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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#414955 | #4234. Tic Tac Toe Counting | ivan_len# | WA | 19ms | 3904kb | C++20 | 2.9kb | 2024-05-20 05:28:12 | 2024-05-20 05:28:14 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
#define PB push_back
#define MP make_pair
#define A first
#define B second
#define SZ(x) int(x.size())
#define FR(i, a, b) for (int i = (a); i < (b); ++i)
#define FOR(i, n) FR(i, 0, n)
const int M = 1000000007;
mt19937_64 rnd(chrono::steady_clock::now().time_since_epoch().count());
int n;
int State(vector<vector<int>>& s) {
int win = 0;
FOR(i, 3) {
if (s[i][0] == s[i][1] && s[i][0] == s[i][2]) {
if (s[i][0] == 1) win |= 1;
if (s[i][0] == 2) win |= 2;
}
if (s[0][i] == s[1][i] && s[0][i] == s[2][i]) {
if (s[0][i] == 1) win |= 1;
if (s[0][i] == 2) win |= 2;
}
}
if (s[0][0] == s[1][1] && s[0][0] == s[2][2]) {
if (s[0][0] == 1) win |= 1;
if (s[0][0] == 2) win |= 2;
}
if (s[2][0] == s[1][1] && s[2][0] == s[0][2]) {
if (s[1][1] == 1) win |= 1;
if (s[1][1] == 2) win |= 2;
}
return win;
}
int to(vector<vector<int>>& state) {
int tot = 0;
FOR(i, 3) {
FOR(j, 3) {
tot *= 3;
tot += state[i][j];
}
}
return tot;
}
unordered_map<int, pair<int, int>> mp;
pair<int, int> dfs(vector<vector<int>>& state, int cnt) {
int T = to(state);
if (mp.count(T)) return mp[T];
int win = 0;
if (cnt >= 5) win = State(state);
if (win == 3) {
return mp[T] = MP(0, 0);
}
if (win == 1) {
return mp[T] = MP(1, 0);
}
if (win == 2) {
return mp[T] = MP(0, 1);
}
if (cnt == 9) return mp[T] = MP(0, 0);
int c = ((cnt & 1)?2:1);
pair<int, int> ans{};
FOR(i, 3) {
FOR(j, 3) {
if (state[i][j] == 0) {
vector<vector<int>> nxt = state;
nxt[i][j] = c;
auto p = dfs(nxt, cnt + 1);
ans.A += p.A;
ans.B += p.B;
}
}
}
return mp[T] = ans;
}
// X for 1, O for 2; . for 0
void solve() {
vector<vector<int>> state(3, vector<int>(3));
string s;
cin >> s;
FOR(i, 3) {
FOR(j, 3) {
if (s[i * 3 + j] == 'X') state[i][j] = 1;
if (s[i * 3 + j] == 'O') state[i][j] = 2;
}
}
int Xcnt = 0, Ocnt = 0;
FOR(i, 3) {
FOR(j, 3) {
if (state[i][j] == 1) Xcnt++;
if (state[i][j] == 2) Ocnt++;
}
}
if (Xcnt < Ocnt || Xcnt > Ocnt + 1) {
cout << "-1 -1\n";
return;
}
if (State(state) == 3) {
cout << "-1 -1\n";
return;
}
auto p = dfs(state, Xcnt + Ocnt);
cout << p.A << ' ' << p.B << '\n';
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int numtests;
cin >> numtests;
while(numtests--) {
solve();
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3600kb
input:
4 XX..O.... X...OX... OOOX.X.X. OOOXXX...
output:
191 194 232 200 0 1 -1 -1
result:
ok 4 lines
Test #2:
score: 0
Accepted
time: 19ms
memory: 3824kb
input:
100000 ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......
output:
131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 131184 77904 1...
result:
ok 100000 lines
Test #3:
score: -100
Wrong Answer
time: 17ms
memory: 3904kb
input:
100000 ......... X........ O........ .X....... XX....... OX....... .O....... XO....... OO....... ..X...... X.X...... O.X...... .XX...... XXX...... OXX...... .OX...... XOX...... OOX...... ..O...... X.O...... O.O...... .XO...... XXO...... OXO...... .OO...... XOO...... OOO...... ...X..... X..X..... O.....
output:
131184 77904 14652 7896 -1 -1 14232 10176 -1 -1 1798 1276 -1 -1 2048 756 -1 -1 14652 7896 -1 -1 1832 1132 -1 -1 -1 -1 220 248 2048 756 268 144 -1 -1 -1 -1 1832 1132 -1 -1 1798 1276 220 248 -1 -1 -1 -1 -1 -1 -1 -1 14232 10176 -1 -1 1798 1276 -1 -1 -1 -1 264 188 1868 1080 239 126 -1 -1 -1 -1 -1 -1 312...
result:
wrong answer 882nd lines differ - expected: '-1 -1', found: '1 0'