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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#388788#4884. Battleship: New RulesunputdownableML 3ms3676kbC++173.0kb2024-04-13 19:45:232024-04-13 19:45:24

Judging History

你现在查看的是最新测评结果

  • [2024-04-13 19:45:24]
  • 评测
  • 测评结果:ML
  • 用时:3ms
  • 内存:3676kb
  • [2024-04-13 19:45:23]
  • 提交

answer

#include <bits/stdc++.h>
// #define int long long
#define i64 long long
#define pii pair <int, int> 
using namespace std;
int n,Ax,Ay,Bx,By;
inline void Answer(int x,int y) {
    cout<<"! "<<x<<' '<<y<<endl;
    int res; cin>>res;
    if(res==-1) exit(0);
}
inline int qry(int x,int y) {
    cout<<"? "<<x<<' '<<y<<endl;
    int res; cin>>res;
    if(res==-1) exit(0);
    return res;
}
#define lch (x<<1)
#define rch (x<<1|1)
inline void chkmin(int&x,int y) { x=min(x,y); }
inline void chkmax(int&x,int y) { x=max(x,y); }
struct segtree {
    int lzy[2003];
    void init(int n,int v) { for(int i=0; i<=4*n; ++i) lzy[i]=v; }
    void upd(int x,int l,int r,const int ql,const int qr,const int v,const auto f) {
        if(ql<=l&&r<=qr) return f(lzy[x],v),void();
        int mid=(l+r)>>1;
        if(ql<=mid) upd(lch,l,mid,ql,qr,v,f);
        if(qr> mid) upd(rch,mid+1,r,ql,qr,v,f); 
    }
    int qry(int x,int l,int r,const int q,const auto f) {
        if(l==r) return assert(l==q),lzy[x];
        int mid=(l+r)>>1;
        if(q<=mid) return f(lzy[x],qry(lch,l,mid,q,f));
        else return f(lzy[x],qry(rch,mid+1,r,q,f));
    }
} L,R;
mt19937 rnd(191182396859681231);
int rev[4003];
pii pos[1000006];
inline void dfs(int x,int l,int r) {
    int mid=(l+r)>>1; rev[x]=mid;
    if(l<mid) dfs(lch,l,mid-1);
    if(r>mid) dfs(rch,mid+1,r);
}
inline void work() {
    int lim;
    cin>>n; lim=6*n;
    if(n&1) return Answer(-1,-1),void();
    n=n/2-1;
    int cnt=0;
    auto Max=[&](int x,int y){return x>y ? x : y;};
    auto Min=[&](int x,int y){return x<y ? x : y;};
    // dfs(1,1,n);
    // int ccc=0;
    // for(int i=1; i<=4*n; ++i) if(rev[i]) rev[++ccc]=rev[i];
    // for(int i=1; i<=n; ++i) {
    //     pos[++cnt]=make_pair(rev[i],rev[i]);
    //     for(int u=1; u<i; ++u) {
    //         pos[++cnt]=make_pair(rev[i],rev[u]);
    //         pos[++cnt]=make_pair(rev[u],rev[i]);
    //     }
    // } 
    for(int i=1; i<=n; ++i) {
        for(int u=1; u<=n; ++u) {
            pos[++cnt]=make_pair(i,u);
        }
    }
    for(int i=2; i<=cnt; ++i) swap(pos[i],pos[rnd()%i+1]);
    assert(cnt==n*n);
    L.init(n,0);
    R.init(n,n+1);
    int cntq=0;
    for(int i=1; i<=cnt; ++i) {
        int A,B,C,D,x=pos[i].first,y=pos[i].second;
        if(L.qry(1,1,n,x,Max)>=y&&y>=R.qry(1,1,n,x,Min)) continue;  
        if(cntq==lim) return Answer(x<<1,y<<1),void();
        A=qry(x*2,y*2),B=qry(x*2,y*2+1);
        C=qry(x*2+1,y*2),D=qry(x*2+1,y*2+1); cntq+=4;
        if(A==0&&B==0&&C==0&&D==0) return Answer(x<<1,y<<1),void();
        if(A) R.upd(1,1,n,x+1,n,y+1,chkmin);
        if(B) L.upd(1,1,n,x+1,n,y-1,chkmax);
        if(C) R.upd(1,1,n,1,x-1,y+1,chkmin);
        if(D) L.upd(1,1,n,1,x-1,y-1,chkmax);
    }
    exit(-1);
}
signed main() {
    // freopen("localinput","r",stdin);
    // freopen("localoutput","w",stdout);
    ios::sync_with_stdio(0);
    int T; cin>>T;
    while(T--) work();
    // fprintf(stderr,"%.4lf\n",1.0*clock()/CLOCKS_PER_SEC);
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3676kb

input:

2
3
1
4
0
0
0
0
1

output:

! -1 -1
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2

result:

ok max_C=1.00, avg_C=0.50 (2 test cases)

Test #2:

score: 0
Accepted
time: 3ms
memory: 3624kb

input:

100
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
0
1
4
0
0
0
...

output:

? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
? 2 2
? 2 3
? 3 2
? 3 3
! 2 2
...

result:

ok max_C=1.00, avg_C=1.00 (100 test cases)

Test #3:

score: -100
Memory Limit Exceeded

input:

100
10
1
1
0
0
1
0
0
0
0
0
1
0

output:

? 8 4
? 8 5
? 9 4
? 9 5
? 8 8
? 8 9
? 9 8
? 9 9
? 2 6
? 2 7
? 3 6
? 3 7

result: