// Author: Minghan Ye (Donotplaygame)
// Name: L. Exchanging Kubic
// URL: https://qoj.ac/contest/1596/problem/8553
// ML: 1024 MB
// TL: 1000 ms
// 
// Powered by CP Editor (https://cpeditor.org)

#include<bits/stdc++.h>
using namespace std;
#ifdef DEBUG
#include "E:/OI/normal/templates/debug.h"
#else
#define dbg(...) (void)0
#define msg(...) (void)0
#endif
#define ll long long
#define PB emplace_back
#define PPB pop_back
#define MP make_pair
#define ALL(Name) Name.begin(),Name.end()
#define PII pair<int,int>
#define VI vector<int>
#define fi first
#define se second

const int N=2005;
int n;
ll a[N],sm[N];
ll ask(int l,int r)
{
	cout<<"? "<<l<<" "<<r<<endl;
	ll res;cin>>res;
	return res;
}
void answer()
{
	cout<<"!";
	for(int i=1;i<=n;i++)cout<<" "<<a[i];
	cout<<endl;
}
void upd()
{
	for(int i=1;i<=n;i++)sm[i]=sm[i-1]+a[i];
}
ll sum(int l,int r){return sm[r]-sm[l-1];}

int main()
{
	ios::sync_with_stdio(false),cin.tie(nullptr);
	int _;cin>>_;while(_--)
{
	cin>>n;
	for(int i=1;i<=n;i++)a[i]=ask(i,i);
	vector<PII> p;
	for(int i=1,lst=0;i<=n+1;i++)
		if(a[i]>0)
		{
			if(!lst)lst=i;
		}
		else
		{
			if(lst)p.PB(lst,i-1);
			lst=0;
		}
	while(p.size()>1)
	{
//		cerr<<"p = [";
//		for(int i=0;i<p.size();i++)fprintf(stderr,"(%d, %d)%s",p[i].fi,p[i].se,i+1==p.size()?"]\n":", ");
		upd();
		vector<PII>::iterator it;
		for(auto i=p.begin();i!=p.end();i++)
			if(i==p.begin()||sum(i->fi,i->se)<sum(it->fi,it->se))it=i;
		if(it!=p.begin())
		{
			ll t=ask((it-1)->fi,it->se),s=sum((it-1)->fi,(it-1)->se),u=s+sum(it->fi,it->se);
			if(t>s)
			{
				a[it->fi-1]=t-u;
				for(int i=(it-1)->se+1;i<it->fi-1;i++)a[it->fi-1]-=a[i];
				int st=(it-1)->fi,ed=it->se;
				p.emplace(p.erase(it-1,it+1),st,ed);
				continue;
			}
		}
		if(it+1!=p.end())
		{
			ll t=ask(it->fi,(it+1)->se),s=sum((it+1)->fi,(it+1)->se),u=s+sum(it->fi,it->se);
			if(t>s)
			{
				a[it->se+1]=t-u;
				for(int i=it->se+2;i<(it+1)->fi;i++)a[it->se+1]-=a[i];
				int st=it->fi,ed=(it+1)->se;
				p.emplace(p.erase(it,it+2),st,ed);
				continue;
			}
		}
		a[it->fi-1]=a[it->se+1]=-sum(it->fi,it->se);
		p.erase(it);
	}
	answer();
}

	return 0;
}