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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#427564#8770. Comparatorucup-team635#AC ✓475ms97852kbRust6.4kb2024-06-01 13:52:192024-06-01 13:52:20

Judging History

你现在查看的是最新测评结果

  • [2024-06-01 13:52:20]
  • 评测
  • 测评结果:AC
  • 用时:475ms
  • 内存:97852kb
  • [2024-06-01 13:52:19]
  • 提交

answer

use std::collections::*;
use std::io::Write;

type Map<K, V> = BTreeMap<K, V>;
type Set<T> = BTreeSet<T>;
type Deque<T> = VecDeque<T>;

fn main() {
    input! {
        n: usize,
        k: usize,
        cond: [(usize1, usize1, bytes, u8); n],
        fix: u8,
    }
    let mut used = [[[[false; 2]; 2]; 10]; 10];
    let mut memo = vec![];
    for (a, b, s, r) in cond {
        let mut solver = Parser {
            s: s,
            po: 0,
        };
        let mat = solver.xor();
        for i in 0..2 {
            for j in 0..2 {
                if !used[a][b][i][j] && mat[i][j] == 1 {
                    used[a][b][i][j] = true;
                    memo.push((a, b, i, j, r));
                }
            }
        }
    }
    let eval = |x: usize, y: usize| -> u8 {
        for &(a, b, p, q, r) in memo.iter() {
            if x >> a & 1 == p && y >> b & 1 == q {
                return r;
            }
        }
        fix
    };
    let w = 8 * std::mem::size_of::<usize>();
    let len = ((1 << k) + w - 1) / 2;
    let mut func = vec![vec![0; len]; 1 << k];
    for (i, f) in func.iter_mut().enumerate() {
        for j in 0..(1 << k) {
            let q = j / w;
            let r = j % w;
            f[q] |= (eval(i, j) as usize) << r;
        }
    }
    let at = |f: &[usize], x: usize| -> bool {
        let q = x / w;
        let r = x % w;
        f[q] >> r & 1 == 1
    };
    let find = |x: usize, y: usize| -> bool {
        at(&func[x], y)
    };
    let mut rev = vec![vec![0; len]; 1 << k];
    for i in 0..(1 << k) {
        for j in 0..(1 << k) {
            let q = j / w;
            let r = j % w;
            rev[i][q] |= (find(j, i) as usize) << r;
        }
    }
    let mut ans = (0, 0, 0);
    for i in 0..(1 << k) {
        if find(i, i) {
            ans.0 += 1;
        }
        for j in 0..(1 << k) {
            if find(i, j) && find(j, i) {
                ans.1 += 1;
            }
            if !find(i, j) {
                ans.2 += func[i].iter().zip(rev[j].iter()).fold(0, |s, a| s + (*a.0 & *a.1).count_ones());
            }
        }
    }
    println!("{} {} {}", ans.0, ans.1, ans.2);
}

#[derive(Debug)]
struct Parser {
    s: Vec<u8>,
    po: usize,
}

// [x][y] = res
impl Parser {
    fn peek(&self) -> Option<u8> {
        self.s.get(self.po).cloned()
    }
    fn eat(&mut self) -> u8 {
        let c = self.peek().unwrap();
        self.po += 1;
        c
    }
    fn xor(&mut self) -> [[u8; 2]; 2] {
        let mut l = self.or();
        while self.peek().map_or(false, |c| c == b'^') {
            self.eat();
            let r = self.or();
            for (l, r) in l.iter_mut().zip(r.iter()) {
                for (l, r) in l.iter_mut().zip(r.iter()) {
                    *l ^= *r;
                }
            }
        }
        l
    }
    fn or(&mut self) -> [[u8; 2]; 2] {
        let mut l = self.and();
        while self.peek().map_or(false, |c| c == b'|') {
            self.eat();
            let r = self.and();
            for (l, r) in l.iter_mut().zip(r.iter()) {
                for (l, r) in l.iter_mut().zip(r.iter()) {
                    *l |= *r;
                }
            }
        }
        l
    }
    fn and(&mut self) -> [[u8; 2]; 2] {
        let mut l = self.eq();
        while self.peek().map_or(false, |c| c == b'&') {
            self.eat();
            let r = self.eq();
            for (l, r) in l.iter_mut().zip(r.iter()) {
                for (l, r) in l.iter_mut().zip(r.iter()) {
                    *l &= *r;
                }
            }
        }
        l
    }
    fn eq(&mut self) -> [[u8; 2]; 2] {
        let mut l = self.not();
        while self.peek().map_or(false, |c| c == b'=') {
            self.eat();
            let r = self.not();
            for (l, r) in l.iter_mut().zip(r.iter()) {
                for (l, r) in l.iter_mut().zip(r.iter()) {
                    *l = (*l == *r) as u8;
                }
            }
        }
        l
    }
    fn not(&mut self) -> [[u8; 2]; 2] {
        if self.peek().unwrap() != b'!' {
            return self.term();
        }
        let mut sign = 0;
        if self.peek().unwrap() == b'!' {
            self.eat();
            sign = 1;
        }
        let mut res = self.not();
        for a in res.iter_mut().flatten() {
            *a ^= sign;
        }
        res
    }
    fn term(&mut self) -> [[u8; 2]; 2] {
        let c = self.eat();
        if c == b'0' {
            [[0; 2]; 2]
        } else if c == b'1' {
            [[1; 2]; 2]
        } else if c == b'x' {
            [[0; 2], [1; 2]]
        } else if c == b'y' {
            [[0, 1]; 2]
        } else {
            assert!(c == b'(', "{}", c as char);
            let res = self.xor();
            let d = self.eat();
            assert!(d == b')', "{}", d as char);
            res
        }
    }
}

// ---------- begin input macro ----------
// reference: https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
#[macro_export]
macro_rules! input {
    (source = $s:expr, $($r:tt)*) => {
        let mut iter = $s.split_whitespace();
        input_inner!{iter, $($r)*}
    };
    ($($r:tt)*) => {
        let s = {
            use std::io::Read;
            let mut s = String::new();
            std::io::stdin().read_to_string(&mut s).unwrap();
            s
        };
        let mut iter = s.split_whitespace();
        input_inner!{iter, $($r)*}
    };
}

#[macro_export]
macro_rules! input_inner {
    ($iter:expr) => {};
    ($iter:expr, ) => {};
    ($iter:expr, $var:ident : $t:tt $($r:tt)*) => {
        let $var = read_value!($iter, $t);
        input_inner!{$iter $($r)*}
    };
}

#[macro_export]
macro_rules! read_value {
    ($iter:expr, ( $($t:tt),* )) => {
        ( $(read_value!($iter, $t)),* )
    };
    ($iter:expr, [ $t:tt ; $len:expr ]) => {
        (0..$len).map(|_| read_value!($iter, $t)).collect::<Vec<_>>()
    };
    ($iter:expr, chars) => {
        read_value!($iter, String).chars().collect::<Vec<char>>()
    };
    ($iter:expr, bytes) => {
        read_value!($iter, String).bytes().collect::<Vec<u8>>()
    };
    ($iter:expr, usize1) => {
        read_value!($iter, usize) - 1
    };
    ($iter:expr, $t:ty) => {
        $iter.next().unwrap().parse::<$t>().expect("Parse error")
    };
}
// ---------- end input macro ----------

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 2216kb

input:

3 2
1 1 (x=0)&(y=1) 1
1 1 (x=1)&(y=(x^x)) 0
2 2 (x=1)|(y=0) 0
1

output:

0 0 0

result:

ok single line: '0 0 0'

Test #2:

score: 0
Accepted
time: 0ms
memory: 2096kb

input:

4 3
2 1 x=0&(y=1) 1
1 2 !x^!!y 0
2 3 ((x|1)=y)&1&1 1
3 1 !x&!x&!x 0
1

output:

3 25 52

result:

ok single line: '3 25 52'

Test #3:

score: 0
Accepted
time: 16ms
memory: 3852kb

input:

1413 3
1 3 0 0
3 3 !x 0
2 2 x=0 1
1 2 !y^0 1
2 3 (x^1) 0
3 2 ((!0)) 1
1 1 !!1=(y) 0
2 2 !(1^x)&y 1
3 2 (y)&1|!!1 0
3 1 !x=(y&y=y) 0
2 1 (((!1)^!x)) 1
2 3 !0=(0&y)=1&y 0
1 2 ((((!0)))|!1) 0
3 1 !(y=!1=x|(!x)) 0
1 1 ((((y=!y)))&!0) 0
2 3 ((y=1)^!1^!!1|0) 1
2 3 1|(!x)&!x|1|(x=1) 1
2 3 !0^!!!!y&0=(!1&!0...

