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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#382171 | #6683. Difficult Constructive Problem | kevinyang# | AC ✓ | 20ms | 4580kb | C++20 | 10.9kb | 2024-04-08 04:44:15 | 2024-04-08 04:44:15 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
/* Macros {{{ */
/* A lot of this is from some of Benq's submissions
[https://codeforces.com/profile/Benq]
Ugly af to the eyes, but with vim fold its barable
Hopefully c++20 concepts can make all this stuff must cleaner */
/* Basics {{{ */
using ll = long long;
using ld = long double;
using str = string;
using pi = pair<int, int>;
using pll = pair<ll, ll>;
using pld = pair<ld, ld>;
#define mp make_pair
#define fi first
#define se second
#define arr array
#define ve vector
using vi = vector<int>;
using vll = vector<ll>;
using vld = vector<ld>;
using vpi = vector<pi>;
using vpll = vector<pll>;
using vpld = vector<pld>;
using vvi = vector<vi>;
using vvll = vector<vll>;
using vvld = vector<vld>;
using vvpi = vector<vpi>;
using vvpll = vector<vpll>;
using vvpld = vector<vpld>;
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define sz size()
#define rsz(a) resize(a)
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define For(i, a, b) for (int i = a; i < b; ++i)
#define Rof(i, a, b) for (int i = (b)-1; i >= (a); --i)
#define rep(a) For(_, 0, a)
#define each(a, x) for (auto &a : x)
#define reach(a, x) for (auto a = x.rbegin(); a != x.rend(); ++a)
template <typename T, typename U>
inline void cmin(T &x, U y) {
if (y < x) x = y;
}
template <typename T, typename U>
inline void cmax(T &x, U y) {
if (x < y) x = y;
}
/*}}}*/
/* IO {{{ */
/* Template Macros {{{ */
#define tcT template <class T
#define tcTU tcT, class U
#define tcTUU tcT, class... U
/*}}}*/
inline namespace Helpers { /*{{{*/
tcT, class = void > struct is_iterable : false_type {};
tcT > struct is_iterable<
T, void_t<decltype(begin(declval<T>())), decltype(end(declval<T>()))>>
: true_type {};
tcT > constexpr bool is_iterable_v = is_iterable<T>::value;
tcT, class = void > struct is_readable : false_type {};
tcT > struct is_readable<T, typename std::enable_if_t<is_same_v<
decltype(cin >> declval<T &>()), istream &>>>
: true_type {};
tcT > constexpr bool is_readable_v = is_readable<T>::value;
tcT, class = void > struct is_printable : false_type {};
tcT > struct is_printable<T, typename std::enable_if_t<is_same_v<
decltype(cout << declval<T>()), ostream &>>>
: true_type {};
tcT > constexpr bool is_printable_v = is_printable<T>::value;
} /* namespace Helpers */
/*}}}*/
inline namespace Input { /*{{{*/
tcT > constexpr bool needs_input_v = !is_readable_v<T> && is_iterable_v<T>;
tcTUU > void re(T &t, U &...u);
tcTU > void re(pair<T, U> &p); /* pairs */
/* re: read{{{ */
tcT > typename enable_if<is_readable_v<T>, void>::type re(T &x) {
cin >> x;
} /* default */
tcT > typename enable_if<needs_input_v<T>, void>::type re(
T &i); // vectors, arrays, etc...
