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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#407876#6744. SquarelrherAC ✓479ms3908kbC++142.0kb2024-05-09 13:47:122024-05-09 13:47:12

Judging History

你现在查看的是最新测评结果

  • [2024-05-09 13:47:12]
  • 评测
  • 测评结果:AC
  • 用时:479ms
  • 内存:3908kb
  • [2024-05-09 13:47:12]
  • 提交

answer

#include<set>
#include<map>
#include<cmath>
#include<ctime>
#include<stack>
#include<queue>
#include<deque>
#include<string>
#include<bitset>
#include<vector>
#include<cstdio>
#include<random>
#include<complex>
#include<cstdlib>
#include<climits>
#include<iomanip>
#include<cstring>
#include<stdlib.h>
#include<iostream>
#include<algorithm>
#include<unordered_map>
using namespace std;
// #define getchar()(p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++)
// char buf[1<<21],*p1=buf,*p2=buf;
const long long _base=107374183;
int writetemp[30];
inline int read()
{
    char c=getchar();int x=0;bool f=0;
    for(;!isdigit(c);c=getchar())f^=!(c^45);
    for(;isdigit(c);c=getchar())x=(x<<1)+(x<<3)+(c^48);
    if(f)x=-x;
    return x;
}
inline void write(int x)
{
	int tot=(x==0);
    writetemp[1]=0;
	while(x) writetemp[++tot]=x%10,x/=10;
    while(tot) putchar(writetemp[tot--]+'0');
    putchar('\n');
	return ;
}
long long ans;
long long calc(long long x)
{
    return (x+1)*x/2;
}
long long add(long long x)
{
    return sqrt(x+x)+1.5;
}
int T;
long long x,y;
long long step(long long x,long long y)
{
    // add(x)~add(y)
    if(x>=y) return x-y;
    if(add(x)==add(y)) return x+add(x)-y+1;
    long long now=x;
    now+=calc(add(y)-1)-calc(add(x)-1);
    // printf("%lld %lld %lld %lld %lld\n",now,add(x),add(y),now-y,add(y)-add(x));
    // printf("%lld\n",now+add(now)-y);
    // if(add(now)!=add(y)) printf("cnm\n");
    if(now>=y) return now-y+add(y)-add(x);
    return now+add(now)-y+add(y)-add(x)+1;
}
int main()
{
    // freopen("s.out","r",stdin);
    // freopen("a.out","w",stdout);
    scanf("%d",&T);
    while(T--)
    {
        scanf("%lld%lld",&x,&y),ans=step(x,y);
        long long now=add(x)-1;
        long long val=calc(now-1);
        for(long long i=val;i>=max(1ll,val-1000);i--) ans=min(ans,step(i,y)+x-i);
        // if(ans==1349069334) printf("x:%lldy:%lld\n",x,y);
        printf("%lld\n",ans);
    }
    return 0;
}
/*
*/

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3864kb

input:

2
5 1
1 5

output:

4
3

result:

ok 2 number(s): "4 3"

Test #2:

score: 0
Accepted
time: 479ms
memory: 3908kb

input:

100000
1 1
1 2
1 3
1 4
1 5
1 6
1 7
1 8
1 9
1 10
1 11
1 12
1 13
1 14
1 15
1 16
1 17
1 18
1 19
1 20
1 21
1 22
1 23
1 24
1 25
1 26
1 27
1 28
1 29
1 30
1 31
1 32
1 33
1 34
1 35
1 36
1 37
1 38
1 39
1 40
1 41
1 42
1 43
1 44
1 45
1 46
1 47
1 48
1 49
1 50
1 51
1 52
1 53
1 54
1 55
1 56
1 57
1 58
1 59
1 60
1 ...

output:

0
2
1
4
3
2
6
5
4
3
8
7
6
5
4
10
9
8
7
6
5
12
11
10
9
8
7
6
14
13
12
11
10
9
8
7
16
15
14
13
12
11
10
9
8
18
17
16
15
14
13
12
11
10
9
20
19
18
17
16
15
14
13
12
11
10
22
21
20
19
18
17
16
15
14
13
12
11
24
23
22
21
20
19
18
17
16
15
14
13
12
26
25
24
23
22
21
20
19
18
1
0
2
2
1
3
4
3
2
4
6
5
4
3
5
...

result:

ok 100000 numbers