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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#420610 | #8718. 保区间最小值一次回归问题 | Scintilla# | WA | 395ms | 33356kb | C++20 | 3.0kb | 2024-05-24 20:37:43 | 2024-05-24 20:37:44 |
Judging History
answer
#include <map>
#include <set>
#include <cmath>
#include <queue>
#include <bitset>
#include <vector>
#include <random>
#include <cassert>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <functional>
#include <unordered_map>
using namespace std;
#define rep(i, s, e) for (int i = s; i <= e; ++i)
#define per(i, s, e) for (int i = s; i >= e; --i)
#define file(a) freopen(#a".in", "r", stdin), freopen(#a".out", "w", stdout)
#define pv(a) cout << #a << " = " << a << endl
#define pa(a, l, r) cout << #a " : "; rep(_, l, r) cout << a[_] << " \n"[_ == r]
using i64 = long long;
const i64 inf = 1e18;
const int N = 5e5 + 10;
int read() {
int x = 0, f = 1; char c = getchar();
for (; c < '0' || c > '9'; c = getchar()) if (c == '-') f = -1;
for (; c >= '0' && c <= '9'; c = getchar()) x = x * 10 + (c - 48);
return x * f;
}
int n, m, a[N], bd[N], mx[N];
i64 f[N], pre[N], ans;
struct node {
int l, r, k;
node() {}
friend bool operator < (node u, node v) {
return u.k < v.k;
}
} o[N];
map <int, vector <int>> pos;
map <int, vector <node>> lim;
int fa[N];
int get(int u) { return u == fa[u] ? u : fa[u] = get(fa[u]); }
void merge(int u, int v) { fa[get(v)] = get(u); }
void solve() {
n = read(), m = read(), ans = 0;
pos.clear(), lim.clear();
rep(i, 1, n) a[i] = read();
rep(i, 1, m) {
o[i].l = read(), o[i].r = read(), o[i].k = read();
lim[o[i].k].emplace_back(o[i]);
}
sort(o + 1, o + m + 1);
rep(i, 1, n) fa[i] = i, bd[i] = -1;
per(i, m, 1) {
for (int p = o[i].r; (p = get(p)) >= o[i].l; merge(p - 1, p)) bd[p] = o[i].k;
}
rep(i, 1, n) if (~bd[i]) pos[bd[i]].emplace_back(i);
// pa(bd, 1, n);
for (auto [k, vec] : lim) {
if (pos[k].empty()) {
printf("-1\n");
return;
}
}
for (auto [k, vec] : pos) {
// cout << "--- k = " << k << endl;
int w = vec.size();
// pv(w);
// pa(vec, 0, w - 1);
rep(i, 1, w) {
mx[i] = 0, f[i] = inf;
pre[i] = pre[i - 1] + max(0, k - a[vec[i - 1]]);
}
for (auto it : lim[k]) {
int l = lower_bound(vec.begin(), vec.end(), it.l) - vec.begin() + 1;
int r = lower_bound(vec.begin(), vec.end(), it.r) - vec.begin() + 1;
if (l > r) {
printf("-1\n");
return;
}
// cout << "l, r = " << l << ' ' << r << endl;
mx[r] = max(mx[r], l);
}
deque <int> q;
q.push_back(0);
rep(i, 1, w) {
mx[i] = max(mx[i], mx[i - 1]);
f[i] = f[i - 1];
while (q.size() && q.front() < mx[i]) q.pop_front();
if (q.size()) f[i] = min(f[i], f[q.front()] + pre[i - 1] - pre[q.front()]);
f[i] += abs(k - a[vec[i - 1]]);
while (q.size() && f[q.back()] >= f[i]) q.pop_back();
q.push_back(i);
}
// pa(mx, 1, w);
// pa(f, 1, w);
// pa(g, 1, w);
i64 res = inf;
rep(i, mx[w], w) res = min(res, f[i]);
ans += res;
}
printf("%lld\n", ans);
}
int main() {
for (int tc = read(); tc; --tc) solve();
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 16036kb
input:
1 3 2 2023 40 41 1 1 2022 2 3 39
output:
2
result:
ok 1 number(s): "2"
Test #2:
score: -100
Wrong Answer
time: 395ms
memory: 33356kb
input:
1000 100 100 1 35141686 84105222 84105220 7273527 178494861 178494861 112519027 77833654 77833656 261586535 278472336 278472336 261586536 416361017 416361017 426649080 323519513 278472337 420127821 420127823 420127823 482516531 434108818 420127821 631535744 615930922 546346921 546346920 546346920 70...
output:
41 37 47 39 48 49 53 43 44 49 47 52 932 50 48 51 44 51 53 44 47 40 38 48 50 47 42 39 38 38 37 49 55 44 51 39 45 44 34 45 44 53 37 50 963 890 49 43 51 43 39 41 52 48 40 46 47 48 48 46 34 43 46 40 47 38 48 50 40 47 50 42 38 45 48 51 46 47 43 37 41 40 40 43 43 46 48 43 38 46 45 40 49 52 41 38 40 51 50 ...
result:
wrong answer 1st numbers differ - expected: '49', found: '41'