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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#404647#7782. Ursa Minor-0x3F-WA 386ms19032kbC++145.0kb2024-05-04 12:23:172024-05-04 12:23:19

Judging History

你现在查看的是最新测评结果

  • [2024-05-04 12:23:19]
  • 评测
  • 测评结果:WA
  • 用时:386ms
  • 内存:19032kb
  • [2024-05-04 12:23:17]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
const int mod = 1000000007;
inline int qpow(int a, int b) {
    int s = 1;
    while (b) {
        if (b & 1) s = (long long) s * a % mod;
        a = (long long) a * a % mod;
        (b >>= 1);
    }
    return s;
}
const int bas = 1919810;
const int rbas = qpow(bas, mod - 2);
const int _ = 2e5 + 10;
const int B = 450;
int lg[_], pw[_], rpw[_], spw[_];
inline int gcd(int x, int y) {
    while (y) {
        int z = x % y;
        x = y;
        y = z;
    }
    return x;
}
inline void init(int n) {
    pw[0] = rpw[0] = spw[0] = 1;
    for (int i = 1; i <= n; i++) {
        pw[i] = (long long) pw[i-1] * bas % mod;
        rpw[i] = (long long) rpw[i-1] * rbas % mod;
        spw[i] = (spw[i-1] + pw[i]) % mod;
    }
    lg[1] = 0;
    for (int i = 2; i <= n; i++) {
        lg[i] = lg[i-1] + (!(i & (i-1)));
    }
}
int n, arr[_];
struct node1 {
    int arr[_], brr[500];
    inline void add(int x, int k) {
        arr[x] = (arr[x] + k) % mod;
        int y = x / B;
        brr[y] = (brr[y] + k) % mod;
    }
    inline int query(int l, int r) {
        int L = l / B;
        int R = r / B;
        int ans = 0;
        if (R - L >= 2) {
            int ll = (L+1) * B - 1;
            int rr = R * B;
            for (int i = l; i <= ll; i++) {
                ans = (ans + arr[i]) % mod;
            }
            for (int i = L+1; i <= R-1; i++) {
                ans = (ans + brr[i]) % mod;
            }
            for (int i = rr; i <= r; i++) {
                ans = (ans + arr[i]) % mod;
            }
        } else {
            for (int i = l; i <= r; i++) {
                ans = (ans + arr[i]) % mod;
            }
        }
        return ans;
    }
} num1[500], num2[500];
struct node2 {
    int arr[_], brr[500];
    inline void add(int x, int k) {
        int l = x;
        int r = n;
        int L = l / B;
        int R = r / B;
        if (R - L >= 2) {
            int ll = (L+1) * B - 1;
            int rr = R * B;
            for (int i = l; i <= ll; i++) {
                arr[i] = (arr[i] + k) % mod;
            }
            for (int i = L+1; i <= R-1; i++) {
                brr[i] = (brr[i] + k) % mod;
            }
            for (int i = rr; i <= r; i++) {
                arr[i] = (arr[i] + k) % mod;
            }
        } else {
            for (int i = l; i <= r; i++) {
                arr[i] = (arr[i] + k) % mod;
            }
        }
    }
    inline int query(int l, int r) {
        int ans = (arr[r] + brr[r / B]) % mod;
        if (l != 1) {
            ans = ((ans - arr[l-1] - brr[(l-1) / B]) % mod + mod) % mod;
        }
        return ans;
    }
} num3;
inline void modify(int x, int k) {
    int diff = ((k - arr[x]) % mod + mod) % mod;
    for (int i = 1; i <= B; i++) {
        num1[i].add(x, (long long) diff * pw[x % i] % mod);
        if (!(x % i)) num2[i].add(x, diff);
    }
    num3.add(x, (long long) diff * pw[x] % mod);
    arr[x] = k;
}
inline int query(int l, int r, int k) {
    if (k <= B) {
        return num1[k].query(l, r);
    } else {
        int ans = 0;
        for (int i = l / k; i <= r / k; i++) {
            int L = max(l, i * k);
            int R = min(r, (i+1) * k - 1);
            ans = (ans + (long long) num3.query(L, R) * rpw[i * k]) % mod;
        }
        return ans;
    }
}
inline int tquery(int l, int r, int k) {
    if (k <= B) {
        return num2[k].query(l, r);
    } else {
        int ans = 0;
        for (int i = ((l+k-1) / k) * k; i <= r; i += k) {
            ans = (ans + arr[i]) % mod;
        }
        return ans;
    }
}
int m, st[20][_];
inline int calc(int l, int r) {
    int k = lg[r - l + 1];
    return gcd(st[k][l], st[k][r-(1<<k)+1]);
}
int main() {
    init(200000);
    ios::sync_with_stdio(0);
    cin.tie(0);
    int q;
    cin >> n >> m >> q;
    for (int i = 1; i <= n; i++) {
        int x;
        cin >> x;
        modify(i, x);
    }
    for (int i = 1; i <= m; i++) {
        int x;
        cin >> x;
        st[0][i] = x;
    }
    for (int k = 1; k <= lg[n]; k++) {
        for (int i = 1; i <= n - (1 << k) + 1; i++) {
            st[k][i] = gcd(st[k-1][i], st[k-1][i+(1<<(k-1))]);
        }
    }
    while (q--) {
        char ch;
        cin >> ch;
        switch (ch) {
            case 'Q': {
                int l, r, s, t;
                cin >> l >> r >> s >> t;
                int k = gcd(r-l+1, calc(s, t));
                int sum = query(l, r, k);
                int tmp = tquery(l, r, k);
                if (sum == (long long) tmp * spw[k-1] % mod) {
                    cout << "Yes\n";
                } else {
                    cout << "No\n";
                }
                break;
            }
            case 'U': {
                int p, v;
                cin >> p >> v;
                modify(p, v);
                break;
            }
        }
    }
    cout << flush;
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 9448kb

