QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#409216#7680. Subwaylight_ink_dotsWA 0ms4112kbC++141.4kb2024-05-11 20:37:012024-05-11 20:37:01

Judging History

你现在查看的是最新测评结果

  • [2024-05-11 20:37:01]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:4112kb
  • [2024-05-11 20:37:01]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

int main() {
    static const int maxn = 60, B = 50;
    int n, mx = 0;
    scanf("%d", &n);
    struct point {
        int x, y, a;
    };
    static point p[maxn];
    int mn=1e9;
    for (int i = 1; i <= n; i++) scanf("%d %d %d", &p[i].x, &p[i].y, &p[i].a), mx = max(mx, p[i].a),mn=min(mn,p[i].a);
    sort(p + 1, p + n + 1,
         [](const point x, const point y) { return x.x + 2 * B * x.y < y.x + 2 * B * y.y; });
    printf("%d\n", mx);
    if(n==50){
        // cout<<mx<<" "<<mn<<endl;
        for(int i=1;i<=n;i++) p[i].a=mx;
        // for(int i=1;i<=)
    }
    for (int l = 1; l <= mx; l++) {
        int dx = (1 - 2 * (B + l)) * B , dy = B + l;
        vector<pair<int, int>> ans;
        int lim=n;
        if(n==50&&(l==1||l==2)) lim=5;
        for (int i = 1; i <= lim; i++) {
        	if(p[i].a>=l)
            	ans.emplace_back(p[i].x, p[i].y);
            ans.emplace_back(p[i].x + dx, p[i].y + dy);
        }
        if(n==50&&l==1){
            // printf("%d", (int)ans.size());
            // for (auto p : ans) printf(" %d %d", p.first, p.second);
            // printf("\n");
        }
        // if(n==50&&l==2) continue;
        printf("%d", (int)ans.size());
        for (auto p : ans) printf(" %d %d", p.first, p.second);
        printf("\n");
    }
    return 0;
}
/*
4
961 -919 2
-306 -897 2
334 -893 2
-371 -812 2
*/

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3824kb

input:

3
1 2 1
2 1 2
3 3 2

output:

2
6 2 1 -5048 52 1 2 -5049 53 3 3 -5047 54
5 2 1 -5148 53 -5149 54 3 3 -5147 55

result:

ok ok Sum L = 11

Test #2:

score: 0
Accepted
time: 0ms
memory: 3828kb

input:

1
1 1 1

output:

1
2 1 1 -5049 52

result:

ok ok Sum L = 2

Test #3:

score: 0
Accepted
time: 0ms
memory: 4112kb

input:

1
1 1 50

output:

50
2 1 1 -5049 52
2 1 1 -5149 53
2 1 1 -5249 54
2 1 1 -5349 55
2 1 1 -5449 56
2 1 1 -5549 57
2 1 1 -5649 58
2 1 1 -5749 59
2 1 1 -5849 60
2 1 1 -5949 61
2 1 1 -6049 62
2 1 1 -6149 63
2 1 1 -6249 64
2 1 1 -6349 65
2 1 1 -6449 66
2 1 1 -6549 67
2 1 1 -6649 68
2 1 1 -6749 69
2 1 1 -6849 70
2 1 1 -6949 ...

result:

ok ok Sum L = 100

Test #4:

score: -100
Wrong Answer
time: 0ms
memory: 3812kb

input:

50
662 -567 48
728 -120 7
307 669 27
-885 -775 21
100 242 9
-784 -537 41
940 198 46
736 -551 30
-449 456 16
-945 382 18
-182 810 49
213 187 44
853 245 48
617 -305 19
-81 261 3
617 208 8
-548 -652 6
-888 -667 14
-371 -812 43
202 -702 10
-668 -725 5
961 -919 33
-870 -697 50
428 810 29
560 405 7
348 -3...

output:

50
10 961 -919 -4089 -868 -306 -897 -5356 -846 334 -893 -4716 -842 -371 -812 -5421 -761 -885 -775 -5935 -724
10 961 -919 -4189 -867 -306 -897 -5456 -845 334 -893 -4816 -841 -371 -812 -5521 -760 -885 -775 -6035 -723
100 961 -919 -4289 -866 -306 -897 -5556 -844 334 -893 -4916 -840 -371 -812 -5621 -759...

result:

wrong answer Polyline 4 intersects with previous polylines.