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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#411544 | #6744. Square | zhangmeixing | AC ✓ | 40ms | 3732kb | C++23 | 923b | 2024-05-15 15:43:33 | 2024-05-15 15:43:34 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define pii pair<int, int>
#define int long long
#define inf 1e18
#define rep(i, l, n) for (int i = l; i <= n; i++)
#define per(i, l, n) for (int i = n; i >= l; i--)
//cout<<fixed<<setprecision(15)
const int mol=998244353;
const int N = 3e5+10,M=5010;
int qmi(int a,int k){int res=1;while(k){if(k&1)res=res*a%mol;a=a*a%mol;k>>=1;}return res;}
int inv(int x){return qmi(x%mol,mol-2);}
int n,m,q,k;
int work(int x)
{
return (int)(sqrt(2*x)+1.5);
}
void solve()
{
int x,y;
cin>>x>>y;
if(x>=y)
{
cout<<x-y<<endl;
return ;
}
int l=work(x),r=work(y);
int l1=l*(l-1)/2-x,r1=r*(r-1)/2-y;
if(l1<=r1)
{
cout<<r-l+r1-l1<<endl;
}
else cout<<r+r1-l1<<endl;
}
signed main()
{
ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
int T = 1;
cin>>T;
for (int i = 1; i <= T; i++)solve();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3536kb
input:
2 5 1 1 5
output:
4 3
result:
ok 2 number(s): "4 3"
Test #2:
score: 0
Accepted
time: 40ms
memory: 3732kb
input:
100000 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 21 1 22 1 23 1 24 1 25 1 26 1 27 1 28 1 29 1 30 1 31 1 32 1 33 1 34 1 35 1 36 1 37 1 38 1 39 1 40 1 41 1 42 1 43 1 44 1 45 1 46 1 47 1 48 1 49 1 50 1 51 1 52 1 53 1 54 1 55 1 56 1 57 1 58 1 59 1 60 1 ...
output:
0 2 1 4 3 2 6 5 4 3 8 7 6 5 4 10 9 8 7 6 5 12 11 10 9 8 7 6 14 13 12 11 10 9 8 7 16 15 14 13 12 11 10 9 8 18 17 16 15 14 13 12 11 10 9 20 19 18 17 16 15 14 13 12 11 10 22 21 20 19 18 17 16 15 14 13 12 11 24 23 22 21 20 19 18 17 16 15 14 13 12 26 25 24 23 22 21 20 19 18 1 0 2 2 1 3 4 3 2 4 6 5 4 3 5 ...
result:
ok 100000 numbers