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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#417750#1869. Power Station of ArtKevin5307AC ✓971ms47444kbC++232.5kb2024-05-22 21:38:112024-05-22 21:38:11

Judging History

你现在查看的是最新测评结果

  • [2024-05-22 21:38:11]
  • 评测
  • 测评结果:AC
  • 用时:971ms
  • 内存:47444kb
  • [2024-05-22 21:38:11]
  • 提交

answer

//Author: Kevin
#include<bits/stdc++.h>
//#pragma GCC optimize("O2")
using namespace std;
#define ll long long
#define ull unsigned ll
#define pb emplace_back
#define mp make_pair
#define ALL(x) (x).begin(),(x).end()
#define rALL(x) (x).rbegin(),(x).rend()
#define srt(x) sort(ALL(x))
#define rev(x) reverse(ALL(x))
#define rsrt(x) sort(rALL(x))
#define sz(x) (int)(x.size())
#define inf 0x3f3f3f3f
#define pii pair<int,int>
#define lb(v,x) (int)(lower_bound(ALL(v),x)-v.begin())
#define ub(v,x) (int)(upper_bound(ALL(v),x)-v.begin())
#define uni(v) v.resize(unique(ALL(v))-v.begin())
#define longer __int128_t
void die(string S){puts(S.c_str());exit(0);}
vector<int> G[1001000];
int n,m,vis[1001000],color[1001000];
string color1,color2;
int number1[1001000],number2[1001000];
bool bipar;
map<int,int> Cnt[2][3][2];
set<int> st;
void dfs(int u,int c=1)
{
	st.insert(number1[u]);
	vis[u]=1;
	Cnt[0][color[u]][color1[u-1]=='B'][number1[u]]++;
	Cnt[1][color[u]][color2[u-1]=='B'][number2[u]]++;
	color[u]=c;
	Cnt[0][color[u]][color1[u-1]=='B'][number1[u]]++;
	Cnt[1][color[u]][color2[u-1]=='B'][number2[u]]++;
	for(auto v:G[u])
		if(!vis[v])
			dfs(v,3-c);
		else if(color[v]==c) bipar=false;
}
int main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	int t;
	cin>>t;
	while(t--)
	{
		cin>>n>>m;
		for(int i=1;i<=n;i++)
		{
			vis[i]=color[i]=0;
			G[i].clear();
		}
		for(int i=1;i<=m;i++)
		{
			int u,v;
			cin>>u>>v;
			G[u].pb(v);
			G[v].pb(u);
		}
		for(int i=1;i<=n;i++)
			cin>>number1[i];
		cin>>color1;
		for(int i=1;i<=n;i++)
			cin>>number2[i];
		cin>>color2;
		bool ok=true;
		for(int i=1;i<=n;i++)
			if(!vis[i])
			{
				st.clear();
				bipar=true;
				for(int a=0;a<2;a++)
					for(int b=0;b<3;b++)
						for(int c=0;c<2;c++)
							Cnt[a][b][c].clear();
				dfs(i);
				if(bipar)
				{
					for(auto x:st)
					{
						if(Cnt[0][0][0][x]+Cnt[0][0][1][x]!=Cnt[1][0][0][x]+Cnt[1][0][1][x])
							ok=false;
						if(Cnt[0][1][0][x]+Cnt[0][2][1][x]!=Cnt[1][1][0][x]+Cnt[1][2][1][x])
							ok=false;
						if(Cnt[0][1][1][x]+Cnt[0][2][0][x]!=Cnt[1][1][1][x]+Cnt[1][2][0][x])
							ok=false;
					}
				}
				else
				{
					int ch=0;
					for(auto x:st)
					{
						if(Cnt[0][0][0][x]+Cnt[0][0][1][x]!=Cnt[1][0][0][x]+Cnt[1][0][1][x])
							ok=false;
						if((Cnt[0][0][0][x]-Cnt[1][0][0][x])%2)
							ch^=1;
					}
					if(ch)
						ok=false;
				}
			}
		if(ok)
			cout<<"YES\n";
		else
			cout<<"NO\n";
	}
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 3ms
memory: 11728kb

input:

3
2 1
1 2
3 4
RR
4 3
BB
3 2
1 2
2 3
1 1 1
RBR
1 1 1
BBB
3 3
1 2
2 3
3 1
1 1 1
RBR
1 1 1
BBB

output:

YES
NO
YES

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 971ms
memory: 47444kb

input:

25054
5 10
4 5
4 2
4 3
4 1
5 2
5 3
5 1
2 3
2 1
3 1
12 2 9 10 7
RRRBB
10 2 9 7 12
RRBRB
1 0
4
R
4
R
8 4
4 3
1 5
8 5
6 5
7 2 11 10 9 6 3 5
RBRBBRBR
7 2 10 11 6 5 3 9
RBRBBRBR
7 4
7 2
5 1
5 6
5 4
12 5 9 14 5 12 12
RRBRBRR
14 12 9 5 12 12 5
RBBRBRB
10 1
4 6
5 3 2 9 7 3 11 11 6 8
RRRBRRBBBR
5 3 2 3 7 9 1...

output:

YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
NO
YES
NO
NO
YES
YES
YES
NO
YES
NO
YES
YES
NO
YES
YES
NO
YES
NO
YES
YES
YES
YES
NO
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
NO
YES
NO
YES
YES
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
YES
YES
NO
YES
NO
NO...

result:

ok 25054 lines