QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#386499#7782. Ursa MinorA_programmerML 131ms19332kbC++174.3kb2024-04-11 17:32:582024-04-11 17:32:59

Judging History

你现在查看的是最新测评结果

  • [2024-04-11 17:32:59]
  • 评测
  • 测评结果:ML
  • 用时:131ms
  • 内存:19332kb
  • [2024-04-11 17:32:58]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
const ll mod = 1e9 + 7;
const ll Base = 13131;
const int B = 455;
const int maxn = 2e5 + 5;

int a[maxn], b[maxn], f[maxn][18], lg[maxn];
inline int gcd(int a, int b) { return b ? gcd(b, a % b) : a; }
int query(int l, int r)
{
    int k = lg[r - l + 1];
    return gcd(f[l][k], f[r - (1 << k) + 1][k]);
}

ll fpow(ll a, ll b)
{
    ll ans = 1;
    while (b)
    {
        if (b & 1) ans = ans * a % mod;
        a = a * a % mod;
        b >>= 1;
    }
    return ans;
}

ll mi[maxn], inv[maxn], pre[maxn], iBase;
int bs, bn, bl[B], br[B], bel[maxn];

struct ds1 // O(1) query to O(sqrt(n)) update  a_i * x^i
{
    ll c[maxn], tag[B];
    void add(int pos, ll x)
    {
        for (int i = 1; i < bel[pos]; i++) (tag[i] += x) %= mod;
        for (int i = bl[bel[pos]]; i <= pos; i++) (c[i] += x) %= mod;
    }
    ll sum(int pos) { return (c[pos] + tag[bel[pos]]) % mod; }
}ds1;

struct ds2 // O(sqrt(n)) query to O(1) update a_i * x^(i % k)
{
    ll c[maxn], sum[B];
    ll d[maxn], sud[B];
    void add(int pos, ll x) { (c[pos] += x) %= mod; (sum[bel[pos]] += x) %= mod; }
    void addD(int pos, ll x) { (d[pos] += x) %= mod; (sud[bel[pos]] += x) %= mod; }
    ll sumP(int pos)
    {
        ll ans = 0;
        for (int i = 1; i < bel[pos]; i++) (ans += sum[i]) %= mod;
        for (int i = bl[bel[pos]]; i <= pos; i++) (ans += c[i]) %= mod;
        return ans;
    }
    ll sumD(int pos)
    {
        ll ans = 0;
        for (int i = 1; i < bel[pos]; i++) (ans += sud[i]) %= mod;
        for (int i = bl[bel[pos]]; i <= pos; i++) (ans += d[i]) %= mod;
        return ans;
    }
}ds2[B];

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    
    int n, m, q;
    cin >> n >> m >> q;
    mi[0] = inv[0] = pre[0] = 1; iBase = fpow(Base, mod - 2);
    for (int i = 1; i <= n; i++) mi[i] = mi[i - 1] * Base % mod, pre[i] = (pre[i - 1] + mi[i]) % mod;
    for (int i = 1; i <= n; i++) inv[i] = inv[i - 1] * iBase % mod;
    for (int i = 1; i <= n; i++) cin >> a[i];
    for (int i = 1, k = 0; i <= m; i++)
    {
        cin >> b[i], f[i][0] = b[i];
        lg[i] = k;
        if (i == (1 << (k + 1))) lg[i] = ++k;
    }
    for (int j = 1; j <= 17; j++)
        for (int i = 1; i + (1 << j) - 1 <= m; i++)
            f[i][j] = gcd(f[i][j - 1], f[i + (1 << (j - 1))][j - 1]);
    
    bs = (int)sqrt(n);
    for (int i = 1; i <= n; i += bs)
        bl[++bn] = i, br[bn] = i + bs - 1;
    br[bn] = n;
    for (int i = 1; i <= bn; i++)
        for (int j = bl[i]; j <= br[i]; j++) bel[j] = i;
    
    for (int i = 1; i <= n; i++)
    {
        for (int j = 1; j <= bs; j++)
        {
            ds2[j].add(i, a[i] * mi[i % j] % mod);
            if (i % j == 0) ds2[j].addD(i, a[i]);
        }
        ds1.add(i, a[i] * mi[i] % mod);
    }

