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#411059#7513. Palindromic BeadsSortingWA 1ms7700kbC++205.6kb2024-05-14 20:55:432024-05-14 20:55:44

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你现在查看的是最新测评结果

  • [2024-05-14 20:55:44]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:7700kb
  • [2024-05-14 20:55:43]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std ;
typedef long long ll ;
typedef unsigned long long ull ;
typedef pair < int , int > pii ;
typedef vector < int > vi ;
#define fi first
#define se second
mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());

#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()

const int MAXN = 2e5 + 7 ;
const int LOG = 18 ;
const int MAXVAL = 3.5e7 ;

int n ;
vector < int > v[ MAXN ] ;
int lvl[ MAXN ] , LCA[ MAXN ][ LOG ] ;
vector < int > col[ MAXN ] ;

struct col_elem {
    int x , y , dist , id ;
};

int tp ;
int st[ MAXN ] , en[ MAXN ] ;

void init ( int x , int prv ) {
    st[ x ] = ++ tp ;
    for ( int i = 1 ; i < LOG ; ++ i ) {
        LCA[ x ][ i ] = LCA[ LCA[ x ][ i - 1 ] ][ i - 1 ] ;
    }
    for ( auto y : v[ x ] ) {
        if ( y == prv ) { continue ; }
        lvl[ y ] = lvl[ x ] + 1 ;
        LCA[ y ][ 0 ] = x ;
        init ( y , x ) ;
    }
    en[ x ] = tp ;
}

int get_lca ( int x , int y ) {
    for ( int i = LOG - 1 ; i >= 0 ; -- i ) {
        if ( lvl[ x ] - ( 1 << i ) >= lvl[ y ] ) {
            x = LCA[ x ][ i ] ;
        }
        if ( lvl[ y ] - ( 1 << i ) >= lvl[ x ] ) {
            y = LCA[ y ][ i ] ;
        }
    }
    for ( int i = LOG - 1 ; i >= 0 ; -- i ) {
        if ( LCA[ x ][ i ] != LCA[ y ][ i ] ) {
            x = LCA[ x ][ i ] , y = LCA[ y ][ i ] ;
        }
    }
    if ( x != y ) { x = LCA[ x ][ 0 ] ; }
    return x ;
}

int move_up ( int x , int cnt ) {
    for ( int i = LOG - 1 ; i >= 0 ; -- i ) {
        if ( cnt >= ( 1 << i ) ) {
            cnt -= ( 1 << i ) ;
            x = LCA[ x ][ i ] ;
        }
    }
    return x ;
}

vector < col_elem > srt ;


int mx[ MAXVAL ] , pl[ MAXVAL ] , pr[ MAXVAL ] ;
int root[ 4 * MAXN ] ;

void tr_init ( int w , int l , int r ) {
    root[ w ] = ++ tp ;
    if ( l == r ) { return ; }
    int mid = ( l + r ) / 2 ;
    tr_init ( 2 * w , l , mid ) ;
    tr_init ( 2 * w + 1 , mid + 1 , r ) ;
}

void update_inner ( int w , int l , int r , int wh , int val ) {
    mx[ w ] = max ( mx[ w ] , val ) ;
    if ( l == r ) { return ; }
    int mid = ( l + r ) / 2 ;
    if ( wh <= mid ) {
        if ( pl[ w ] == 0 ) { pl[ w ] = ++ tp ; }
        update_inner ( pl[ w ] , l , mid , wh , val ) ; 
    }
    else {
        if ( pr[ w ] == 0 ) { pr[ w ] = ++ tp ; }
        update_inner ( pr[ w ] , mid + 1 , r , wh , val ) ;
    }
}

void update_outer ( int w , int l , int r , int pos , int wh , int val ) {
    update_inner ( root[ w ] , 1 , n , wh , val ) ;
    if ( l == r ) { return ; }
    int mid = ( l + r ) / 2 ;
    if ( pos <= mid ) { update_outer ( 2 * w , l , mid , pos , wh , val ) ; }
    else { update_outer ( 2 * w + 1 , mid + 1 , r , pos , wh , val ) ; }
}


int qret ;

void query_inner ( int w , int l , int r , int st , int en ) {
    if ( l > r || st > en ) { return ; }
    if ( r < st || en < l ) { return ; }
    if ( st <= l && r <= en ) {
        qret = max ( qret , mx[ w ] ) ;
        return ;
    }
    int mid = ( l + r ) / 2 ;
    if ( pl[ w ] != 0 ) { query_inner ( pl[ w ] , l , mid , st , en ) ; }
    if ( pr[ w ] != 0 ) { query_inner ( pr[ w ] , mid + 1 , r , st , en ) ; }
}

