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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#408363 | #6396. Puzzle: Kusabi | Rico64 | WA | 4ms | 16076kb | C++23 | 1.8kb | 2024-05-10 08:04:58 | 2024-05-10 08:05:00 |
Judging History
answer
#include <iostream>
#include <vector>
#include <list>
const int MAX_N = 100000;
using namespace std;
int n;
string val[MAX_N];
vector<int> graph[MAX_N];
list<int> tong[MAX_N], duan[MAX_N], chang[MAX_N];
void search1(int v, int p, int l) {
if (val[v] == "Duan") {
duan[l].push_back(v);
} else if (val[v] == "Tong") {
tong[l].push_back(v);
} else if (val[v] == "Chang") {
chang[l].push_back(v);
}
for (const int& ne : graph[v]) {
if (ne == p) continue;
search1(ne, v, l + 1);
}
}
int main() {
cin >> n;
for (int i = 1, f, t; i < n; ++i) {
cin >> f >> t;
f--; t--;
cin >> val[f];
graph[f].push_back(t);
graph[t].push_back(f);
}
search1(0, -1, 0);
vector<pair<int,int>> res;
list<int> duans;
for (int l = 0; l < n; ++l) {
while (!chang[l].empty() && !duans.empty()) {
res.push_back({chang[l].front(), duans.front()});
chang[l].pop_front();
duans.pop_front();
}
if (!chang[l].empty()) {
cout << "NO" << endl;
return 0;
}
while (tong[l].size() >= 2) {
int f = tong[l].front(); tong[l].pop_front();
int t = tong[l].front(); tong[l].pop_front();
res.push_back({f, t});
}
if (!tong[l].empty()) {
cout << "NO" << endl;
return 0;
}
while (!duan[l].empty()) {
int v = duan[l].front(); duan[l].pop_front();
duans.push_back(v);
}
}
if (!duans.empty()) {
cout << "NO" << endl;
return 0;
}
cout << "YES" << endl;
for (const auto& r : res) {
cout << r.first + 1 << ' ' << r.second + 1 << endl;
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 16076kb
input:
8 2 1 - 3 1 - 4 2 Tong 5 2 Tong 6 3 Duan 7 3 - 8 7 Chang
output:
YES 4 5 8 6
result:
ok Correct.
Test #2:
score: -100
Wrong Answer
time: 4ms
memory: 16072kb
input:
10 2 1 Duan 3 2 Duan 4 2 - 5 4 Chang 6 2 Chang 7 1 Duan 8 6 Tong 9 6 Tong 10 3 Chang
output:
YES 6 2 10 7 5 3 8 9
result:
wrong answer Edge 3-2 used twice.