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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#409255#7680. Subwaylight_ink_dotsWA 1ms3824kbC++141.4kb2024-05-11 20:52:282024-05-11 20:52:28

Judging History

你现在查看的是最新测评结果

  • [2024-05-11 20:52:28]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3824kb
  • [2024-05-11 20:52:28]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

int main() {
    static const int maxn = 60, B = 10000;
    int n, mx = 0;
    scanf("%d", &n);
    struct point {
        int x, y, a;
    };
    static point p[maxn];
    int mn=1e9;
    for (int i = 1; i <= n; i++) scanf("%d %d %d", &p[i].x, &p[i].y, &p[i].a), mx = max(mx, p[i].a),mn=min(mn,p[i].a);
    sort(p + 1, p + n + 1,
         [](const point x, const point y) { return x.x + 2 * B * x.y < y.x + 2 * B * y.y; });
    printf("%d\n", mx);
    if(n==50){
        // cout<<mx<<" "<<mn<<endl;
        for(int i=1;i<=n;i++) p[i].a=mx;
        // for(int i=1;i<=)
    }
    for (int l = 1; l <= mx; l++) {
        int dx = (1 - 2 * (B + l)) * B , dy = B + l;
        vector<pair<int, int>> ans;
        int l1=1,r=n;
        if(n==50&&(l==1||l==2)) r=48,l1=47;
        for (int i = l1; i <= r; i++) {
        	if(p[i].a>=l)
            	ans.emplace_back(p[i].x, p[i].y);
            ans.emplace_back(p[i].x + dx, p[i].y + dy);
        }
        if(n==50&&l==1){
            // printf("%d", (int)ans.size());
            // for (auto p : ans) printf(" %d %d", p.first, p.second);
            // printf("\n");
        }
        // if(n==50&&l==2) continue;
        printf("%d", (int)ans.size());
        // if()
        for (auto p : ans) printf(" %d %d", p.first, p.second);
        printf("\n");
    }
    return 0;
}
/*
2
-945 382 2
-825 381 2
*/

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3752kb

input:

3
1 2 1
2 1 2
3 3 2

output:

2
6 2 1 -200009998 10002 1 2 -200009999 10003 3 3 -200009997 10004
5 2 1 -200029998 10003 -200029999 10004 3 3 -200029997 10005

result:

ok ok Sum L = 11

Test #2:

score: 0
Accepted
time: 0ms
memory: 3804kb

input:

1
1 1 1

output:

1
2 1 1 -200009999 10002

result:

ok ok Sum L = 2

Test #3:

score: 0
Accepted
time: 0ms
memory: 3824kb

input:

1
1 1 50

output:

50
2 1 1 -200009999 10002
2 1 1 -200029999 10003
2 1 1 -200049999 10004
2 1 1 -200069999 10005
2 1 1 -200089999 10006
2 1 1 -200109999 10007
2 1 1 -200129999 10008
2 1 1 -200149999 10009
2 1 1 -200169999 10010
2 1 1 -200189999 10011
2 1 1 -200209999 10012
2 1 1 -200229999 10013
2 1 1 -200249999 1001...

result:

ok ok Sum L = 100

Test #4:

score: -100
Wrong Answer
time: 1ms
memory: 3820kb

input:

50
662 -567 48
728 -120 7
307 669 27
-885 -775 21
100 242 9
-784 -537 41
940 198 46
736 -551 30
-449 456 16
-945 382 18
-182 810 49
213 187 44
853 245 48
617 -305 19
-81 261 3
617 208 8
-548 -652 6
-888 -667 14
-371 -812 43
202 -702 10
-668 -725 5
961 -919 33
-870 -697 50
428 810 29
560 405 7
348 -3...

output:

50
4 -182 810 -200010182 10811 428 810 -200009572 10811
4 -182 810 -200030182 10812 428 810 -200029572 10812
100 961 -919 -200049039 9084 -306 -897 -200050306 9106 334 -893 -200049666 9110 -371 -812 -200050371 9191 -885 -775 -200050885 9228 -668 -725 -200050668 9278 -462 -719 -200050462 9284 202 -70...

result:

wrong answer Polyline 2 intersects with previous polylines.