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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#397922#5434. Binary SubstringsqwqUwU_WA 9ms12076kbC++172.1kb2024-04-24 19:56:492024-04-24 19:56:49

Judging History

你现在查看的是最新测评结果

  • [2024-04-24 19:56:49]
  • 评测
  • 测评结果:WA
  • 用时:9ms
  • 内存:12076kb
  • [2024-04-24 19:56:49]
  • 提交

answer

// clang-format off
#include<bits/stdc++.h>
#define pb push_back
#define P make_pair
#define fi first
#define se second
#define bit(s,x) (((s)>>(x))&1)
#define pnp(s) __builtin_popcountll(s)
#define rep(i,a,b) for(int i=(a);i<=(b);++i)
#define per(i,a,b) for(int i=(a);i>=(b);--i)
using namespace std;
mt19937 gen(time(0));
typedef long long ll; 
typedef unsigned long long ull; 
typedef pair<int,int> pii; typedef pair<ll,int> pli; typedef pair<ll,ll> pll; typedef pair<int,ll> pil;
inline ll read(){
	ll x=0,f=1,c=getchar();
	while(c<'0'||c>'9')f=(c=='-'?-1:1),c=getchar();
	while(c>='0'&&c<='9')x=(x<<1)+(x<<3)+(c^48),c=getchar();
	return x*f;
}
const int mod=998244353;
inline int fp(int x,ll p=mod-2,int m=mod,int res=1){
	for(;p;p>>=1){if(p&1)res=1ll*res*x%m;x=1ll*x*x%m;}
	return res;
}
inline void plust(int &x,int y){x=x+y>=mod?x+y-mod:x+y;}
const int N=2e5+3;
// clang-format on
int n,m,a[N],tot,lim;
bool vis[N][2];
inline void check(){
	if(tot>lim)return;
	rep(i,1,n)printf("%d",a[i]);
	exit(0);
}
inline void dfs(int u){
	check();
	if(!vis[u][0]){
		vis[u][0]=1;
		dfs((u<<1|0)&((1<<(m-1))-1));
		a[tot--]=0;
		check();
	}
	if(!vis[u][1]){
		vis[u][1]=1;
		dfs((u<<1|1)&((1<<(m-1))-1));
		a[tot--]=1;
		check();
	}
}
int b[N<<1];
inline void dfs2(int u){
	if(!vis[u][0]){
		vis[u][0]=1;
		dfs2((u<<1|0)&((1<<m)-1));
		b[tot--]=0;
	}
	if(!vis[u][1]){
		vis[u][1]=1;
		dfs2((u<<1|1)&((1<<m)-1));
		b[tot--]=1;
	}
}
int main() {
    //freopen("data.in", "r", stdin);
    // freopen(".in","r",stdin);
    // freopen("myans.out","w",stdout);
	n=read();
	if(n==1){puts("1");return 0;}
	if(n==2){puts("01");return 0;}
	for(;(1<<m)+m-1<=n;++m);--m;
	tot=(1<<m)+m-1;
	dfs(0);//vertex :2^{m-1},edge :2^m
	lim=(1<<m)+m-1;
	//cout<<m<<endl;
	//rep(i,1,tot)printf("%d",a[i]);
	memset(vis,0,sizeof vis);
	rep(i,1,(1<<m)-1){
		int u=0;
		rep(j,i,i+m-1)u=(u<<1)|a[j];
		vis[u][a[i+m]]=1;
	}
	tot=(N<<1)-1;
	int u=0;
	rep(j,(1<<m),(1<<m)+m-1)u=(u<<1)|a[j];
	dfs2(u);
	rep(i,1,lim)printf("%d",a[i]);
	int k=(N<<1)-1;
	rep(i,tot+1,tot+n-lim)printf("%d",b[i]);
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3768kb

input:

2

output:

01

result:

ok meet maximum 3

Test #2:

score: 0
Accepted
time: 0ms
memory: 4220kb

input:

5

output:

00110

result:

ok meet maximum 12

Test #3:

score: 0
Accepted
time: 0ms
memory: 3828kb

input:

1

output:

1

result:

ok meet maximum 1

Test #4:

score: 0
Accepted
time: 0ms
memory: 3896kb

input:

3

output:

010

result:

ok meet maximum 5

Test #5:

score: 0
Accepted
time: 0ms
memory: 3892kb

input:

4

output:

0100

result:

ok meet maximum 8

Test #6:

score: 0
Accepted
time: 1ms
memory: 5952kb

input:

6

output:

001101

result:

ok meet maximum 16

Test #7:

score: 0
Accepted
time: 1ms
memory: 4284kb

input:

7

output:

0011010

result:

ok meet maximum 21

Test #8:

score: 0
Accepted
time: 0ms
memory: 4408kb

input:

8

output:

00110100

result:

ok meet maximum 27

Test #9:

score: 0
Accepted
time: 0ms
memory: 4296kb

input:

9

output:

001101000

result:

ok meet maximum 34

Test #10:

score: 0
Accepted
time: 1ms
memory: 4348kb

input:

10

output:

0001011100

result:

ok meet maximum 42

Test #11:

score: 0
Accepted
time: 0ms
memory: 5920kb

input:

11

output:

00010111001

result:

ok meet maximum 50

Test #12:

score: 0
Accepted
time: 1ms
memory: 4348kb

input:

12

output:

000101110011

result:

ok meet maximum 59

Test #13:

score: -100
Wrong Answer
time: 9ms
memory: 12076kb

input:

200000

output:

000000000000000001000000000000000110000000000000010100000000000000111000000000000010010000000000000101100000000000001101000000000000011110000000000001000100000000000010011000000000000101010000000000001011100000000000011001000000000000110110000000000001110100000000000011111000000000001000010000000000...

result:

wrong answer Token parameter [name=s] equals to "000000000000000001000000000000...0000000000000000000000000000000", doesn't correspond to pattern "[01]{200000}"