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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#403047 | #6746. Merge the Rectangles | altaires1 | WA | 1ms | 3996kb | C++14 | 2.8kb | 2024-05-01 19:54:57 | 2024-05-01 19:54:57 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int maxn=1600;
set<pair<int,int>> shu[maxn];
set<pair<int,int>> heng[maxn];
string zifu[maxn];
int main(){
//freopen("5.txt","r",stdin);
//freopen("144.out","w",stdout);
int n,m;
cin>>n>>m;
for(int i=1;i<=n-1;i++){
string s;
cin>>s;
s=' '+s;
pair<int,int> temp={-1,-1};
for(int j=1;j<=m;j++){
if(s[j]=='1'){
if(temp.first==-1){
temp={j,j};
}
else{
temp.first=j;
}
}
else{
if(temp.first!=-1){
heng[i].insert(temp);
}
temp.first=-1;
}
if(j==m){
if(temp.first!=-1){
heng[i].insert(temp);
}
}
}
}
for(int i=1;i<=n;i++){
string temp;
cin>>temp;
zifu[i]=' '+temp;
}
for(int j=1;j<=m-1;j++){
pair<int,int> temp={-1,-1};
for(int i=1;i<=n;i++){
if(zifu[i][j]=='1'){
if(temp.first==-1){
temp={i,i};
}
else{
temp.first=i;
}
}
else{
if(temp.first!=-1){
shu[j].insert(temp);
}
temp.first=-1;
}
if(i==n){
if(temp.first!=-1){
shu[j].insert(temp);
}
}
}
}
int judge=0;
//for(int j=1;j<=m-1;j++){
// for(auto it : shu[j]){ //找到这样一条线段
// int up=it.second;
// up--;
// if(up==0){
// continue;
// }
// if(heng[up].empty()){
// continue;
// }
// auto iter=heng[up].lower_bound({j+1,0});
// if(iter==heng[up].end()){
// continue;
// }
// int left=iter->second;
// int right=iter->first;
// if(left>j){
// continue;
// }
// if(shu[right].empty()){
// continue;
// }
// iter=shu[right].lower_bound({up+1,0});
// if(iter==shu[right].end()){
// continue;
// }
// int up1=iter->second;
// if(up1>up){
// continue;
// }
// int down=iter->first;
// if(down>=it.first){
// continue;
// }
// if(heng[down].empty()){
// continue;
// }
// iter=heng[down].lower_bound({right+1,0});
// if(iter==heng[down].end()){
// continue;
// }
// if(iter->second!=j+1){
// continue;
// }
// if(iter->first<right+1){
// continue;
// }
// judge=1;
// }
//}
for(int j=1;j<=m-1;j++){
for(auto it : shu[j]){ //找到这样一条线段
int down=it.first;
auto iter=heng[down].lower_bound({j+1,0});
if(iter==heng[down].end()){
continue;
}
if(it.second>j){
continue;
}
int right=it.first;
iter=shu[right].lower_bound({down+1,0});
if(iter==shu[right].end()){
continue;
}
if(iter->second>down){
continue;
}
int up=iter->second;
if(up<=it.second){
continue;
}
up--;
iter=heng[up].lower_bound({right+1,0});
int left=iter->second;
if(left!=j+1){
continue;
}
judge=1;
}
}
if(judge==0){
cout<<"YES"<<'\n';
}
else{
cout<<"NO"<<'\n';
}
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 3996kb
input:
3 4 0000 0111 101 101 110
output:
YES
result:
ok answer is YES
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 3920kb
input:
3 3 110 011 01 11 10
output:
YES
result:
wrong answer expected NO, found YES