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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#380984#8049. Equal Sumsucup-team2230#TL 2ms11440kbC++233.8kb2024-04-07 15:50:192024-04-07 15:50:19

Judging History

你现在查看的是最新测评结果

  • [2024-04-07 15:50:19]
  • 评测
  • 测评结果:TL
  • 用时:2ms
  • 内存:11440kb
  • [2024-04-07 15:50:19]
  • 提交

answer

#ifndef LOCAL
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#endif

#include <bits/stdc++.h>
using namespace std;

using ll=long long;
using uint=unsigned;

#define rng(i,a,b) for(int i=int(a);i<int(b);i++)
#define rep(i,b) rng(i,0,b)
#define pb push_back
#define eb emplace_back
#define all(x) x.begin(),x.end()
#define si(x) int(x.size())
#define a first
#define b second
template<class t>using vc=vector<t>;
template<class t,class u>bool chmax(t&a, u b){ if(a<b){a=b;return 1;}return 0;}
template<class t,class u>bool chmin(t&a,u b){if(a>b){a=b;return 1;}return 0;}

using P=pair<int,int>;

const uint mod=998244353;
struct mint{
	uint v;
	mint(ll vv=0){s(vv%mod+mod);}
	mint& s(uint vv){
		v=vv<mod?vv:vv-mod;
		return *this;
	}
	mint operator-()const{return mint()-*this;}
	mint&operator+=(mint r){return s(v+r.v);}
	mint&operator-=(mint r){return s(v+mod-r.v);}
	mint&operator*=(mint r){v=(unsigned long long)v*r.v%mod; return *this;}
	mint&operator/=(mint r){return *this*=r.inv();}
	mint operator+(mint r)const{return mint(*this)+=r;}
	mint operator-(mint r)const{return mint(*this)-=r;}
	mint operator*(mint r)const{return mint(*this)*=r;}
	mint operator/(mint r)const{return mint(*this)/=r;}
	mint pow(ll n)const{
		if(n<0)return inv(),pow(-n);
		mint res(1),x(*this);
		while(n){
			if(n&1)res*=x;
			x*=x;
			n>>=1;
		}
		return res;
	}
	mint inv()const{return pow(mod-2);}
};

const mint prim_root=3;
const mint prim_root_inv=prim_root.inv();
void inplace_fmt(vc<mint>&f, const bool inv){
	const int n=f.size();
	const mint root=inv?prim_root_inv:prim_root;
	static vc<mint>g;
	g.clear();g.resize(n);
	
	for(int b=n/2;b>=1;b/=2){
		mint w=root.pow((mod-1)/(n/b)), p=1;
		for(int i=0;i<n;i+=b*2){
			rep(j,b){
				f[i+j+b]*=p;
				g[i/2+j]=f[i+j]+f[i+b+j];
				g[n/2+i/2+j]=f[i+j]-f[i+b+j];
			}
			p*=w;
		}
		swap(f,g);
	}
	if(inv){
		mint z=mint(n).inv();
		rep(i,n)f[i]*=z;
	}
}
vc<mint> multiply(vc<mint> a,vc<mint> b){
	int n=a.size(),m=b.size();
	assert(n>0&&m>0);
	int s=1;while(s<n+m-1) s*=2;
	a.resize(s);inplace_fmt(a,false);
	b.resize(s);inplace_fmt(b,false);
	rep(i,s)a[i]*=b[i];inplace_fmt(a,true);
	a.resize(n+m-1);return a;
}

void solve(){
	int n,m;
	cin>>n>>m;
	vc<P> A(n),C(m);
	
	for(int i=0;i<n;i++) cin>>A[i].a>>A[i].b;
	for(int i=0;i<m;i++){
		cin>>C[i].a>>C[i].b;
	}/*
	for(int i=0;i<n;i++) A[i].a=1,A[i].b=500;
	for(int i=0;i<m;i++) C[i].a=1,C[i].b=500;*/
	for(int i=0;i<m;i++){
		swap(C[i].a,C[i].b);
		C[i].a=-C[i].a;
		C[i].b=-C[i].b;
	}
	int M=505;
	int B=4*M*M;
	vc<mint> dp(2*B);
	dp[B]=1;
	vc<vc<mint>> ans(n,vc<mint>(m));

	auto adda=[&](int l,int r,int x){
		P p=A[x];
		mint sum=0;
		for(int i=r-p.b;i<=r-p.a;i++) sum+=dp[i];
		for(int i=r-1;i>=l;i--){
			sum+=dp[i-p.b];
			sum-=dp[i-p.a+1];
			dp[i]=sum;
		}
	};
	auto addc=[&](int l,int r,int x){
		P p=C[x];
		mint sum=0;
		for(int i=l-p.b;i<=l-p.a;i++) sum+=dp[i];
		for(int i=l;i<r;i++){
			dp[i]=sum;
			sum-=dp[i-p.b];
			sum+=dp[i-p.a+1];
		}
	};
	vc<vc<mint>> cur(20);
	int mx=n+m;
	for(int i=0;i<20;i++){
		int sz=mx*M*4;
		cur[i].resize(sz);
		mx=(mx+2)/2;
	}
	auto rec=[&](int a,int b,int c,int d,int dep,auto self)->void{
		if(a==b||c==d) return;
		int L=max(b-a,d-c);
		int l=B-L*M,r=B+L*M;
		for(int i=l;i<r;i++) cur[dep][i-l]=dp[i];
		if(a+1==b&&c+1==d){
			adda(l,r,a);
			addc(l,r,c);
			ans[a][c]=dp[B];
		} else{
			int ma=(a+b)/2,mc=(c+d)/2;
			self(a,ma,c,mc,dep+1,self);
			for(int i=a;i<ma;i++) adda(l,r,i);
			self(ma,b,c,mc,dep+1,self);
			for(int i=c;i<mc;i++) addc(l,r,i);
			self(ma,b,mc,d,dep+1,self);
			for(int i=l;i<r;i++) dp[i]=cur[dep][i-l];
			for(int i=c;i<mc;i++) addc(l,r,i);
			self(a,ma,mc,d,dep+1,self);
		}
		for(int i=l;i<r;i++) dp[i]=cur[dep][i-l];
	};
	rec(0,n,0,m,0,rec);
	for(int i=0;i<n;i++){
		for(int j=0;j<m;j++){
			cout<<ans[i][j].v<<" ";
		}cout<<endl;
	}
}

signed main(){
	cin.tie(0);
	ios::sync_with_stdio(0);
	cout<<fixed<<setprecision(20);
	
	solve();
}

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 11440kb

input:

2 3
1 2
2 3
1 4
2 2
1 3

output:

2 0 0 
3 4 4 

result:

ok 6 numbers

Test #2:

score: -100
Time Limit Exceeded

input:

500 500
19 458
1 480
7 485
50 461
12 476
15 461
48 466
40 453
46 467
9 458
27 478
26 472
46 459
29 490
6 500
17 487
48 484
28 472
28 459
25 480
4 491
29 481
36 460
2 491
44 499
22 473
20 458
4 483
27 471
2 496
11 461
43 450
2 478
37 466
15 459
42 482
7 451
19 455
2 453
47 475
48 450
1 474
46 471
9 4...

output:


result: