#include <bits/stdc++.h>


using namespace std;


#define ll long long
#define flt double
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()


const ll inf = 1e18;
mt19937 rnd(234);
const ll mod = 1e9 + 7;
typedef complex<flt> base;
const flt pi = atan2(1, 0) * 2;

int32_t main() {
    if (1) {
        ios::sync_with_stdio(0);
        cin.tie(0);
        cout.tie(0);
    }
    int n;
    cin >> n;
    string s;
    cin >> s;
    map<char, pair<int, int>> go = {
        make_pair('U', make_pair(0, 1)),
        make_pair('D', make_pair(0, -1)),
        make_pair('L', make_pair(-1, 0)),
        make_pair('R', make_pair(1, 0)),
    };
    vector<int> dx(n), dy(n);
    for (int i = 0; i < n; i += 1) {
        dx[i] = go[s[i]].first;
        dy[i] = go[s[i]].second;
    }
    set<pair<int, int>> st;
    int usdc = 0;
    vector<vector<int>> usd(2 * n + 1, vector<int>(2 * n + 1, 0));
    vector<vector<int>> tp(2 * n + 1, vector<int>(2 * n + 1, 0));
    for (int mask = 0; mask < (1 << n); mask += 1) {
        int x = 0;
        int y = 0;
        ++usdc;
        usd[n + x][n + y] = usdc;
        tp[n + x][n + y] = 0;
        bool ok = true;
        for (int i = 0; i < n; i += 1) {
            int nx = x + dx[i];
            int ny = y + dy[i];
            if ((mask >> i) & 1) {
                if (usd[n + nx][n + ny] == usdc and tp[n + nx][n + ny] != 1) {
                    ok = false;
                    break;
                }
                usd[n + nx][n + ny] = usdc;
                tp[n + nx][n + ny] = 1;
            } else {
                if (usd[n + nx][n + ny] == usdc and tp[n + nx][n + ny] != 0) {
                    ok = false;
                    break;
                }
                usd[n + nx][n + ny] = usdc;
                tp[n + nx][n + ny] = 0;
                x = nx;
                y = ny;
            }
        }
        if (ok) {
            st.insert(make_pair(x, y));
        }
    }
    cout << (int)st.size() << "\n";
    for (auto [x, y] : st) {
        cout << x << " " << y << "\n";
    }
    return 0;
}