tcTU > void re(pair<T, U> &p) { re(p.fi, p.se); } // pairs
tcT > typename enable_if<needs_input_v<T>, void>::type re(T &i) {
each(x, i) re(x);
}
tcTUU > void re(T &t, U &...u) {
re(t);
re(u...);
} /* read multiple}}} */
/* rv: resize and read vectors{{{ */
void rv(size_t) {}
tcTUU > void rv(size_t N, ve<T> &t, U &...u);
template <class... U>
void rv(size_t, size_t N2, U &...u);
tcTUU > void rv(size_t N, ve<T> &t, U &...u) {
t.rsz(N);
re(t);
rv(N, u...);
}
template <class... U>
void rv(size_t, size_t N2, U &...u) {
rv(N2, u...);
} /*}}}*/
/* dumb shortcuts to read in ints{{{ */
void decrement() {} /* subtract one from each */
tcTUU > void decrement(T &t, U &...u) {
--t;
decrement(u...);
}
#define ints(...) \
int __VA_ARGS__; \
re(__VA_ARGS__);
#define int1(...) \
ints(__VA_ARGS__); \
decrement(__VA_ARGS__); /*}}}*/
} /* namespace Input */
/*}}}*/
inline namespace ToString { /*{{{*/
tcT > constexpr bool needs_output_v = !is_printable_v<T> && is_iterable_v<T>;
/* ts: string representation to print */
tcT > typename enable_if<is_printable_v<T>, str>::type ts(T v) {
stringstream ss;
ss << fixed << setprecision(15) << v;
return ss.str();
} /* default */
tcT > str bit_vec(T t) { /* bit vector to string */
str res = "{";
For(i, 0, t.sz) res += ts(t[i]);
res += "}";
return res;
}
str ts(ve<bool> v) { return bit_vec(v); }
template <size_t SZ>
str ts(bitset<SZ> b) {
return bit_vec(b);
} /* bit vector */
tcTU > str ts(pair<T, U> p); /* pairs */
tcT > typename enable_if<needs_output_v<T>, str>::type ts(
T v); /* vectors, arrays */
tcTU > str ts(pair<T, U> p) { return "(" + ts(p.fi) + ", " + ts(p.se) + ")"; }
tcT > typename enable_if<is_iterable_v<T>, str>::type ts_sep(T v, str sep) {
/* convert container to string w/ separator sep */
bool fst = 1;
str res = "";
for (const auto &x : v) {
if (!fst) res += sep;
fst = 0;
res += ts(x);
}
return res;
}
tcT > typename enable_if<needs_output_v<T>, str>::type ts(T v) {
return "{" + ts_sep(v, ", ") + "}";
}
/* for nested DS */
template <int, class T>
typename enable_if<!needs_output_v<T>, ve<str>>::type ts_lev(const T &v) {
return {ts(v)};
}
template <int lev, class T>
typename enable_if<needs_output_v<T>, ve<str>>::type ts_lev(const T &v) {
if (lev == 0 || !v.sz) return {ts(v)};
ve<str> res;
for (const auto &t : v) {
if (res.sz) res.back() += ",";
ve<str> tmp = ts_lev<lev - 1>(t);
res.insert(end(res), all(tmp));
}
For(i, 0, res.sz) {
str bef = " ";
if (i == 0) bef = "{";
res[i] = bef + res[i];
}
res.back() += "}";
return res;
}
} /* namespace ToString */
/*}}}*/
inline namespace Output { /*{{{*/
template <class T>
void pr_sep(ostream &os, str, const T &t) {
os << ts(t);
}
template <class T, class... U>
void pr_sep(ostream &os, str sep, const T &t, const U &...u) {
pr_sep(os, sep, t);
os << sep;
pr_sep(os, sep, u...);
}
/* print w/ no spaces */
template <class... T>
void pr(const T &...t) {
pr_sep(cout, "", t...);
}
/* print w/ spaces, end with newline */
void ps() { cout << "\n"; }
template <class... T>
void ps(const T &...t) {
pr_sep(cout, " ", t...);
ps();
}
/* debug to cerr */
template <class... T>
void dbg_out(const T &...t) {
pr_sep(cerr, " | ", t...);
cerr << endl;
}
void loc_info(int line, str names) {
cerr << "Line(" << line << ") -> [" << names << "]: ";
}
template <int lev, class T>
void dbgl_out(const T &t) {
cerr << "\n\n" << ts_sep(ts_lev<lev>(t), "\n") << "\n" << endl;
}
} /* namespace Output */
/*}}}}}}}}}*/
int n, k;
str s;
str get_res(str s) {
int tmp = 0;
for(int i=1; i<n; ++i) if((s[i] == '0' && s[i-1] == '1') || (s[i] == '1' && s[i-1] == '0')) ++tmp;
int cnt=0, min_thng=0;
int lp=0, rp;
while(lp < s.sz) {
int rp = lp+1;
while(rp<s.sz && s[rp] == '?') ++rp;
int x = rp-lp-1;
if(x > 0) {
if(s[lp] == s[rp]) cnt += (x+1)/2*2;
if(s[lp] != s[rp]) min_thng+=1, cnt += x/2*2 + 1;
}
lp = rp;
}
