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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#420586 | #8718. 保区间最小值一次回归问题 | Scintilla# | WA | 384ms | 37396kb | C++20 | 2.8kb | 2024-05-24 20:28:01 | 2024-05-24 20:28:01 |
Judging History
answer
#include <map>
#include <set>
#include <cmath>
#include <queue>
#include <bitset>
#include <vector>
#include <random>
#include <cassert>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <functional>
#include <unordered_map>
using namespace std;
#define rep(i, s, e) for (int i = s; i <= e; ++i)
#define per(i, s, e) for (int i = s; i >= e; --i)
#define file(a) freopen(#a".in", "r", stdin), freopen(#a".out", "w", stdout)
#define pv(a) cout << #a << " = " << a << endl
#define pa(a, l, r) cout << #a " : "; rep(_, l, r) cout << a[_] << " \n"[_ == r]
using i64 = long long;
const i64 inf = 1e18;
const int N = 5e5 + 10;
int read() {
int x = 0, f = 1; char c = getchar();
for (; c < '0' || c > '9'; c = getchar()) if (c == '-') f = -1;
for (; c >= '0' && c <= '9'; c = getchar()) x = x * 10 + (c - 48);
return x * f;
}
int n, m, a[N], bd[N], mx[N];
i64 f[N], pre[N], ans;
struct node {
int l, r, k;
node() {}
friend bool operator < (node u, node v) {
return u.k < v.k;
}
} o[N];
map <int, vector <int>> pos;
map <int, vector <node>> lim;
int fa[N];
int get(int u) { return u == fa[u] ? u : fa[u] = get(fa[u]); }
void merge(int u, int v) { fa[get(v)] = get(u); }
void solve() {
n = read(), m = read(), ans = 0;
pos.clear(), lim.clear();
rep(i, 1, n) a[i] = read();
rep(i, 1, m) {
o[i].l = read(), o[i].r = read(), o[i].k = read();
lim[o[i].k].emplace_back(o[i]);
}
sort(o + 1, o + m + 1);
rep(i, 1, n) fa[i] = i, bd[i] = -1;
per(i, m, 1) {
for (int p = o[i].r; (p = get(p)) >= o[i].l; merge(p - 1, p)) bd[p] = o[i].k;
}
rep(i, 1, n) if (~bd[i]) pos[bd[i]].emplace_back(i);
// pa(bd, 1, n);
for (auto [k, vec] : lim) {
if (pos[k].empty()) {
printf("-1\n");
return;
}
}
for (auto [k, vec] : pos) {
// cout << "--- k = " << k << endl;
int w = vec.size();
// pv(w);
// pa(vec, 0, w - 1);
rep(i, 1, w) mx[i] = 0, f[i] = pre[i] = inf;
for (auto it : lim[k]) {
int l = lower_bound(vec.begin(), vec.end(), it.l) - vec.begin() + 1;
int r = lower_bound(vec.begin(), vec.end(), it.r) - vec.begin() + 1;
if (l > r) {
printf("-1\n");
return;
}
// cout << "l, r = " << l << ' ' << r << endl;
mx[r] = max(mx[r], l);
}
deque <int> q;
rep(i, 1, w) {
mx[i] = max(mx[i], mx[i - 1]);
f[i] = f[i - 1] + abs(k - a[vec[i - 1]]);
while (q.size() && q.front() < mx[i]) q.pop_front();
if (q.size()) f[i] = min(f[i], f[q.front()] + max(0, k - a[vec[i - 1]]));
while (q.size() && f[q.back()] >= f[i]) q.pop_back();
q.push_back(i);
}
// pa(f, 1, w);
ans += f[w];
}
printf("%lld\n", ans);
}
int main() {
for (int tc = read(); tc; --tc) solve();
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 16416kb
input:
1 3 2 2023 40 41 1 1 2022 2 3 39
output:
2
result:
ok 1 number(s): "2"
Test #2:
score: -100
Wrong Answer
time: 384ms
memory: 37396kb
input:
1000 100 100 1 35141686 84105222 84105220 7273527 178494861 178494861 112519027 77833654 77833656 261586535 278472336 278472336 261586536 416361017 416361017 426649080 323519513 278472337 420127821 420127823 420127823 482516531 434108818 420127821 631535744 615930922 546346921 546346920 546346920 70...
output:
47 36 33 35 35 33 32 45 36 44 33 52 620 48 35 49 48 55 35 32 36 45 36 52 39 52 40 36 37 32 26 50 46 42 53 36 33 31 29 41 30 36 33 38 585 602 29 39 34 47 43 38 41 47 23 38 52 50 51 37 36 42 28 27 49 34 45 31 25 42 46 35 41 38 31 33 27 33 29 31 34 24 40 38 38 44 30 35 26 34 39 33 35 39 46 30 37 33 34 ...
result:
wrong answer 1st numbers differ - expected: '49', found: '47'