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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#401930#5438. Half MixeddukerRE 0ms11468kbC++201.4kb2024-04-29 16:50:372024-04-29 16:50:38

Judging History

你现在查看的是最新测评结果

  • [2024-04-29 16:50:38]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:11468kb
  • [2024-04-29 16:50:37]
  • 提交

answer

#define _CRT_SECURE_NO_WARNINGS 0
#include <iostream> 
#include<iomanip>
#include<algorithm>
#include<vector>
#include<map>
#include<string>
#include<set>
#include<queue>
#include <stack>
#include<list>
#include<cstring>
#include<cmath>
#include <cstdlib>
#include<fstream>
#include<climits>
using namespace std;
long long karr[1000005];
void solve() {
    int n, m;
    cin >> n >> m;
    if (((m * n * (m + 1) * (n + 1) ) / 4) % 2 == 0) {
        cout << "Yes" << endl;
        int total = m * (m + 1) / 4;
        vector<int> ans; 
        vector<bool> flag;
        long long sum = 1;
        bool swich = true;
        while (total > 0)
        {
            long long pos = lower_bound(karr + 1, karr + 1000000 + 1, total - m + sum) - karr;
            ans.push_back(pos);
            sum += pos;
            total -= karr[pos];
            for (int i = 0; i < pos; i++)
            {
                flag.push_back(swich);
            }
            swich = !swich;
        }
        for (int i = 0; i < n; i++)
        {
            for (int j = 0; j < m; j++)
            {
                printf("%d ", flag[j] ? 1 : 0);
            }
            printf("\n");
        }
    }
    else {
        cout << "No" << endl;
    }
}
int main() {
    int t;
    cin >> t;
    for (int i = 1; i < 1000000; i++)
    {
        karr[i] += karr[i - 1] + i;
    }
    while (t--)
    {
        solve();
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 11468kb

input:

2
2 3
1 1

output:

Yes
1 0 1 
1 0 1 
No

result:

ok OK, Accepted. (2 test cases)

Test #2:

score: -100
Runtime Error

input:

5382
1 1
1 2
2 1
1 3
2 2
3 1
1 4
2 3
3 2
4 1
1 5
2 4
3 3
4 2
5 1
1 6
2 5
3 4
4 3
5 2
6 1
1 7
2 6
3 5
4 4
5 3
6 2
7 1
1 8
2 7
3 6
4 5
5 4
6 3
7 2
8 1
1 9
2 8
3 7
4 6
5 5
6 4
7 3
8 2
9 1
1 10
2 9
3 8
4 7
5 6
6 5
7 4
8 3
9 2
10 1
1 11
2 10
3 9
4 8
5 7
6 6
7 5
8 4
9 3
10 2
11 1
1 12
2 11
3 10
4 9
5 8
6 ...

output:

No
No
No
Yes
1 0 1 
No
Yes

result: