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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#398959 | #8235. Top Cluster | Eray | RE | 3ms | 16184kb | C++14 | 2.3kb | 2024-04-25 20:24:10 | 2024-04-25 20:24:11 |
Judging History
answer
#include <bits/stdc++.h>
typedef long long LL;
const int N = 5e5 + 5;
int n, Q;
int a[N], b[N];
struct Edge { int to, nxt; LL w; } edge[N << 1];
int head[N];
void add_edge(int u, int v, LL w) { static int k = 1; edge[k] = (Edge){v, head[u], w}, head[u] = k++; }
int fa[N], dfn[N], dep[N], time_stamp;
LL depth[N];
int go[21][N];
void dfs(int u) {
dep[u] = dep[fa[u]] + 1;
dfn[u] = ++time_stamp, go[0][dfn[u]] = u;
for(int i = head[u]; i; i = edge[i].nxt) if(edge[i].to != fa[u]) {
int v = edge[i].to;
fa[v] = u;
depth[v] = depth[u] + edge[i].w;
dfs(v);
}
}
int lower_dep(int u, int v) { return dep[u] < dep[v] ? u : v; }
void binary_lifting() {
for(int j = 1; j <= 20; j++)
for(int i = 1; i + (1 << j) - 1 <= n; i++)
go[j][i] = lower_dep(go[j - 1][i], go[j - 1][i + (1 << (j - 1))]);
}
int lca(int u, int v) {
if(u == v) return u;
int l = dfn[u], r = dfn[v];
if(l > r) std::swap(l, r);
int k = 31 ^ __builtin_clz(r - l);
return fa[lower_dep(go[k][l + 1], go[k][r - (1 << k) + 1])];
}
LL dist(int u, int v) { return depth[u] + depth[v] - 2 * depth[lca(u, v)]; }
std::pair<int, int> diameter[N];
LL calc(const std::pair<int, int> &p) { return dist(p.first, p.second); }
std::pair<int, int> calc(const std::pair<int, int> &p, int u) {
auto cmp = [](const std::pair<int, int> &p1, const std::pair<int, int> &p2) { return calc(p1) < calc(p2); };
return std::max({p, {p.first, u}, {p.second, u}}, cmp);
}
int main() {
scanf("%d%d", &n, &Q);
for(int i = 1; i <= n; i++) scanf("%d", &a[i]);
for(int i = 1; i < n; i++) { int u, v; LL w; scanf("%d%d%lld", &u, &v, &w); add_edge(u, v, w), add_edge(v, u, w); }
for(int i = 1; i <= n; i++) if(b[i] <= n) b[a[i]] = i;
dfs(1);
binary_lifting();
int mx = 0;
for(int i = 0; i <= n; i++) {
if(!b[i]) { mx = i; break; }
if(i) diameter[i] = calc(diameter[i - 1], b[i]);
else diameter[i] = {b[i], b[i]};
// printf("%d: b = %d, diameter = {%d, %d}\n", i, b[i], diameter[i].first, diameter[i].second);
}
while(Q--) {
int u; LL d;
scanf("%d%lld", &u, &d);
int l = 1, r = mx + 1;
while(l < r) {
int mid = (l + r) >> 1;
if(calc(calc(diameter[mid - 1], u)) <= d) l = mid + 1;
else r = mid;
}
l--;
printf("%d\n", l);
}
return 0;
} /*
5 4
3 9 0 1 2
1 2 10
3 1 4
3 4 3
3 5 2
3 0
1 0
4 6
4 7
*/
詳細信息
Test #1:
score: 100
Accepted
time: 3ms
memory: 16184kb
input:
5 4 3 9 0 1 2 1 2 10 3 1 4 3 4 3 3 5 2 3 0 1 0 4 6 4 7
output:
1 0 3 4
result:
ok 4 number(s): "1 0 3 4"
Test #2:
score: -100
Runtime Error
input:
500000 500000 350828 420188 171646 209344 4 999941289 289054 79183 999948352 427544 160827 138994 192204 108365 99596 999987124 292578 2949 384841 269390 999920664 315611 163146 51795 265839 34188 999939494 145387 366234 86466 220368 357231 347706 332064 279036 173185 5901 217061 112848 37915 377359...