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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#406670 | #8543. Periodic Sequence | xiaolang | TL | 1ms | 3848kb | C++14 | 2.3kb | 2024-05-07 16:20:56 | 2024-05-07 16:21:01 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int N=3e6+5;
int n,MOD;
int cc[N];
int anss[N];
int tar[N];
int inv[N];
int cnt=0;
namespace Polynomial{
int cc[N];
void mul(vector<pair<int,int> > a,vector<pair<int,int> > b){
int lena=a.size();
int lenb=b.size();
for(int i=0;i<=n;i++){
cc[i]=0;
}
for(int i=0;i<lena;i++){
for(int j=0;j<lenb;j++){
anss[a[i].first+b[j].first]=(anss[a[i].first+b[j].first]+(long long)a[i].second*b[j].second%MOD)%MOD;
}
}
}
vector<pair<int,int> > mulinv(vector<pair<int,int> > x){
int xlen=x.size();
for(int i=0;i<=n;i++){
cc[i]=0;
tar[i]=0;
}
tar[0]=1;
vector<pair<int,int> >ans;
for(int i=0;i<=n;i++){
if(cc[i]==tar[i])continue;
else{
cnt++;
int nowc=(cc[i]-tar[i]+MOD)%MOD;
ans.push_back(make_pair(i,nowc));
for(int j=0;j<xlen;j++){
cc[i+x[j].first]=(cc[i+x[j].first]+(long long)nowc*x[j].second%MOD)%MOD;
}
}
}
return ans;
}
vector<int> div(vector<int> c){/* /(2x-1) */
vector<int>ans;
ans.clear();
int len=c.size();
for(int i=0;i<len;i++){
int t=(MOD-c[i])%MOD;
ans.push_back(t);
if(i!=len-1)c[i+1]=((long long)c[i+1]-2*t+MOD+MOD)%MOD;
}
return ans;
}
void div2(vector<int> c,int p){/* /(-x^p+2x-1) */
int len=c.size();
for(int i=0;i<len;i++){
int t=(MOD-c[i])%MOD;
anss[i]=(anss[i]+t)%MOD;
if(i!=len-1)c[i+1]=((long long)c[i+1]-2*t+MOD+MOD)%MOD;
if(i+p<len)c[i+p]=(c[i+p]+t)%MOD;
}
}
};
using namespace Polynomial;
vector<int> fz;
int maxdep=0;
int addlen=0;
int main(){
//freopen("1.txt","r",stdin);
//freopen("1.out","w",stdout);
//int tim1=clock();
scanf("%d%d",&n,&MOD);
int B=pow(n,0.45);
fz.resize(n+2);
for(int i=1;i<=B;i++){
for(int j=0;j<=n;j++)fz[j]=((j==i)?(MOD-1):0);
div2(fz,i+1);
}
int tim3=clock();
vector<int>ans(n+1000,0);
for(int i=n/B+1;i>=1;i--){
for(int j=B+1;j*i-1<=n;j++){
ans[j*i+i-1]=(ans[j*i+i-1]-1+MOD)%MOD;
}
ans=div(ans);
}
//int tim4=clock();
//cout<<tim4-tim3<<"\n";
//int tim4=clock();
//cout<<tim3-tim1<<"\n";
int tot=0;
for(int i=1;i<=n;i++){
//cout<<ans[i]<<" "<<anss[i]<<"\n";
cout<<(ans[i]+anss[i])%MOD<<" ";
}
cout<<"\n";
//int tim2=clock();
//cout<<tim2-tim1<<"\n";
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3848kb
input:
5 1000000007
output:
1 3 6 11 19
result:
ok 5 number(s): "1 3 6 11 19"
Test #2:
score: -100
Time Limit Exceeded
input:
200000 567894337
output:
1 3 6 11 19 33 57 100 177 317 573 1045 1919 3547 6592 12311 23091 43479 82153 155715 295983 564049 1077399 2062310 3955185 7598755 14622317 28179337 54379519 105071497 203254163 393607533 195106662 344669981 35619335 477103886 79913732 147415830 329955039 273123672 546045352 337527455 443978690 4597...