if(min_thng > (k-tmp) || cnt < (k-tmp) || ((k-tmp)-cnt)&1) {
return "";
}
int cur_min_possible=min_thng, cur_max_possible=cnt;
lp=0;
while(lp < s.sz) {
int rp = lp+1;
while(rp<s.sz && s[rp] == '?') ++rp;
for(int i=lp+1; i<rp; ++i) {
// before I add a zero, what is the contribution of this interval of ?'s
int bx = rp-i;
int bMv = ((s[i-1] == s[rp]) ? (bx+1)/2*2 : bx/2*2 + 1);
int bmv = (s[i-1] != s[rp]);
// if i add a 0, how will it change
int x = rp-i-1;
int Mv, mv;
if(x > 0) {
Mv = (s[i-1] != '0') + (('0' == s[rp]) ? (x+1)/2*2 : x/2*2+1); // this is how the max acheivable value will change
mv = (s[i-1] != '0') + ('0' != s[rp]); // this is how the min acheviable value will change
} else {
Mv = (s[i-1] != '0') + (s[rp] != '0');
mv = (s[i-1] != '0') + (s[rp] != '0');
}
// ps(bMv, Mv);
int nMp = cur_max_possible - bMv + Mv;
int nmp = cur_min_possible - bmv + mv;
if(nmp <= (k-tmp) && (k-tmp) <= nMp) {
s[i] = '0';
cur_max_possible = nMp;
cur_min_possible = nmp;
} else s[i] = '1';
}
lp = rp;
}
return s;
}
void solve() {
re(n, k, s);
// for(int i=1; i<n-1; ++i) {
// if(s[i-1] == '0' && s[i] == '?' && s[i+1] == '1') s[i] = '0';
// if(s[i-1] == '1' && s[i] == '?' && s[i+1] == '0') s[i] = '0';
// }
ve<str> cands;
if(s[0] == '?' && s[n-1] == '?') {
for(int zv=0; zv<2; ++zv) for(int lv=0; lv<2; ++lv) {
s[0] = '0'+zv, s[n-1] = '0'+lv;
cands.pb(s);
}
} else if (s[0] == '?') {
for(int zv=0; zv<2; ++zv) {
s[0] = '0'+zv;
cands.pb(s);
}
} else if (s[n-1] == '?') {
for(int lv=0; lv<2; ++lv) {
s[n-1] = '0'+lv;
cands.pb(s);
}
} else cands.pb(s);
ve<str> opts;
for(auto s : cands) {
str tmp = get_res(s);
if(tmp != "") opts.pb(tmp);
}
if(opts.sz) ps(*min_element(all(opts)));
else ps("Impossible");
// any 0?1 and 1?0 will always contribute a +1, and thus all of these should be filled in with 0's
// any 0?...?1 and 1?...?0 will contribute at least a +1 and at most a +(2*x - (x&1))
//
// any 0?...?0 and 1?...?1 will contribute at least a +0 and at most a +(2*x - (x&1^1))
//
// for 0?...?1, what are the acheviable values
//
// 0?0 -> { 0, 2 }
// 0?1 -> { 1 }
// 1?0 -> { 1 }
// 1?1 -> { 0, 2 }
// 0??0 -> { 0, 2 }
// 0??1 -> { 1, 3 }
// 1??0 -> { 1, 3 }
//
// claim: 0?...?0 and 1?...?1 can acheive all and only even values in the range [0, 2(x - (x&1^1))]
// 0?...?1 and 1?...?0 can acheive all and only odd values in the range [0, 2x - (x&1)]
// proof: the induction is pretty easy
//
// for even x, 0?...?0 -> 00?...?0 changes nothing and should be done
// for odd x, 0?...?1 -> 00?...?1 changes nothing
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
/* cout << fixed << setprecision(6); */
int t = 1;
cin >> t;
for (int i = 0; i < t; i++) solve();
return 0;
// you should actually read the stuff at the bottom
}
/* stuff you should look for
* int overflow, array bounds
* special cases (n=1?)
* do smth instead of nothing and stay organized
* WRITE STUFF DOWN
* DON'T GET STUCK ON ONE APPROACH
*/
这程序好像有点Bug,我给组数据试试?
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3840kb
input:
5 9 6 1?010??01 9 5 1?010??01 9 6 100101101 9 5 100101101 9 3 ????????1
output:
100100101 Impossible 100101101 Impossible 000000101
result:
ok 5 lines
Test #2:
score: 0
Accepted
time: 20ms
memory: 4580kb
input:
6110 2 0 01 9 5 ????110?? 18 8 ???111???00??010?? 11 8 001??01???0 2 0 00 8 1 ?????111 11 2 110???01??? 13 7 ??100???01??1 6 2 ?????0 18 8 110??11??011??110? 12 5 00??011??00? 20 10 ??01???0011???0010?? 1 0 ? 13 6 ???10??110??0 6 2 00???1 17 10 ??010??001???11?? 5 2 ????0 14 7 010???00???11? 2 1 01 ...
output:
Impossible 001011001 000111000000101010 00101010010 00 00000111 11000001111 0010000101001 000010 110001100011001101 000001101001 00010000011001001010 0 0001000110010 Impossible 00010010010101100 00010 01000100010111 01 0100100001 Impossible 001100010100100101 00111111000 000 01111001 001000000100010...
result:
ok 6110 lines