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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#384735#6846. Wiring Engineeringyaoxi_stdTL 0ms9744kbC++1410.3kb2024-04-10 11:33:532024-04-10 11:33:53

Judging History

你现在查看的是最新测评结果

  • [2024-04-10 11:33:53]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:9744kb
  • [2024-04-10 11:33:53]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
#define debug(fmt, ...) \
  fprintf(stderr, "[%d] " fmt "\n", __LINE__, ##__VA_ARGS__)
template <class _Tx, class _Ty>
inline void chkmin(_Tx& x, const _Ty& y) { if (y < x) x = y; }
template <class _Tx, class _Ty>
inline void chkmax(_Tx& x, const _Ty& y) { if (x < y) x = y; }
bool Mbe;
using ll = long long;
constexpr int N = 505, Q = 3e5 + 10;
int n, q, a[N], b[N], w[N][N], dpl[N][N][2][2][2][2], dpr[N][N][2][2][2][2], ans[Q];
vector<tuple<int, int, int, int, int>> qrya[N], qryb[N];
void solve(int la, int ra, int lb, int rb, bool typ) {
  if (la > ra || lb > rb) return;
  if (!typ) {
    int mid = (la + ra) >> 1;
    vector<tuple<int, int, int, int, int>> qry;
    for (int i = la; i <= mid; ++i) {
      for (auto it : qrya[i]) {
        int qla, qra, qlb, qrb, id;
        tie(qla, qra, qlb, qrb, id) = it;
        if (mid <= qra && qra <= ra && lb <= qlb && qrb <= rb) qry.push_back(it);
      }
    }
    for (int i = lb; i <= rb; ++i) {
      memset(dpl[mid][i], -0x3f, sizeof(dpl[mid][i]));
      dpl[mid][i][0][0][0][0] = 0;
      dpl[mid][i][0][1][0][1] = -b[i];
      dpl[mid][i][1][0][1][0] = -a[mid];
      dpl[mid][i][1][1][1][1] = w[mid][i] - (a[mid] + b[i]);
      for (int j = mid; j >= la; --j) {
        for (int k = i; k >= lb; --k) {
          if (j != mid || k != i) memset(dpl[j][k], -0x3f, sizeof(dpl[j][k]));
          if (j < mid) {
            for (int x = 0; x < 2; ++x) {
              for (int y = 0; y < 2; ++y) {
                for (int p = 0; p < 2; ++p) {
                  for (int q = 0; q < 2; ++q) {
                    chkmax(dpl[j][k][0][y][p][q],
                           dpl[j + 1][k][x][y][p][q]);
                    chkmax(dpl[j][k][1][1][p][q],
                           dpl[j + 1][k][x][y][p][q] - a[j] - (!y ? b[k] : 0) + w[j][k]);
                  }
                }
              }
            }
          }
          if (k < i) {
            for (int x = 0; x < 2; ++x) {
              for (int y = 0; y < 2; ++y) {
                for (int p = 0; p < 2; ++p) {
                  for (int q = 0; q < 2; ++q) {
                    chkmax(dpl[j][k][x][0][p][q],
                           dpl[j][k + 1][x][y][p][q]);
                    chkmax(dpl[j][k][1][1][p][q],
                           dpl[j][k + 1][x][y][p][q] - (!x ? a[j] : 0) - b[k] + w[j][k]);
                  }
                }
              }
            }
          }
          for (int x = 0; x < 2; ++x) {
            for (int y = 0; y < 2; ++y) {
              for (int p = 0; p < 2; ++p) {
                for (int q = 0; q < 2; ++q) {
                  chkmax(dpl[j][k][0][0][p][q], dpl[j][k][x][y][p][q]);
                }
              }
            }
          }
        }
      }
      memset(dpr[mid][i], -0x3f, sizeof(dpr[mid][i]));
      dpr[mid][i][0][0][0][0] = 0;
      dpr[mid][i][0][1][0][1] = -b[i];
      dpr[mid][i][1][0][1][0] = -a[mid];
      dpr[mid][i][1][1][1][1] = w[mid][i] - (a[mid] + b[i]);
      for (int j = mid; j <= ra; ++j) {
        for (int k = i; k <= rb; ++k) {
          if (j != mid || k != i) memset(dpr[j][k], -0x3f, sizeof(dpr[j][k]));
          if (j > mid) {
            for (int x = 0; x < 2; ++x) {
              for (int y = 0; y < 2; ++y) {
                for (int p = 0; p < 2; ++p) {
                  for (int q = 0; q < 2; ++q) {
