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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#409073 | #7680. Subway | light_ink_dots# | WA | 1ms | 3832kb | C++14 | 920b | 2024-05-11 17:30:33 | 2024-05-11 17:30:33 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
int main() {
static const int maxn = 60, B = 10000;
int n, mx = 0;
scanf("%d", &n);
struct point {
int x, y, a;
};
static point p[maxn];
for (int i = 1; i <= n; i++) scanf("%d %d %d", &p[i].x, &p[i].y, &p[i].a), mx = max(mx, p[i].a);
sort(p + 1, p + n + 1, [](const point x, const point y) { return B * x.x + x.y < B * y.x + y.y; });
printf("%d\n", mx);
for (int l = mx; l; l--) {
int dx = l - B, dy = 1 - dx * B;
vector<pair<int, int>> ans;
for (int i = 1; i <= n; i++)
if (p[i].a >= l) {
ans.emplace_back(p[i].x, p[i].y);
ans.emplace_back(p[i].x + dx, p[i].y + dy);
}
printf("%d", (int)ans.size());
for (auto p : ans) printf(" %d %d", p.first, p.second);
printf("\n");
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3752kb
input:
3 1 2 1 2 1 2 3 3 2
output:
2 4 2 1 -9996 99980002 3 3 -9995 99980004 6 1 2 -9998 99990003 2 1 -9997 99990002 3 3 -9996 99990004
result:
ok ok Sum L = 10
Test #2:
score: 0
Accepted
time: 1ms
memory: 3688kb
input:
1 1 1 1
output:
1 2 1 1 -9998 99990002
result:
ok ok Sum L = 2
Test #3:
score: 0
Accepted
time: 0ms
memory: 3832kb
input:
1 1 1 50
output:
50 2 1 1 -9949 99500002 2 1 1 -9950 99510002 2 1 1 -9951 99520002 2 1 1 -9952 99530002 2 1 1 -9953 99540002 2 1 1 -9954 99550002 2 1 1 -9955 99560002 2 1 1 -9956 99570002 2 1 1 -9957 99580002 2 1 1 -9958 99590002 2 1 1 -9959 99600002 2 1 1 -9960 99610002 2 1 1 -9961 99620002 2 1 1 -9962 99630002 2 1...
result:
ok ok Sum L = 100
Test #4:
score: -100
Wrong Answer
time: 1ms
memory: 3692kb
input:
50 662 -567 48 728 -120 7 307 669 27 -885 -775 21 100 242 9 -784 -537 41 940 198 46 736 -551 30 -449 456 16 -945 382 18 -182 810 49 213 187 44 853 245 48 617 -305 19 -81 261 3 617 208 8 -548 -652 6 -888 -667 14 -371 -812 43 202 -702 10 -668 -725 5 961 -919 33 -870 -697 50 428 810 29 560 405 7 348 -3...
output:
50 4 -870 -697 -10820 99499304 -3 -296 -9953 99499705 8 -870 -697 -10821 99509304 -182 810 -10133 99510811 -3 -296 -9954 99509705 135 -187 -9816 99509814 12 -870 -697 -10822 99519304 -182 810 -10134 99520811 -3 -296 -9955 99519705 135 -187 -9817 99519814 662 -567 -9290 99519434 853 245 -9099 9952024...
result:
wrong answer Polyline 2 intersects with previous polylines.