QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#418917#8339. Rooted TreeyouthpaulTL 322ms3740kbC++203.6kb2024-05-23 16:26:372024-05-23 16:26:37

Judging History

你现在查看的是最新测评结果

  • [2024-05-23 16:26:37]
  • 评测
  • 测评结果:TL
  • 用时:322ms
  • 内存:3740kb
  • [2024-05-23 16:26:37]
  • 提交

answer

#include<bits/stdc++.h>
#define fore(i,l,r)	for(int i=(int)(l);i<(int)(r);++i)
#define fi first
#define se second
#define endl '\n'
#define ull unsigned long long
#define ALL(v) v.begin(), v.end()
#define Debug(x, ed) std::cerr << #x << " = " << x << ed;

const int INF=0x3f3f3f3f;
const long long INFLL=1e18;

// typedef long long ll;

using ll = int;

template<class T>
constexpr T power(T a, ll b){
    T res = 1;
    while(b){
        if(b&1) res = res * a;
        a = a * a;
        b >>= 1;
    }
    return res;
}

constexpr ll mul(ll a,ll b,ll mod){ //快速乘,避免两个long long相乘取模溢出
    ll res = a * b - ll(1.L * a * b / mod) * mod;
    res %= mod;
    if(res < 0) res += mod; //误差
    return res;
}

template<ll P>
struct MLL{
    ll x;
    constexpr MLL() = default;
    constexpr MLL(ll x) : x(norm(x % getMod())) {}

    static ll Mod;
    constexpr static ll getMod(){
       if(P > 0) return P;
       return Mod;
    }

    constexpr static void setMod(int _Mod){
       Mod = _Mod;
    }
    constexpr ll norm(ll x) const{
       if(x < 0){
           x += getMod();
       }
       if(x >= getMod()){
           x -= getMod();
       }
       return x;
    }
    constexpr ll val() const{
       return x;
    }
    explicit constexpr operator ll() const{ 
       return x; //将结构体显示转换为ll类型: ll res = static_cast<ll>(OBJ)
    }
    constexpr MLL operator -() const{ //负号,等价于加上Mod
       MLL res;
       res.x = norm(getMod() - x);
       return res;
    }
    constexpr MLL inv() const{
       assert(x != 0);
       return power(*this, getMod() - 2); //用费马小定理求逆
    }
    constexpr MLL& operator *= (MLL rhs) & { //& 表示“this”指针不能指向一个临时对象或const对象
       x = mul(x, rhs.x, getMod()); //该函数只能被一个左值调用
       return *this;
    }
    constexpr MLL& operator += (MLL rhs) & {
       x = norm(x + rhs.x);
       return *this;
    }
    constexpr MLL& operator -= (MLL rhs) & {
       x = norm(x - rhs.x);
       return *this;
    }
    constexpr MLL& operator /= (MLL rhs) & {
       return *this *= rhs.inv();
    }
    friend constexpr MLL operator * (MLL lhs, MLL rhs){
       MLL res = lhs;
       res *= rhs;
       return res;
    }
    friend constexpr MLL operator + (MLL lhs, MLL rhs){
       MLL res = lhs;
       res += rhs;
       return res;
    }
    friend constexpr MLL operator - (MLL lhs, MLL rhs){
       MLL res = lhs;
       res -= rhs;
       return res;
    }
    friend constexpr MLL operator / (MLL lhs, MLL rhs){
       MLL res = lhs;
       res /= rhs;
       return res;
    }
    friend constexpr std::istream& operator >> (std::istream& is, MLL& a){
       ll v;
       is >> v;
       a = MLL(v);
       return is;
    }
    friend constexpr std::ostream& operator << (std::ostream& os, MLL& a){
       return os << a.val();
    }
    friend constexpr bool operator == (MLL lhs, MLL rhs){
       return lhs.val() == rhs.val();
    }
    friend constexpr bool operator != (MLL lhs, MLL rhs){
       return lhs.val() != rhs.val();
    }
};

const ll mod = 1e9 + 9;
using Z = MLL<mod>;

int main(){
    std::ios::sync_with_stdio(false);
    std::cin.tie(nullptr);
    std::cout.tie(nullptr);
    int m, k;
    std::cin >> m >> k;
    Z ans = 0;
    Z A = 0;
    fore(i, 0, k){
        Z inv = 1 / Z((m - 1) * i + 1);
        ans += A * inv + 1;
        A = A * ((m - 1) * (i + 1) + 1) * inv + m;
    }

    ans *= m;

    std::cout << ans << endl;
    
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3608kb

input:

6 2

output:

18

result:

ok 1 number(s): "18"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3656kb

input:

2 6

output:

600000038

result:

ok 1 number(s): "600000038"

Test #3:

score: 0
Accepted
time: 322ms
memory: 3740kb

input:

83 613210

output:

424200026

result:

ok 1 number(s): "424200026"

Test #4:

score: -100
Time Limit Exceeded

input:

48 6713156

output:


result: