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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#381572 | #8570. Idola-Tree | ucup-team1004 | WA | 3ms | 14212kb | C++17 | 2.2kb | 2024-04-07 19:03:58 | 2024-04-07 19:04:02 |
Judging History
answer
#include<bits/stdc++.h>
#define Gc() getchar()
#define Me(x,y) memset(x,y,sizeof(x))
#define Mc(x,y) memcpy(x,y,sizeof(x))
#define d(x,y) ((m)*(x-1)+(y))
#define R(n) (rnd()%(n)+1)
#define Pc(x) putchar(x)
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define eb emplace_back
#define all(x) x.begin(),x.end()
using namespace std;using ll=long long;using db=double;using lb=long db;using ui=unsigned;using ull=unsigned long long;using pii=pair<int,int>;
const int N=3e5+5,M=2000+5,K=1000+5,mod=998244353,Mod=mod-1;const db eps=1e-8;const int INF=1e9+7;mt19937 rnd(263082);
#define Tp template<typename T>
#define Ts template<typename T,typename... Ar>
namespace Debug{
Tp void _debug(char* f,T t){cerr<<f<<'='<<t<<endl;}
Ts void _debug(char* f,T x,Ar... y){while(*f!=',') cerr<<*f++;cerr<<'='<<x<<",";_debug(f+1,y...);}
#ifdef LOCAL
#define gdb(...) _debug((char*)#__VA_ARGS__,__VA_ARGS__)
#else
#define gdb(...) void()
#endif
}using namespace Debug;
int n,C,w[N];vector<int> S[N];
int siz[N];ll f1[N],f2[N];
void DP1(int x,int La){
siz[x]=1;f1[x]=0;
for(int i:S[x]) if(i^La) DP1(i,x),f1[x]+=f1[i]+1ll*siz[i]*w[i],siz[x]+=siz[i];
}
void DP2(int x,int La){
for(int i:S[x]) if(i^La) f2[i]=f2[x]+1ll*(n-siz[i])*w[i];
ll tot=0;for(int i:S[x]) if(i^La) f2[i]+=tot,tot+=f1[i]+1ll*siz[i]*w[i];
reverse(all(S[x]));
tot=0;for(int i:S[x]) if(i^La) f2[i]+=tot,tot+=f1[i]+1ll*siz[i]*w[i];
for(int i:S[x]) if(i^La) DP2(i,x);
}
void Solve(){
int i,j;scanf("%d%d",&n,&C);
for(i=1;i<=n;i++) S[i].clear(),w[i]=1;
for(i=1;i<n;i++){
int x,y;scanf("%d%d",&x,&y);
S[x].emplace_back(y);S[y].emplace_back(x);
}
int rt=1;for(i=2;i<=n;i++) if(S[i].size()>=2) rt=i;
DP1(rt,0),DP2(rt,0);
ll tot=0,ans=0;for(j=1;j<=n;j++) if(j^rt) tot+=(f1[j]%mod*(n-siz[j])+f2[j]%mod*siz[j])%mod*w[j]%mod;
priority_queue<ll> q;
for(j=1;j<=n;j++) if(j^rt&&S[j].size()==1) q.emplace(-f2[j]);
int add=0;
for(i=n-1;i<=C;i++){
ans+=1ll*tot*tot%mod*tot%mod;
ll x=-q.top();q.pop();
tot+=2*(x+add)+n-1;tot%=mod;
q.emplace(-(x+n-2));add++;
}
printf("%lld\n",ans%mod);
}
int main(){
int t=1;
scanf("%d",&t);
while(t--) Solve();
cerr<<clock()*1.0/CLOCKS_PER_SEC<<'\n';
}
详细
Test #1:
score: 100
Accepted
time: 3ms
memory: 11336kb
input:
2 4 3 1 4 1 3 2 1 4 4 1 4 1 3 2 1
output:
3375 25327
result:
ok 2 tokens
Test #2:
score: -100
Wrong Answer
time: 3ms
memory: 14212kb
input:
4 4 3 1 4 1 3 2 1 4 4 1 4 1 3 2 1 5 4 1 4 1 3 1 2 5 4 5 5 1 4 1 3 1 2 5 4
output:
3375 25327 314432 1255624
result:
wrong answer 3rd words differ - expected: '54872', found: '314432'