    while (q--)
    {
        char s[4];
        cin >> s;
        if (s[0] == 'U')
        {
            int pos;
            ll v;
            cin >> pos >> v;
            v = (v + mod - a[pos]) % mod;
            for (int i = 1; i <= bs; i++)
            {
                ds2[i].add(pos, v * mi[pos % i] % mod);
                if (pos % i == 0) ds2[i].addD(pos, v);
            }
            ds1.add(pos, v * mi[pos] % mod);
            (a[pos] += v) %= mod;
        }
        else
        {
            int l, r, s, t;
            cin >> l >> r >> s >> t;
            int k = gcd(r - l + 1, query(s, t));
            ll hsh = 0, hs2 = 0;
            if (k <= bs)
            {
                hsh = ds2[k].sumP(r) - ds2[k].sumP(l - 1);
                hs2 = ds2[k].sumD(r) - ds2[k].sumD(l - 1);
                if (hsh < 0) hsh += mod;
                if (hs2 < 0) hs2 += mod;
            }
            else
            {
                for (int i = l; i <= r; i += k) (hs2 += a[i]) %= mod;
                for (int i = l / k; i <= r / k; i++)
                {
                    int L = i * k, R = L + k - 1;
                    L = max(L, l), R = min(R, r);
                    ll res = (ds1.sum(r) + mod - ds1.sum(l - 1)) * inv[i * k] % mod;
                    (hsh += res) %= mod;
                }
            }
            (hs2 *= pre[k - 1]) %= mod;
            cout << (hsh == hs2 ? "Yes\n" : "No\n");
        }
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3736kb

input:

6 4 5
1 1 4 5 1 4
3 3 2 4
Q 1 5 1 2
Q 2 5 3 4
U 5 2
Q 1 6 1 2
Q 2 5 3 4

output:

Yes
No
No
Yes

result:

ok 4 tokens

Test #2:

score: 0
Accepted
time: 1ms
memory: 3768kb

input:

1 1 1
0
1
Q 1 1 1 1

output:

Yes

result:

ok "Yes"

Test #3:

score: 0
Accepted
time: 131ms
memory: 6108kb

input:

2000 2000 200000
1 1 2 0 0 2 0 2 0 0 0 0 0 2 2 1 2 0 0 2 2 2 1 0 1 2 1 2 0 0 1 1 1 2 0 0 2 2 2 2 0 2 0 0 2 1 2 0 0 1 2 2 1 0 2 0 0 0 1 2 2 1 2 2 0 0 1 1 1 0 0 2 0 0 1 1 0 2 2 2 1 0 0 1 0 1 2 2 2 1 1 2 2 1 2 1 0 2 2 3 1 3 2 3 1 0 1 2 0 1 1 1 0 2 2 3 2 0 3 2 3 3 1 2 3 1 2 0 1 0 3 1 0 0 2 0 1 2 1 3 2 2...

output:

Yes
Yes
No
Yes
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
No
Yes
Yes
No
No
No
No
No
Yes
No
No
No
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
No
Yes
Yes
Yes
No
No
Yes
No
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
No...

result:

ok 100554 tokens

Test #4:

score: 0
Accepted
time: 58ms
memory: 19332kb

input:

1 200000 200000
998244353
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

output:

Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
...

result:

ok 100240 tokens

Test #5:

score: 0
Accepted
time: 38ms
memory: 14104kb

input:

6 131072 200000
0 0 0 0 1000000000 1000000000
4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 ...

output:

Yes
Yes
Yes
No
No
No
Yes
No
No
No
No
No
Yes
Yes
No
Yes
No
Yes
Yes
Yes
No
No
No
No
No
No
No
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
No
No
No
Yes
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
Yes
Yes
No
Yes
N...

result:

ok 100021 tokens

Test #6:

score: -100
Memory Limit Exceeded

input:

200000 200000 200000
490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877...

output:

No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
Yes
Yes
Yes
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
Yes
Yes
No
No
No
No
No
No
No
No
N...

result: