QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#389131 | #6705. Median | Mayuri | AC ✓ | 0ms | 3988kb | C++20 | 1.3kb | 2024-04-14 02:54:24 | 2024-04-14 02:54:25 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
#define endl '\n'
const ll maxn = 100 + 5;
ll T;
ll n, m;
vector<ll>to[maxn];
vector<ll>to2[maxn];
ll sz[maxn];
ll sz2[maxn];
bool vis[maxn];
void dfs(ll u, ll s) {
if (vis[u]) return;
vis[u] = true;
sz[s]++;
sz2[u]++;
for (auto v : to[u]) {
dfs(v, s);
}
}
ll in[maxn];
bool topu() {
queue<ll>q;
for (ll i = 1; i <= n; i++)if (!in[i])
q.push(i);
while (!q.empty()) {
ll u = q.front();
q.pop();
for (auto v : to[u]){
in[v]--;
if (!in[v])
q.push(v);
}
}
for (ll i = 1; i <= n; i++)if (in[i])
return false;
return true;
}
int main()//H
{
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> T;
while (T--) {
for (ll i = 1; i <= n; i++)sz[i] = sz2[i] = in[i] = 0,to[i].clear(), to2[i].clear();
cin >> n >> m;
for (ll i = 1; i <= m; i++) {
ll a, b; cin >> a >> b;
to[a].push_back(b);
in[b]++;
}
if (topu()) {
for (ll i = 1; i <= n; i++) {
memset(vis, false, sizeof(vis));
dfs(i, i);
}
for (ll i = 1; i <= n; i++) {
if (sz[i] - 1 <= n / 2 && sz2[i] - 1 <= n / 2)cout << 1;
else cout << 0;
}
cout << endl;
}
else{
for (ll i = 1; i <= n; i++) {
cout << 0;
}
cout << endl;
}
}
}
这程序好像有点Bug,我给组数据试试?
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3684kb
input:
2 5 4 1 2 3 2 2 4 2 5 3 2 1 1 2 3
output:
01000 000
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 0ms
memory: 3988kb
input:
66 13 2 9 13 7 11 11 19 9 1 8 1 5 1 2 8 4 2 2 1 5 2 6 3 3 11 3 2 4 6 6 10 9 8 3 5 1 7 5 8 3 9 4 9 6 7 3 1 2 3 11 6 9 4 1 6 5 2 1 5 4 6 8 4 15 15 10 6 15 8 7 6 11 1 5 2 3 4 11 13 4 6 10 12 10 13 1 6 15 2 5 12 13 14 5 3 15 86 14 12 8 1 14 9 8 15 5 10 1 9 11 2 6 2 7 10 10 13 14 5 4 13 5 8 4 10 13 9 6 9...
output:
1111111111111 01001000111 111 11111111111 111111111111111 001001000000000 00100 01100 1111111 1000000000000 111101101 111111111 000011111011101 010111111 001100000 0100001001101 1111111111111 001000010000000 10010111011 001000000000100 11111111111 00100000011 11111 01000000110 11101110111 00000 1111...
result:
ok 66 lines