output:

4 16 0

result:

ok single line: '4 16 0'

Test #4:

score: 0
Accepted
time: 35ms
memory: 18460kb

input:

181737 10
5 2 1 1
1 10 !1=!x 0
10 1 (1^x) 0
2 4 !1 1
10 8 y=(!1)^1 1
6 2 !((x&!x)) 1
1 10 !!((!x)|x) 1
7 10 (((0))) 0
7 3 !(1)^!x 0
10 4 (!1)&x 0
7 7 !y&!0 1
8 8 !1=(x)|1^1 1
2 6 ((!!!x)) 0
7 2 1 1
2 2 y=1=0 0
6 3 (!0) 0
6 4 0 0
1 1 (!1) 1
1 8 y 1
3 5 !x|!x^!1 0
4 7 (!0) 0
3 4 !1&1&!1|!0 1
2 7 ((0|1...

output:

1024 1048576 0

result:

ok single line: '1024 1048576 0'

Test #5:

score: 0
Accepted
time: 19ms
memory: 97852kb

input:

1 3
1 1 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!...

output:

4 16 0

result:

ok single line: '4 16 0'

Test #6:

score: 0
Accepted
time: 0ms
memory: 2252kb

input:

1 1
1 1 x^y|1 0
1

output:

1 1 0

result:

ok single line: '1 1 0'

Test #7:

score: 0
Accepted
time: 0ms
memory: 2060kb

input:

1 1
1 1 x&y|1 0
1

output:

0 0 0

result:

ok single line: '0 0 0'

Test #8:

score: 0
Accepted
time: 0ms
memory: 2120kb

input:

1 1
1 1 x=y|1 0
1

output:

0 0 0

result:

ok single line: '0 0 0'

Test #9:

score: 0
Accepted
time: 0ms
memory: 2132kb

input:

2 2
1 2 !x&!y 1
1 1 !x&y 0
1

output:

4 12 2

result:

ok single line: '4 12 2'

Test #10:

score: 0
Accepted
time: 475ms
memory: 10784kb

input:

2 10
9 8 ((((!((!x=1))^(!1&(x|x|!y))&((!y&!x=(x=y)))&!((((x=1))&(0=(y))^(!!(!!x^1=x)&(x)^y&1=!x&1=(((!0^(1)^1))^!(((((y))|x|!y))))^!!0=!y&(0)|(y=x&!y&y=x)))=((((!!y&!!0|!0^!0)=!x))))^0&(((!1=!(!x)))|(((((x=1|!y|y)=(!1^1^0^(0)))=!0^1)))=(!(!1^(((((!1)^!x^0))))=(1)^((((y=((x))|(0)|(!1^1)))|(!!!y))=((!...

output:

0 0 0

result:

ok single line: '0 0 0'

Test #11:

score: 0
Accepted
time: 0ms
memory: 2224kb

input:

4 3
1 1 !!!!!!x 0
2 1 !!y 1
1 2 !!!!!x 1
2 2 !!!x 0
1

output:

4 16 0

result:

ok single line: '4 16 0'

Test #12:

score: 0
Accepted
time: 11ms
memory: 30336kb

input:

1 1
1 1 ((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((...

output:

1 1 0

result:

ok single line: '1 1 0'

Test #13:

score: 0
Accepted
time: 273ms
memory: 20116kb

input:

200000 10
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10 !x^!y 1
3 10...

output:

512 262144 134217728

result:

ok single line: '512 262144 134217728'

Test #14:

score: 0
Accepted
time: 0ms
memory: 2328kb

input:

10 3
3 1 (!x) 1
3 2 !1&x&1&!y 1
2 1 ((x)&y) 1
1 3 0 0
2 2 !1&0=y&0 1
3 3 (!y)^y 1
2 1 0|((!y)) 0
3 2 x 0
2 2 (y|1^x) 0
2 1 ((!0)|y) 0
1

output:

8 64 0

result:

ok single line: '8 64 0'

Test #15:

score: 0
Accepted
time: 0ms
memory: 2152kb

input:

0 3
1

output:

8 64 0

result:

ok single line: '8 64 0'