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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#398313 | #4893. Imbalance | jinqihao2023 | 0 | 331ms | 8960kb | C++14 | 5.2kb | 2024-04-25 10:45:27 | 2024-04-25 10:45:27 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int mod=998244353;
int n,k,m;
string s,t;
int power(int a,int b){int res=1;for(;b;b>>=1){if(b&1)res=1ll*res*a%mod;a=1ll*a*a%mod;}return res;}
namespace work1
{
const int N=125,M=(1<<19)+5;
int f[2][M];
void add(int &x,int y){x+=y;if(x>=mod)x-=mod;}
void solve()
{
memset(f,0,sizeof(f));
int now=0;
for(int i=1;i<=m;i++)now|=((s[i]-'0')<<m-i);
f[m&1][now]=1;
int all=(1<<k-1)-1;
for(int i=m;i<n;i++)
{
memset(f[i+1&1],0,sizeof(f[i+1&1]));
for(int j=0;j<(1<<k-1);j++)if(f[i&1][j])
{
for(int l=0;l<2;l++)
{
int now=(j<<1)|l;
if(i>=k-1 && __builtin_popcount(now)==k/2)continue;
add(f[i+1&1][now&all],f[i&1][j]);
}
}
}
int ans=0;
for(int i=0;i<(1<<k-1);i++)add(ans,f[n&1][i]);
printf("%d\n",ans);
}
}
int ct,ctt;
namespace work2
{
const int N=125;
int num,st[N],ed[N],stx,sty,ans;
int f[N][N][N],g[N][N][N],stt[N][N],edd[N][N],a[N][N];
void sp(int x,int y){for(int i=0;i<=num;i++)swap(a[x][i],a[y][i]);}
inline void add(int &x,int y){x+=y;if(x>=mod)x-=mod;}
inline int md(int x){if(x>=mod)return x-mod;return x;}
int gauss()
{
int ans=1;
for(int i=0;i<=num;i++)
{
if(!a[i][i])for(int j=i+1;j<=num;j++)if(a[j][i]){sp(i,j),ans=md(mod-ans);break;}
if(!a[i][i])return 0;ans=1ll*ans*a[i][i]%mod;
int temp=power(a[i][i],mod-2);
for(int j=i+1;j<=num;j++)
{
int now=1ll*a[j][i]*temp%mod;
for(int l=i;l<=num;l++)a[j][l]=(a[j][l]-1ll*a[i][l]*now%mod+mod)%mod;
}
}
return ans;
}
bool vis[N][N];
void dfs1(int step)
{
if(step==num+1)
{
int mx=0;
for(int i=0;i<=num;i++)mx=max(mx,ed[i]);
// if(ct%10000==0)cout<<ct<<endl;
for(int i=0;i<=num;i++)for(int j=0;j<=num;j++)a[i][j]=0;
int edx=0,edy=0;
edx=(n%k==0?k:n%k),edy=ed[num];
for(int i=1;i<=num;i++)st[i]=ed[i-1]-k/2;
for(int i=1;i<num;i++)if(st[i]>ed[i] || ed[i]-st[i]>k)return ;
if(sty>ed[0])return ;if(st[num]>edy)return ;
if(ed[0]-sty>k-stx)return ;if(edy-st[num]>edx)return ;
// printf("st:(%d,%d) ",stx,sty);
// for(int i=1;i<=num;i++)printf("(%d,%d) ",0,st[i]);printf("\n");
// printf("ed:");
// for(int i=0;i<num;i++)printf("(%d,%d) ",k,ed[i]);printf("(%d,%d) \n",edx,edy);
for(int j=0;j<=k;j++)for(int l=0;l<=mx;l++)edd[j][l]=0;
if(!vis[edx][edy])edd[edx][edy]=1;
for(int j=edx;j>=0;j--)for(int l=edy;l>=0;l--)if(edd[j][l])
{
if(j>0)add(edd[j-1][l],edd[j][l]);
if(j>0 && l>0)add(edd[j-1][l-1],edd[j][l]);
}
for(int i=1;i<=num;i++)for(int j=0;j<num;j++)if(st[i]<=ed[j])
{
int res=f[st[i]][k][ed[j]];
for(int l=0;l<edx;l++)res=(res-1ll*f[st[i]][l][edy]*g[ed[j]][l+1][edy+1]%mod+mod)%mod;
a[i][j]=res;
}else a[i][j]=0;
for(int j=0;j<num;j++)if(sty<=ed[j])