                    chkmax(dpr[j][k][0][y][p][q],
                           dpr[j - 1][k][x][y][p][q]);
                    chkmax(dpr[j][k][1][1][p][q],
                           dpr[j - 1][k][x][y][p][q] - a[j] - (!y ? b[k] : 0) + w[j][k]);
                  }
                }
              }
            }
          }
          if (k > i) {
            for (int x = 0; x < 2; ++x) {
              for (int y = 0; y < 2; ++y) {
                for (int p = 0; p < 2; ++p) {
                  for (int q = 0; q < 2; ++q) {
                    chkmax(dpr[j][k][x][0][p][q],
                           dpr[j][k - 1][x][y][p][q]);
                    chkmax(dpr[j][k][1][1][p][q],
                           dpr[j][k - 1][x][y][p][q] - (!x ? a[j] : 0) - b[k] + w[j][k]);
                  }
                }
              }
            }
          }
          for (int x = 0; x < 2; ++x) {
            for (int y = 0; y < 2; ++y) {
              for (int p = 0; p < 2; ++p) {
                for (int q = 0; q < 2; ++q) {
                  chkmax(dpr[j][k][0][0][p][q], dpr[j][k][x][y][p][q]);
                }
              }
            }
          }
        }
      }
      for (auto it : qry) {
        int qla, qra, qlb, qrb, id;
        tie(qla, qra, qlb, qrb, id) = it;
        if (qlb <= i && i <= qrb) {
          for (int x = 0; x < 2; ++x) {
            for (int y = 0; y < 2; ++y) {
              int val = dpl[qla][qlb][0][0][x][y] + dpr[qra][qrb][0][0][x][y];
              if (x) val += a[mid];
              if (y) val += b[i];
              if (x && y) val -= w[mid][i];
              chkmax(ans[id], val);
            }
          }
        }
      }
    }
    solve(la, mid - 1, lb, rb, !typ);
    solve(mid + 1, ra, lb, rb, !typ);
  } else {
    int mid = (lb + rb) >> 1;
    vector<tuple<int, int, int, int, int>> qry;
    for (int i = lb; i <= mid; ++i) {
      for (auto it : qryb[i]) {
        int qla, qra, qlb, qrb, id;
        tie(qla, qra, qlb, qrb, id) = it;
        if (mid <= qrb && qrb <= rb && la <= qla && qra <= ra) qry.push_back(it);
      }
    }
    for (int i = la; i <= ra; ++i) {
      memset(dpl[i][mid], -0x3f, sizeof(dpl[i][mid]));
      dpl[i][mid][0][0][0][0] = 0;
      dpl[i][mid][0][1][0][1] = -b[mid];
      dpl[i][mid][1][0][1][0] = -a[i];
      dpl[i][mid][1][1][1][1] = w[i][mid] - (a[i] + b[mid]);
      for (int j = i; j >= la; --j) {
        for (int k = mid; k >= lb; --k) {
          if (j != i && k != mid) memset(dpl[j][k], -0x3f, sizeof(dpl[j][k]));
          if (j < i) {
            for (int x = 0; x < 2; ++x) {
              for (int y = 0; y < 2; ++y) {
                for (int p = 0; p < 2; ++p) {
                  for (int q = 0; q < 2; ++q) {
                    chkmax(dpl[j][k][0][y][p][q],
                           dpl[j + 1][k][x][y][p][q]);
                    chkmax(dpl[j][k][1][1][p][q],
                           dpl[j + 1][k][x][y][p][q] - a[j] - (!y ? b[k] : 0) + w[j][k]);
                  }
                }
              }
            }
          }
          if (k < mid) {
            for (int x = 0; x < 2; ++x) {
              for (int y = 0; y < 2; ++y) {
                for (int p = 0; p < 2; ++p) {
                  for (int q = 0; q < 2; ++q) {
                    chkmax(dpl[j][k][x][0][p][q],
                           dpl[j][k + 1][x][y][p][q]);
                    chkmax(dpl[j][k][1][1][p][q],
                           dpl[j][k + 1][x][y][p][q] - (!x ? a[j] : 0) - b[k] + w[j][k]);
                  }
                }
              }
            }
          }
          for (int x = 0; x < 2; ++x) {
            for (int y = 0; y < 2; ++y) {
              for (int p = 0; p < 2; ++p) {
                for (int q = 0; q < 2; ++q) {
