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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#413349 | #4888. Decoding The Message | chenxinyang2006 | WA | 1ms | 3732kb | C++20 | 5.3kb | 2024-05-17 13:40:54 | 2024-05-17 13:40:54 |
Judging History
answer
#include <bits/stdc++.h>
#define rep(i,j,k) for(int i=(j);i<=(k);i++)
#define per(i,j,k) for(int i=(j);i>=(k);i--)
#define uint unsigned int
#define ll long long
#define ull unsigned long long
#define db double
#define ldb long double
#define pii pair<int,int>
#define pll pair<ll,ll>
#define mkp make_pair
#define eb emplace_back
#define SZ(S) (int)S.size()
#define mod 65535
//#define mod 1000000007
#define inf 0x3f3f3f3f
#define linf 0x3f3f3f3f3f3f3f3f
using namespace std;
template <class T>
void chkmax(T &x,T y){
if(x < y) x = y;
}
template <class T>
void chkmin(T &x,T y){
if(x > y) x = y;
}
inline int popcnt(int x){
return __builtin_popcount(x);
}
inline int ctz(int x){
return __builtin_ctz(x);
}
template <int P>
class mod_int
{
using Z = mod_int;
private:
static int mo(int x) { return x < 0 ? x + P : x; }
public:
int x;
int val() const { return x; }
mod_int() : x(0) {}
template <class T>
mod_int(const T &x_) : x(x_ >= 0 && x_ < P ? static_cast<int>(x_) : mo(static_cast<int>(x_ % P))) {}
bool operator==(const Z &rhs) const { return x == rhs.x; }
bool operator!=(const Z &rhs) const { return x != rhs.x; }
Z operator-() const { return Z(x ? P - x : 0); }
Z pow(long long k) const
{
Z res = 1, t = *this;
while (k)
{
if (k & 1)
res *= t;
if (k >>= 1)
t *= t;
}
return res;
}
Z &operator++()
{
x < P - 1 ? ++x : x = 0;
return *this;
}
Z &operator--()
{
x ? --x : x = P - 1;
return *this;
}
Z operator++(int)
{
Z ret = x;
x < P - 1 ? ++x : x = 0;
return ret;
}
Z operator--(int)
{
Z ret = x;
x ? --x : x = P - 1;
return ret;
}
Z inv() const { return pow(P - 2); }
Z &operator+=(const Z &rhs)
{
(x += rhs.x) >= P && (x -= P);
return *this;
}
Z &operator-=(const Z &rhs)
{
(x -= rhs.x) < 0 && (x += P);
return *this;
}
Z operator-()
{
return -x;
}
Z &operator*=(const Z &rhs)
{
x = 1ULL * x * rhs.x % P;
return *this;
}
Z &operator/=(const Z &rhs) { return *this *= rhs.inv(); }
#define setO(T, o) \
friend T operator o(const Z &lhs, const Z &rhs) \
{ \
Z res = lhs; \
return res o## = rhs; \
}
setO(Z, +) setO(Z, -) setO(Z, *) setO(Z, /)
#undef setO
friend istream& operator>>(istream& is, mod_int& x)
{
long long tmp;
is >> tmp;
x = tmp;
return is;
}
friend ostream& operator<<(ostream& os, const mod_int& x)
{
os << x.val();
return os;
}
};
using Z = mod_int<mod>;
Z power(Z p,ll k){
Z ans = 1;
while(k){
if(k % 2 == 1) ans *= p;
p *= p;
k /= 2;
}
return ans;
}
int T,n,k;
int occ[260],_occ[260];
int a[15];
const int m = 256;
Z brute(){
n = 0;
rep(i,0,m){
while(occ[i]){
a[n++] = i;
occ[i]--;
}
}
// rep(i,0,n - 1) printf("%d ",a[i]);
// printf("\n");
Z answer = 1,sum;
rep(S,0,(1 << n) - 1){
if(popcnt(S) != (n + 1) / 2) continue;
sum = 0;
rep(i,0,n - 1){
if((S >> i) & 1) sum += a[i];
else sum += 256 * a[i];
}
answer *= sum;
}
int rk = 1;
rep(i,1,n / 2) rk *= i;
rep(i,1,(n + 1) / 2) rk *= i;
return power(answer,rk);
}
bitset <520> dp[260],ndp[260];
void trans(int C){
rep(i,0,m) ndp[(i + C) % 257] |= dp[i] << 1;
rep(i,0,m){
dp[i] |= ndp[i];
ndp[i].reset();
}
}
int check(int maj){//除了 maj,剩下 occ 的和至多 2*256
if(maj == -1) maj = 0;
int sz = 0;
ll inst = 0;
//目标子集大小是 n/2
rep(i,0,m){
inst += 1ll * i * occ[i];
dp[i].reset();
ndp[i].reset();
}
inst = inst * 129 % 257;
dp[0].set(0);
rep(i,0,m){
if(i == maj) continue;
while(occ[i]){
trans(i);
occ[i]--;
sz++;
}
}
rep(i,0,m){
rep(j,0,min(n / 2,sz)){
if(dp[i].test(j) && occ[maj] >= n / 2 - j && (i + 1ll * maj * (n / 2 - j)) % m == inst) return 0;
}
}
return 1;
}
void solve(){
memset(occ,0,sizeof(occ));
scanf("%d",&k);
rep(i,1,k){
int pos;
scanf("%d",&pos);
scanf("%d",&occ[pos]);
}
n = 0;
rep(i,0,m){
n += occ[i];
_occ[i] = occ[i];
}
if(n <= 11){
printf("%d\n",brute().val());
return;
}
rep(p,1,256){
int i1 = -1,i2 = -1;
rep(i,0,m){
if(!_occ[i]) continue;
if(i1 == -1) i1 = i;
else i2 = i;
}
if(i2 == -1){
printf("%d\n",check(i1));
return;
}
_occ[i1]--;_occ[i2]--;
}
}
int main(){
// freopen("test.in","r",stdin);
scanf("%d",&T);
while(T--) solve();
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3708kb
input:
5 1 42 1 2 0 1 1 1 1 239 2 2 1 1 2 1 3 1 1 2 2 3 2
output:
42 256 514 1284 61726
result:
ok 5 number(s): "42 256 514 1284 61726"
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 3732kb
input:
100 1 213 79 1 54 69 1 218 55 1 248 80 1 101 8 1 153 79 1 240 45 1 112 70 1 217 5 1 208 64 1 48 30 1 0 19 1 53 40 1 63 17 1 179 65 1 221 22 1 135 84 1 138 20 1 54 29 1 114 19 1 253 94 1 240 36 1 40 94 1 244 93 1 239 24 1 133 8 1 105 91 1 45 43 1 241 74 1 206 17 1 100 73 1 133 44 1 57 70 1 56 72 1 47...
output:
1 1 1 1 32896 1 1 1 43570 1 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 32896 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 15420 1 22101 1 1 1 1 1 1 1 1 1 239 1 1 1 1 1 1 1 1 1 1 1 1 39321 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
result:
wrong answer 1st numbers differ - expected: '21846', found: '1'