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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#420103 | #2817. 鸽鸽的分割 | 300_205_205# | AC ✓ | 1ms | 3840kb | C++14 | 2.2kb | 2024-05-24 14:40:12 | 2024-05-24 14:40:12 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#define rg register
#define ll long long
#define ull unsigned ll
#define lowbit(x) (x&(-x))
#define djq 998244353
const double eps=1e-10;
const short sint=0x3f3f;
const int inf=0x3f3f3f3f;
const ll linf=0x3f3f3f3f3f3f3f3f;
const double alpha=0.73;
const double PI=acos(-1);
inline void file(){
freopen("entrench.in","r",stdin);
freopen("entrench.out","w",stdout);
}
inline ll read(){
rg ll ret=0,f=0;char ch=getchar();
while(!isdigit(ch)){if(ch==EOF)exit(0);if(ch=='-')f=1;ch=getchar();}
while(isdigit(ch)){ret=ret*10+ch-48;ch=getchar();}
return f?-ret:ret;
}
#define ep emplace
#define epb emplace_back
#define all(x) (x).begin(),(x).end()
#define fi first
#define se second
#define it iterator
#define mkp make_pair
#define naive return 0*puts("Yes")
#define angry return 0*puts("No")
#define fls fflush(stdout)
#define rep(i,x,y) for(rg int i=(x);i<=(y);++i)
#define per(i,x,y) for(rg int i=(x);i>=(y);--i)
#define rep0(i,a) for(rg int i=0;i<=a;++i)
#define per0(i,a) for(rg int i=a;~i;--i)
#define szf sizeof
typedef vector<int> vec;
typedef pair<int,int> pii;
struct point{ int x,y; point(int x=0,int y=0):x(x),y(y) {} inline bool operator<(const point& T)const{ return x^T.x?x<T.x:y<T.y; }; };
inline int ksm(int base,int p){int ret=1;while(p){if(p&1)ret=1ll*ret*base%djq;base=1ll*base*base%djq,p>>=1;}return ret;}
inline void pls(int& x,const int k){ x=(x+k>=djq?x+k-djq:x+k); }
inline int add(const int a,const int b){ return a+b>=djq?a+b-djq:a+b; }
inline void sub(int& x,const int k){ x=(x-k<0?x-k+djq:x-k); }
inline int inc(const int a,const int b){ return a<b?a-b+djq:a-b; }
inline void ckmn(int& x,const int k){ x=(k<x?k:x); }
inline void ckmx(int& x,const int k){ x=(k>x?k:x); }
inline void ckmn(ll& x,const ll k){ x=(k<x?k:x); }
inline void ckmx(ll& x,const ll k){ x=(k>x?k:x); }
mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());
int n;
ull f[105];
signed main(){
// file();
f[0]=1,f[1]=1,f[2]=2;
rep(i,3,64){
f[i]=f[i-1];
rep(j,1,i-1){
f[i]+=(j-1)*(i-1-j)+1;
}
}
while(1){
n=read();
printf("%llu\n",f[n]);
}
return 0;
}
/*
*/
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 3840kb
input:
0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 61 62 63 64
output:
1 1 2 4 8 16 31 57 99 163 256 5036 27841 92171 231526 489406 523686 559737 597619 637393
result:
ok 20 lines