{
int res=stt[k][ed[j]];
for(int l=0;l<edx;l++)res=(res-1ll*stt[l][edy]*g[ed[j]][l+1][edy+1]%mod+mod)%mod;
a[0][j]=res;
}else a[0][j]=0;
for(int i=1;i<=num;i++)if(st[i]<=edy)
{
int res=edd[0][st[i]];
a[i][num]=res;
}
a[0][num]=edd[stx][sty];
// int now=ans;
ans=(ans+gauss())%mod;
// ct++;
// if(ans!=now)ctt++;
return ;
}
if(!step)for(int i=k/2+1;i<=k;i++)ed[step]=i,dfs1(step+1),ed[step]=0;
else if(step<num)for(int i=ed[step-1]+1;i<=ed[step-1]+k/2;i++)ed[step]=i,dfs1(step+1),ed[step]=0;
else for(int i=ed[step-1]-k/2;i<=ed[step-1]+k/2;i++)ed[step]=i,dfs1(step+1),ed[step]=0;
}
void init()
{
for(int i=0;i<=k;i++)for(int j=0;j<=n;j++)vis[i][j]=0;
for(int i=0;i<=n;i++)for(int j=0;j<=k;j++)for(int l=0;l<=n;l++)f[i][j][l]=g[i][j][l]=0;
int ax=0,ay=0;
for(int i=1;i<=m;i++)
{
vis[ax][ay]=1;
if(s[i]=='1')ax++,ay++;
else ax++;
}
stx=ax,sty=ay;
for(int i=0;i<=n;i++)
{
if(vis[0][i])continue;
f[i][0][i]=1;
for(int j=0;j<=k;j++)for(int l=0;l<=n;l++)if(f[i][j][l])
{
if(j<k && !vis[j+1][l])f[i][j+1][l]=(f[i][j+1][l]+f[i][j][l])%mod;
if(j<k && l<n && !vis[j+1][l+1])f[i][j+1][l+1]=(f[i][j+1][l+1]+f[i][j][l])%mod;
}
}
for(int i=0;i<=n;i++)
{
if(vis[k][i])continue;
g[i][k][i]=1;
for(int j=k;j>=0;j--)for(int l=n;l>=0;l--)if(g[i][j][l])
{
if(j>0 && !vis[j-1][l])g[i][j-1][l]=(g[i][j-1][l]+g[i][j][l])%mod;
if(j>0 && l>0 && !vis[j-1][l-1])g[i][j-1][l-1]=(g[i][j-1][l-1]+g[i][j][l])%mod;
}
}
for(int i=0;i<=k;i++)for(int j=0;j<=n;j++)stt[i][j]=0;
if(!vis[stx][sty])stt[stx][sty]=1;
for(int j=0;j<=k;j++)for(int l=0;l<=n;l++)if(stt[j][l])
{
if(j<k)stt[j+1][l]=(stt[j+1][l]+stt[j][l])%mod;
if(j<k && l<n)stt[j+1][l+1]=(stt[j+1][l+1]+stt[j][l])%mod;
}
}
void solve()
{
num=(n-1)/k;
// cout<<num<<endl;
init();
dfs1(0);
s=t,stx=sty=0;
for(int i=0;i<=num;i++)st[i]=ed[i]=0;
init();
dfs1(0);
printf("%d\n",ans);
}
}
int main()
{
// int time_st=clock();
// freopen("imbalance.in","r",stdin);
// freopen("imbalance.out","w",stdout);
scanf("%d %d %d",&n,&k,&m);
assert(m==0);
cin>>s,t=s,reverse(s.begin(),s.end()),s=' '+s,t=' '+t;
// work2::solve();
if(k<=20)work1::solve();
else work2::solve();
// cerr<<(clock()-time_st)/1e6<<endl;
// cerr<<ct<<endl;
// cerr<<ctt<<endl;
return 0;
}
詳細信息
Subtask #1:
score: 0
Runtime Error
Test #1:
score: 10
Accepted
time: 0ms
memory: 8960kb
input:
2 2 0
output:
2
result:
ok 1 number(s): "2"
Test #2:
score: -10
Runtime Error
input:
2 2 1 0
output:
result:
Subtask #2:
score: 0
Skipped
Dependency #1:
0%
Subtask #3:
score: 0
Skipped
Dependency #1:
0%
Subtask #4:
score: 0
Time Limit Exceeded
Test #137:
score: 20
Accepted
time: 331ms
memory: 8640kb
input:
114 20 0
output:
849724285
result:
ok 1 number(s): "849724285"
Test #138:
score: -20
Time Limit Exceeded
input:
114 22 0
output:
result:
Subtask #5:
score: 0
Skipped
Dependency #2:
0%