++14 | 2.1kb | 2024-06-02 11:50:38 | 2024-06-02 11:50:38 |
Judging History
answer
//Shirasu Azusa 2024.6
#include <bits/stdc++.h>
#define fi first
#define se second
#define eb emplace_back
#define mp make_pair
using namespace std;
typedef long double ld;
typedef long long ll;
typedef unsigned long long ull;
typedef __int128 i128;
template<class T,class S>
bool chmax(T &a,const S b) {return (a<b?a=b,1:0);}
template<class T,class S>
bool chmin(T &a,const S b) {return (a>b?a=b,1:0);}
int popcnt(int x) {return __builtin_popcount(x);}
int popcnt(ll x) {return __builtin_popcountll(x);}
int topbit(int x) {return (x==0?-1:31-__builtin_clz(x));}
int topbit(ll x) {return (x==0?-1:63-__builtin_clzll(x));}
int lowbit(int x) {return (x==0?-1:__builtin_ctz(x));}
int lowbit(ll x) {return (x==0?-1:__builtin_ctzll(x));}
#define rep(i,a,b) for(int i=(a);i<=(b);i++)
#define per(i,a,b) for(int i=(a);i>=(b);i--)
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pii> vp;
typedef tuple<int,int,int> tiii;
int read() {
int x=0,w=1; char c=getchar();
while(!isdigit(c)) {if(c=='-') w=-1; c=getchar();}
while(isdigit(c)) {x=x*10+(c-'0'); c=getchar();}
return x*w;
}
const int N=3e5+5;
int n,m,k,p[N],q[N],f[N],deg[N],g[N],tot,vst[N],r[N];
vp e[N];
void dfs(int u) {
while(e[u].size()) {
auto [v,d]=e[u][e[u].size()-1]; e[u].pop_back();
if(vst[d]) continue;
vst[d]=v+N; dfs(v);
}
}
void work() {
n=read(), m=read();
rep(i,1,n) p[i]=f[i]=0;
rep(i,1,m) q[i]=g[i]=0;
rep(i,1,n) deg[i]=0;
rep(i,1,n-1) p[i]=read(), deg[p[i]]++;
int k=1; while(k<=n&°[k]==0) k++; k--;
rep(i,1,m-1) q[i]=read();
rep(i,1,k) f[i]=g[i]=1;
rep(i,1,n) f[p[i]]+=f[i];
rep(i,1,m) g[q[i]]+=g[i];
tot=1;
rep(i,1,n) if(f[i]&1) {
++tot; if(i<=k) r[i]=tot;
e[p[i]].eb(i,tot), e[i].eb(p[i],tot);
}
rep(i,1,m) if(g[i]&1) {
++tot; int x=(i<=k?i:i+m);
e[q[i]+m].eb(x,tot), e[x].eb(q[i]+m,tot);
}
rep(i,1,tot) vst[i]=0;
rep(i,0,n+m) dfs(i);
rep(i,1,k) {
if(vst[r[i]]-N==i) putchar('R');
else putchar('B');
} puts("");
}
signed main() {
int T=read(); while(T--) work();
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 17604kb
input:
2 7 7 5 5 6 6 7 7 5 6 5 6 7 7 5 4 4 4 5 5 4 4 4
output:
RBBR BRR
result:
ok ok (2 test cases)
Test #2:
score: -100
Wrong Answer
time: 5ms
memory: 16828kb
input:
10000 6 6 5 5 5 5 6 5 6 6 6 6 9 6 7 9 7 7 6 8 9 9 6 6 6 6 6 9 8 9 9 8 7 7 8 8 9 7 7 8 7 7 7 8 6 10 4 5 5 6 6 4 6 5 7 8 9 8 9 10 6 9 6 6 6 6 6 6 9 7 8 8 9 9 9 8 9 8 6 6 7 6 7 8 7 9 7 6 7 8 9 9 9 8 6 7 7 5 8 8 8 9 7 5 6 5 8 7 8 8 7 6 6 5 5 6 7 8 5 7 6 6 7 7 9 9 8 9 8 8 8 8 9 9 9 9 8 8 9 9 8 9 9 8 8 8 ...
output:
RBRB RRBBB RBBRBR RRB BRRBR RRBBR RRBB RBRB RBBRBRB BRRBRBB RBR RBRBRB BBR RBBRBRR RBRBBR RBRB RRB BBRRR BBR BBRRR RRBBR RBRB BBRRR BRB BRBRR RRBB RBBRBR RBBBRR RBRB RBBBRR RBBBRR RBBRR RBRBRB RBBRBR RBBBRR BRR RBBR BBB RBR BRBRR RRBB RRBRBB BBB RRBRB RBB RBRBRB RBRBRB RRB RBRBRB RBR BRR RRBB BRRBR ...
result:
wrong answer charge of vertex 10 in tree 1 violates range (test case 38)