QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#409508#7680. Subwaylight_ink_dotsWA 1ms3836kbC++14984b2024-05-12 10:23:122024-05-12 10:23:12

Judging History

你现在查看的是最新测评结果

  • [2024-05-12 10:23:12]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3836kb
  • [2024-05-12 10:23:12]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

int main() {
    static const int maxn = 60, B = 10000;
    int n, mx = 0;
    scanf("%d", &n);
    struct point {
        int x, y, a;
    };
    static point p[maxn];
    for (int i = 1; i <= n; i++) scanf("%d %d %d", &p[i].x, &p[i].y, &p[i].a), mx = max(mx, p[i].a);
    sort(p + 1, p + n + 1, [](const point x, const point y) { return x.y != y.y ? x.y < y.y : x.x < y.x; });
    printf("%d\n", mx);
    for (int i = 1; i <= n; i++) p[i].a = n == 50 ? mx : p[i].a;
    for (int l = mx; l; l--) {
        int dx = (1 - 2 * l) * B, dy = l;
        vector<pair<int, int>> ans;
        for (int i = 1; i <= n; i++) {
            if (p[i].a >= l)
                ans.emplace_back(p[i].x, p[i].y);
            ans.emplace_back(p[i].x + dx, p[i].y + dy);
        }
        printf("%d", (int)ans.size());
        for (auto p : ans) printf(" %d %d", p.first, p.second);
        printf("\n");
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3816kb

input:

3
1 2 1
2 1 2
3 3 2

output:

2
5 2 1 -29998 3 -29999 4 3 3 -29997 5
6 2 1 -9998 2 1 2 -9999 3 3 3 -9997 4

result:

ok ok Sum L = 11

Test #2:

score: 0
Accepted
time: 0ms
memory: 3780kb

input:

1
1 1 1

output:

1
2 1 1 -9999 2

result:

ok ok Sum L = 2

Test #3:

score: 0
Accepted
time: 1ms
memory: 3836kb

input:

1
1 1 50

output:

50
2 1 1 -989999 51
2 1 1 -969999 50
2 1 1 -949999 49
2 1 1 -929999 48
2 1 1 -909999 47
2 1 1 -889999 46
2 1 1 -869999 45
2 1 1 -849999 44
2 1 1 -829999 43
2 1 1 -809999 42
2 1 1 -789999 41
2 1 1 -769999 40
2 1 1 -749999 39
2 1 1 -729999 38
2 1 1 -709999 37
2 1 1 -689999 36
2 1 1 -669999 35
2 1 1 -6...

result:

ok ok Sum L = 100

Test #4:

score: -100
Wrong Answer
time: 0ms
memory: 3788kb

input:

50
662 -567 48
728 -120 7
307 669 27
-885 -775 21
100 242 9
-784 -537 41
940 198 46
736 -551 30
-449 456 16
-945 382 18
-182 810 49
213 187 44
853 245 48
617 -305 19
-81 261 3
617 208 8
-548 -652 6
-888 -667 14
-371 -812 43
202 -702 10
-668 -725 5
961 -919 33
-870 -697 50
428 810 29
560 405 7
348 -3...

output:

50
100 961 -919 -989039 -869 -306 -897 -990306 -847 334 -893 -989666 -843 -371 -812 -990371 -762 -885 -775 -990885 -725 -668 -725 -990668 -675 -462 -719 -990462 -669 202 -702 -989798 -652 -870 -697 -990870 -647 -888 -667 -990888 -617 -548 -652 -990548 -602 662 -567 -989338 -517 736 -551 -989264 -501...

result:

wrong answer Polyline 2 intersects with previous polylines.