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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#414949 | #4234. Tic Tac Toe Counting | ivan_len# | TL | 0ms | 3520kb | C++20 | 2.5kb | 2024-05-20 04:49:06 | 2024-05-20 04:49:06 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
#define PB push_back
#define MP make_pair
#define A first
#define B second
#define SZ(x) int(x.size())
#define FR(i, a, b) for (int i = (a); i < (b); ++i)
#define FOR(i, n) FR(i, 0, n)
const int M = 1000000007;
mt19937_64 rnd(chrono::steady_clock::now().time_since_epoch().count());
int n;
int State(vector<vector<int>>& s) {
int win = 0;
FOR(i, 3) {
if (s[i][0] == s[i][1] && s[i][0] == s[i][2]) {
if (s[i][0] == 1) win |= 1;
if (s[i][0] == 2) win |= 2;
}
if (s[0][i] == s[1][i] && s[0][i] == s[2][i]) {
if (s[0][i] == 1) win |= 1;
if (s[0][i] == 2) win |= 2;
}
}
if (s[0][0] == s[1][1] && s[0][0] == s[2][2]) {
if (s[0][0] == 1) win |= 1;
if (s[0][0] == 2) win |= 2;
}
if (s[2][0] == s[1][1] && s[2][0] == s[0][2]) {
if (s[1][1] == 1) win |= 1;
if (s[1][1] == 2) win |= 2;
}
return win;
}
int X, O;
void dfs(vector<vector<int>>& state) {
int win = State(state);
if (win == 3) return;
if (win == 1) {
X++;
return;
}
if (win == 2) {
O++;
return;
}
int cnt = 0;
FOR(i, 3) {
FOR(j, 3) {
if (state[i][j] != 0) cnt++;
}
}
if (cnt == 9) return;
int c = ((cnt & 1)?2:1);
FOR(i, 3) {
FOR(j, 3) {
if (state[i][j] == 0) {
vector<vector<int>> nxt = state;
nxt[i][j] = c;
dfs(nxt);
}
}
}
}
// X for 1, O for 2; . for 0
void solve() {
vector<vector<int>> state(3, vector<int>(3));
string s;
cin >> s;
// cerr << s << '\n';
X = 0; O = 0;
FOR(i, 3) {
FOR(j, 3) {
if (s[i * 3 + j] == 'X') state[i][j] = 1;
if (s[i * 3 + j] == 'O') state[i][j] = 2;
}
}
int Xcnt = 0, Ocnt = 0;
FOR(i, 3) {
FOR(j, 3) {
if (state[i][j] == 1) Xcnt++;
if (state[i][j] == 2) Ocnt++;
}
}
// cerr << Xcnt << ' ' << Ocnt << '\n';
if (Xcnt < Ocnt || Xcnt > Ocnt + 1) {
cout << "-1 -1\n";
return;
}
if (State(state) == 3) {
cout << "-1 -1\n";
return;
}
dfs(state);
cout << X << ' ' << O << '\n';
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int numtests;
cin >> numtests;
while(numtests--) {
solve();
}
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3520kb
input:
4 XX..O.... X...OX... OOOX.X.X. OOOXXX...
output:
191 194 232 200 0 1 -1 -1
result:
ok 4 lines
Test #2:
score: -100
Time Limit Exceeded
input:
100000 ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......... ......