QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#418665 | #8718. 保区间最小值一次回归问题 | wsyear | WA | 873ms | 122084kb | C++17 | 2.8kb | 2024-05-23 15:03:37 | 2024-05-23 15:05:21 |
Judging History
answer
#include <bits/stdc++.h>
#define rep(i, j, k) for (int i = (j); i <= (k); ++i)
#define per(i, j, k) for (int i = (j); i >= (k); --i)
#define SZ(v) int((v).size())
#define ALL(v) (v).begin(),(v).end()
#define fi first
#define se second
using ll = long long;
using pii = std::pair<int, int>;
using pll = std::pair<ll, ll>;
template<class T>inline void chkmn(T &x, T y) { if (y < x) x = y; }
template<class T>inline void chkmx(T &x, T y) { if (y > x) x = y; }
using namespace std;
const int maxn = 500010;
const int inf = 2e9;
int n, m, tot, a[maxn], mx[maxn], st[maxn][20], c[maxn], tlim[maxn], val[maxn];
ll dp[maxn];
vector<int> mvec[maxn], pos[maxn];
vector<pii> vec[maxn];
tuple<int, int, int> lim[maxn];
multiset<int> S;
int que(int l, int r) {
int k = __lg(r - l + 1);
return min(st[l][k], st[r - (1 << k) + 1][k]);
}
void work() {
cin >> n >> m;
rep (i, 1, n) cin >> a[i];
rep (i, 1, n) mvec[i].clear();
rep (i, 1, m) {
int l, r, v;
cin >> l >> r >> v, c[i] = v;
mvec[l].emplace_back(v);
mvec[r + 1].emplace_back(-v);
lim[i] = make_tuple(l, r, v);
}
S.clear();
rep (i, 1, n) {
for (int x : mvec[i]) {
if (x > 0) S.emplace(x);
else S.erase(S.find(-x));
}
if (S.empty()) mx[i] = st[i][0] = inf;
else mx[i] = st[i][0] = *prev(S.end());
}
rep (j, 1, 19) rep (i, 1, n - (1 << j) + 1) {
st[i][j] = min(st[i][j - 1], st[i + (1 << (j - 1))][j - 1]);
}
rep (i, 1, m) {
auto [l, r, v] = lim[i];
if (que(l, r) != v) return cout << "-1\n", void();
}
sort(c + 1, c + m + 1), tot = unique(c + 1, c + m + 1) - c - 1;
rep (i, 1, tot) vec[i].clear(), pos[i].clear();
ll ans = 0;
rep (i, 1, n) if (mx[i] != inf) {
if (a[i] < mx[i]) ans += mx[i] - a[i], a[i] = mx[i];
int w = lower_bound(c + 1, c + tot + 1, mx[i]) - c;
pos[w].emplace_back(i);
}
rep (i, 1, m) {
auto [l, r, v] = lim[i];
v = lower_bound(c + 1, c + tot + 1, v) - c;
vec[v].emplace_back(l, r);
}
rep (i, 1, tot) if (SZ(vec[i])) {
int w = SZ(pos[i]);
rep (j, 1, w) val[j] = a[pos[i][j - 1]] - c[i];
val[w + 1] = 0;
rep (j, 1, w + 1) tlim[i] = 0;
for (auto &[l, r] : vec[i]) {
l = lower_bound(ALL(pos[i]), l) - pos[i].begin() + 1;
r = upper_bound(ALL(pos[i]), r) - pos[i].begin();
chkmx(tlim[r + 1], l);
}
rep (j, 1, w + 1) chkmx(tlim[j], tlim[j - 1]);
rep (j, 1, w + 1) dp[i] = 1e18;
multiset<ll> S;
int pos = 0;
S.emplace(0);
rep (j, 1, w + 1) {
while (pos < tlim[j]) {
S.erase(S.find(dp[pos]));
pos++;
}
dp[j] = *S.begin() + val[j];
S.emplace(dp[j]);
}
ans += dp[w + 1];
}
cout << ans << '\n';
}
int main() {
cin.tie(nullptr) -> ios::sync_with_stdio(false);
int t; cin >> t;
while (t--) work();
}
詳細信息
Test #1:
score: 100
Accepted
time: 4ms
memory: 52660kb
input:
1 3 2 2023 40 41 1 1 2022 2 3 39
output:
2
result:
ok 1 number(s): "2"
Test #2:
score: -100
Wrong Answer
time: 873ms
memory: 122084kb
input:
1000 100 100 1 35141686 84105222 84105220 7273527 178494861 178494861 112519027 77833654 77833656 261586535 278472336 278472336 261586536 416361017 416361017 426649080 323519513 278472337 420127821 420127823 420127823 482516531 434108818 420127821 631535744 615930922 546346921 546346920 546346920 70...
output:
59 55 46 56 56 50 56 55 53 58 55 63 1077 63 56 64 55 71 57 48 53 61 49 62 54 64 55 47 50 50 46 59 62 56 66 52 50 46 47 56 50 54 50 54 957 1080 57 60 54 59 56 50 61 58 46 51 64 62 64 55 43 56 48 46 61 47 57 51 42 60 66 54 51 49 51 54 45 53 47 52 50 42 54 51 56 52 53 51 45 50 56 47 52 59 50 48 49 52 5...
result:
wrong answer 1st numbers differ - expected: '49', found: '59'