QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#409101#7680. Subwaylight_ink_dots#WA 1ms3804kbC++14949b2024-05-11 18:50:192024-05-11 18:50:19

Judging History

你现在查看的是最新测评结果

  • [2024-05-11 18:50:19]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3804kb
  • [2024-05-11 18:50:19]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

int main() {
    static const int maxn = 60, B = 10000;
    int n, mx = 0;
    scanf("%d", &n);
    struct point {
        int x, y, a;
    };
    static point p[maxn];
    for (int i = 1; i <= n; i++) scanf("%d %d %d", &p[i].x, &p[i].y, &p[i].a), mx = max(mx, p[i].a);
    sort(p + 1, p + n + 1,
         [](const point x, const point y) { return 2 * B * x.x + x.y < 2 * B * y.x + y.y; });
    printf("%d\n", mx);
    for (int l = mx; l; l--) {
        int dx = (1 - 2 * (B + l)) * B, dy = B + l;
        vector<pair<int, int>> ans;
        for (int i = 1; i <= n; i++)
            if (p[i].a >= l) {
                ans.emplace_back(p[i].x, p[i].y);
                ans.emplace_back(p[i].x + dx, p[i].y + dy);
            }
        printf("%d", (int)ans.size());
        for (auto p : ans) printf(" %d %d", p.first, p.second);
        printf("\n");
    }
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 0
Wrong Answer
time: 1ms
memory: 3804kb

input:

3
1 2 1
2 1 2
3 3 2

output:

2
4 2 1 -200029998 10003 3 3 -200029997 10005
6 1 2 -200009999 10003 2 1 -200009998 10002 3 3 -200009997 10004

result:

wrong answer Self-intersecting polyline 2.