void query_outer ( int w , int l , int r , int st , int en , int aux_st , int aux_en ) {
    if ( l > r || st > en ) { return ; }
    if ( r < st || en < l ) { return ; }
    if ( st <= l && r <= en ) {
        query_inner ( root[ w ] , 1 , n , aux_st , aux_en ) ;
        return ;
    }
    int mid = ( l + r ) / 2 ;
    query_outer ( 2 * w , l , mid , st , en , aux_st , aux_en ) ;
    query_outer ( 2 * w + 1 , mid + 1 , r , st , en , aux_st , aux_en ) ;
}

int dp[ MAXN ] ;

void solve ( ) {
    cin >> n ;
    for ( int i = 1 , x ; i <= n ; ++ i ) {
        cin >> x ;
        col[ x ].push_back ( i ) ;
    }
    for ( int i = 1 , x , y ; i < n ; ++ i ) {
        cin >> x >> y ;
        v[ x ].push_back ( y ) ;
        v[ y ].push_back ( x ) ;
    }
    init ( 1 , -1 ) ;
    for ( int i = 1 ; i <= n ; ++ i ) {
        if ( col[ i ].size ( ) < 2 ) { continue ; }
        int x = col[ i ][ 0 ] , y = col[ i ][ 1 ] ;
        int dist = lvl[ x ] + lvl[ y ] - 2 * lvl[ get_lca ( x , y ) ] ;
        srt.push_back ( { x , y , dist , i } ) ;
    }
    auto cmp = [ & ] ( col_elem p1 , col_elem p2 ) {
        return ( p1.dist > p2.dist ) ;
    };
    sort ( srt.begin ( ) , srt.end ( ) , cmp ) ;
    tp = 1 ;
    tr_init ( 1 , 1 , n ) ;
    int ans = 0 ;
    for ( auto [ x , y , foo , id ] : srt ) {
        qret = 0 ;
        if ( lvl[ x ] > lvl[ y ] ) { swap ( x , y ) ; }
        if ( st[ x ] <= st[ y ] && en[ y ] <= en[ x ] ) {
            int hh = move_up ( y , lvl[ y ] - lvl[ x ] - 1 ) ;
            query_outer ( 1 , 1 , n , st[ y ] , en[ y ] , 1 , st[ hh ] - 1 ) ;
            query_outer ( 1 , 1 , n , st[ y ] , en[ y ] , en[ hh ] + 1 , n ) ;

            
            query_outer ( 1 , 1 , n , 1 , st[ hh ] - 1 , st[ y ] , en[ y ] ) ;
            query_outer ( 1 , 1 , n , en[ hh ] + 1 , n , st[ y ] , en[ y ] ) ;

            dp[ id ] = qret + 2 ;
            if ( LCA[ y ][ 0 ] == x ) { ans = max ( ans , dp[ id ] ) ; }
            else { ans = max ( ans , dp[ id ] + 1 ) ; }
        }
        else {
            query_outer ( 1 , 1 , n , st[ x ] , en[ x ] , st[ y ] , en[ y ] ) ;
            query_outer ( 1 , 1 , n , st[ y ] , en[ y ] , st[ x ] , en[ x ] ) ;
            dp[ id ] = qret + 2 ;
            ans = max ( ans , dp[ id ] + 1 ) ;
        }
        update_outer ( 1 , 1 , n , st[ x ] , st[ y ] , dp[ id ] ) ;
    }
    cout << ans << "\n" ;
}

int main ( ) {
    ios_base :: sync_with_stdio ( false ) ;
    cin.tie ( NULL ) ;
    int t = 1 ; // cin >> t ;
    while ( t -- ) { solve ( ) ; }
    return 0 ;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 5704kb

input:

4
1 1 2 2
1 2
2 3
2 4

output:

3

result:

ok single line: '3'

Test #2:

score: 0
Accepted
time: 1ms
memory: 5688kb

input:

5
1 3 2 2 1
1 2
2 3
3 4
4 5

output:

4

result:

ok single line: '4'

Test #3:

score: 0
Accepted
time: 1ms
memory: 7700kb

input:

6
1 1 2 2 3 3
1 2
2 3
3 4
4 5
5 6

output:

2

result:

ok single line: '2'

Test #4:

score: -100
Wrong Answer
time: 1ms
memory: 7672kb

input:

6
1 2 3 4 5 6
1 2
2 3
3 4
4 5
5 6

output:

0

result:

wrong answer 1st lines differ - expected: '1', found: '0'