input:

6 4 5
1 1 4 5 1 4
3 3 2 4
Q 1 5 1 2
Q 2 5 3 4
U 5 2
Q 1 6 1 2
Q 2 5 3 4

output:

Yes
No
No
Yes

result:

ok 4 tokens

Test #2:

score: 0
Accepted
time: 5ms
memory: 9436kb

input:

1 1 1
0
1
Q 1 1 1 1

output:

Yes

result:

ok "Yes"

Test #3:

score: 0
Accepted
time: 386ms
memory: 19032kb

input:

2000 2000 200000
1 1 2 0 0 2 0 2 0 0 0 0 0 2 2 1 2 0 0 2 2 2 1 0 1 2 1 2 0 0 1 1 1 2 0 0 2 2 2 2 0 2 0 0 2 1 2 0 0 1 2 2 1 0 2 0 0 0 1 2 2 1 2 2 0 0 1 1 1 0 0 2 0 0 1 1 0 2 2 2 1 0 0 1 0 1 2 2 2 1 1 2 2 1 2 1 0 2 2 3 1 3 2 3 1 0 1 2 0 1 1 1 0 2 2 3 2 0 3 2 3 3 1 2 3 1 2 0 1 0 3 1 0 0 2 0 1 2 1 3 2 2...

output:

Yes
Yes
No
Yes
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
No
Yes
Yes
No
No
No
No
No
Yes
No
No
No
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
No
Yes
Yes
Yes
No
No
Yes
No
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
No...

result:

ok 100554 tokens

Test #4:

score: 0
Accepted
time: 278ms
memory: 10100kb

input:

1 200000 200000
998244353
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

output:

Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
...

result:

ok 100240 tokens

Test #5:

score: -100
Wrong Answer
time: 266ms
memory: 9988kb

input:

6 131072 200000
0 0 0 0 1000000000 1000000000
4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 ...

output:

No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No...

result:

wrong answer 1st words differ - expected: 'Yes', found: 'No'