                  chkmax(dpl[j][k][0][0][p][q], dpl[j][k][x][y][p][q]);
                }
              }
            }
          }
        }
      }
      memset(dpr[i][mid], -0x3f, sizeof(dpr[i][mid]));
      dpr[i][mid][0][0][0][0] = 0;
      dpr[i][mid][0][1][0][1] = -b[mid];
      dpr[i][mid][1][0][1][0] = -a[i];
      dpr[i][mid][1][1][1][1] = w[i][mid] - (a[i] + b[mid]);
      for (int j = i; j <= ra; ++j) {
        for (int k = mid; k <= rb; ++k) {
          if (j != i && k != mid) memset(dpr[j][k], -0x3f, sizeof(dpr[j][k]));
          if (j > i) {
            for (int x = 0; x < 2; ++x) {
              for (int y = 0; y < 2; ++y) {
                for (int p = 0; p < 2; ++p) {
                  for (int q = 0; q < 2; ++q) {
                    chkmax(dpr[j][k][0][y][p][q],
                           dpr[j - 1][k][x][y][p][q]);
                    chkmax(dpr[j][k][1][1][p][q],
                           dpr[j - 1][k][x][y][p][q] - a[j] - (!y ? b[k] : 0) + w[j][k]);
                  }
                }
              }
            }
          }
          if (k > mid) {
            for (int x = 0; x < 2; ++x) {
              for (int y = 0; y < 2; ++y) {
                for (int p = 0; p < 2; ++p) {
                  for (int q = 0; q < 2; ++q) {
                    chkmax(dpr[j][k][x][0][p][q],
                           dpr[j][k - 1][x][y][p][q]);
                    chkmax(dpr[j][k][1][1][p][q],
                           dpr[j][k - 1][x][y][p][q] - (!x ? a[j] : 0) - b[k] + w[j][k]);
                  }
                }
              }
            }
          }
          for (int x = 0; x < 2; ++x) {
            for (int y = 0; y < 2; ++y) {
              for (int p = 0; p < 2; ++p) {
                for (int q = 0; q < 2; ++q) {
                  chkmax(dpr[j][k][0][0][p][q], dpr[j][k][x][y][p][q]);
                }
              }
            }
          }
        }
      }
      for (auto it : qry) {
        int qla, qra, qlb, qrb, id;
        tie(qla, qra, qlb, qrb, id) = it;
        if (qla <= i && i <= qra) {
          for (int x = 0; x < 2; ++x) {
            for (int y = 0; y < 2; ++y) {
              int val = dpl[qla][qlb][0][0][x][y] + dpr[qra][qrb][0][0][x][y];
              if (x) val += a[i];
              if (y) val += b[mid];
              if (x && y) val -= w[i][mid];
              chkmax(ans[id], val);
            }
          }
        }
      }
    }
    solve(la, mid - 1, lb, rb, !typ);
    solve(mid + 1, ra, lb, rb, !typ);
  }
}
bool Med;
int main() {
  // debug("Mem: %.4lfMB.", fabs(&Med - &Mbe) / 1048576);
  cin.tie(0)->sync_with_stdio(0);
  cin >> n >> q;
  for (int i = 1; i <= n; ++i) cin >> a[i];
  for (int i = 1; i <= n; ++i) cin >> b[i];
  for (int i = 1; i <= n; ++i) {
    for (int j = 1; j <= n; ++j) {
      cin >> w[i][j];
    }
  }
  for (int i = 1, la, ra, lb, rb; i <= q; ++i) {
    cin >> la >> ra >> lb >> rb;
    qrya[la].push_back({la, ra, lb, rb, i});
    qryb[lb].push_back({la, ra, lb, rb, i});
  }
  solve(1, n, 1, n, 0);
  for (int i = 1; i <= q; ++i) cout << ans[i] << '\n';
  return 0;
}
/*
g++ -std=c++14 -O2 -o G G.cpp -Wall -Wextra
-Wshadow -fsanitize=address,undefined -g
*/

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 9744kb

input:

3 4
1 2 1
2 1 2
1 2 3
4 5 6
3 2 1
1 3 1 3
2 3 1 2
1 1 2 3
1 2 2 3

output:

8
5
1
7

result:

ok 4 lines

Test #2:

score: -100
Time Limit Exceeded

input:

24 90000
8793 8115 9643 2814 6394 7070 3822 4788 6737 6506 2901 4772 5347 5050 3493 2803 584 2544 3834 678 9891 2958 5475 522
9057 3674 3163 6433 5937 8480 4815 1201 5509 1303 4151 8190 6229 9339 9765 3011 2256 3682 8442 3641 2268 5609 4948 9632
5872 4006 7690 2611 5381 6184 9483 8527 8248 960 8124 ...

output:


result: