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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#413646#5141. Identical ParityhuangbrotherWA 56ms3688kbC++17911b2024-05-17 20:34:372024-05-17 20:34:38

Judging History

你现在查看的是最新测评结果

  • [2024-05-17 20:34:38]
  • 评测
  • 测评结果:WA
  • 用时:56ms
  • 内存:3688kb
  • [2024-05-17 20:34:37]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define int long long
int a[100010];

int exgcd(int a,int b,int &x,int &y){
    if(!b){
        x=1,y=0;
        return a;
    }
    int d=exgcd(b,a%b,y,x);
    y-=x*(a/b);
    return d;
}
signed main(){
    int t;
    cin>>t;
    while(t--){
        int n,k;
        cin>>n>>k;
        if(n%k==0){
            if((n/2)%(n/k)==0)cout<<"Yes\n";
            else cout<<"No\n";
        }else {
            int res1=n%k;
            int res0=k-res1;
            int cnt0=n/2;
            int x,y;
            int d=exgcd(n/k,n/k+1,x,y);
            int mod=(n/k+1)/d;
            x=((x*cnt0)%mod+mod)%mod;
            int r=cnt0-x*(n/k)/(n/k+1);
            int X=(res0-x)/mod*mod+x;
            int l=cnt0-X*(n/k)/(n/k+1);
            if(r<0||l>res1||x>res0)cout<<"No\n";
            else cout<<"Yes\n";
        }
        
    }
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3688kb

input:

3
3 1
4 2
5 3

output:

No
Yes
Yes

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: -100
Wrong Answer
time: 56ms
memory: 3616kb

input:

100000
1 1
2 1
2 2
3 1
3 2
3 3
4 1
4 2
4 3
4 4
5 1
5 2
5 3
5 4
5 5
6 1
6 2
6 3
6 4
6 5
6 6
7 1
7 2
7 3
7 4
7 5
7 6
7 7
8 1
8 2
8 3
8 4
8 5
8 6
8 7
8 8
9 1
9 2
9 3
9 4
9 5
9 6
9 7
9 8
9 9
10 1
10 2
10 3
10 4
10 5
10 6
10 7
10 8
10 9
10 10
11 1
11 2
11 3
11 4
11 5
11 6
11 7
11 8
11 9
11 10
11 11
12 1
...

output:

Yes
No
Yes
No
Yes
Yes
No
Yes
Yes
Yes
No
No
Yes
Yes
Yes
No
Yes
No
No
No
Yes
No
No
No
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
No
No
No
No
Yes
Yes
Yes
Yes
Yes
No
Yes
No
No
No
No
No
No
No
Yes
No
No
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
No
No
No
No
No
Yes
...

result:

wrong answer expected YES, found NO [12th token]