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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#380072#8572. Passing Gameucup-team228#TL 2ms13740kbC++207.9kb2024-04-06 20:54:342024-04-06 20:54:34

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你现在查看的是最新测评结果

  • [2024-04-06 20:54:34]
  • 评测
  • 测评结果:TL
  • 用时:2ms
  • 内存:13740kb
  • [2024-04-06 20:54:34]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

struct CHT {
    int pointer=0;
    vector<long long> K, B;
    void clear() {
        pointer = 0;
        K.clear();
        B.clear();
    }
    bool bad(int l1, int l2, int l3) {
        return (B[l3] - B[l1]) * (K[l1] - K[l2]) < (B[l2] - B[l1]) * (K[l1] - K[l3]);
    }
    void add(long long k, long long b) {
        if (!K.empty() && K.back() == k) return;
        K.push_back(k);
        B.push_back(b);
        while (K.size() >= 3 && bad(K.size() - 3, K.size() - 2, K.size() - 1)) {
            K.erase(K.end()-2);
            B.erase(B.end()-2);
        }
    }
    ll getmin(long long x) {
        int lef = 0, rig = K.size() - 1;
        while (lef < rig) {
            int mid = (lef + rig) / 2;
            if (K[mid] * x + B[mid] > K[mid + 1] * x + B[mid + 1]) {
                lef = mid + 1;
            } else {
                rig = mid;
            }
        }
        return K[lef] * x + B[lef];
//        while (pointer < K.size()-1 && K[pointer+1] * x + B[pointer+1] < K[pointer] * x + B[pointer]) pointer++;
//        return K[pointer] * x + B[pointer];
    }
};

const ll inf = 1e18 + 10;
const int K = 70;
const int N = 3e5 + 10;
int x_init[N], s_init[N];
int x[N], s[N];
tuple<int, int, int> c3[N];
ll dp_lef[2][N], dp_rig[2][N];

ll solve(int n, int k) {
    for (int i = 1; i <= n; i++) {
        c3[i] = {x[i], s[i], i};
    }
    sort(c3 + 1, c3 + n + 1);
    int src, trg;
    for (int i = 1; i <= n; i++) {
        auto [cur_x, cur_s, cur_i] = c3[i];
        x[i] = cur_x;
        s[i] = cur_s;
        if (cur_i == 1) {
            src = i;
        }
        if (cur_i == n) {
            trg = i;
        }
    }
    ll ans = inf;
    {
        stack<int> st;
        for (int i = 1; i <= n; i++) {
            while (!st.empty() && s[i] <= s[st.top()]) {
                st.pop();
            }
            dp_lef[0][i] = inf;
            if (i >= trg) {
                dp_lef[0][i] = min(dp_lef[0][i], 1ll * s[i] * (x[i] - x[trg]));
                if (!st.empty()) {
                    int j = st.top();
                    dp_lef[0][i] = min(dp_lef[0][i], 1ll * s[i] * (x[i] - x[j]) + dp_lef[0][j]);
                }
            }
            st.push(i);
        }
        while (!st.empty()) {
            st.pop();
        }
        for (int i = n; i >= 1; i--) {
            while (!st.empty() && s[i] <= s[st.top()]) {
                st.pop();
            }
            dp_rig[0][i] = inf;
            if (i <= trg) {
                dp_rig[0][i] = min(dp_rig[0][i], 1ll * s[i] * (x[trg] - x[i]));
                if (!st.empty()) {
                    int j = st.top();
                    dp_rig[0][i] = min(dp_rig[0][i], 1ll * s[i] * (x[j] - x[i]) + dp_rig[0][j]);
                }
            }
            st.push(i);
        }
        ans = min({ans, dp_lef[0][src], dp_rig[0][src]});
    }
    for (int iter = 1; iter <= min(k, K); iter++) {
        int p = iter & 1;
        int q = p ^ 1;
        for (int i = 1; i <= n; i++) {
            dp_lef[p][i] = dp_rig[p][i] = inf;
        }

        stack<int> st;
        CHT cht;
        for (int i = 1; i <= n; i++) {
            while (!st.empty() && s[i] <= s[st.top()]) {
                st.pop();
            }
            dp_lef[p][i] = inf;
            if (!st.empty()) {
                int j = st.top();
                dp_lef[p][i] = min(dp_lef[p][i], 1ll * s[i] * (x[i] - x[j]) + dp_lef[p][j]);
                if (i >= 2) {
                    dp_lef[p][i] = min(dp_lef[p][i], 1ll * s[i] * x[i] + cht.getmin(s[i]));
                }
            }
            st.push(i);
            cht.add(-x[i], dp_rig[q][i]);
        }
        while (!st.empty()) {
            st.pop();
        }
        cht.clear();
        for (int i = n; i >= 1; i--) {
            while (!st.empty() && s[i] <= s[st.top()]) {
                st.pop();
            }
            dp_rig[p][i] = inf;
            if (!st.empty()) {
                int j = st.top();
                dp_rig[p][i] = min(dp_rig[p][i], 1ll * s[i] * (x[j] - x[i]) + dp_rig[p][j]);
                if (i <= n - 1) {
                    dp_rig[p][i] = min(dp_rig[p][i], -1ll * s[i] * x[i] + cht.getmin(s[i]));
                }
            }
            st.push(i);
            cht.add(x[i], dp_lef[q][i]);
        }

        ans = min({ans, dp_lef[p][src], dp_rig[p][src]});
    }
    return ans;
}

bool getbit(int mask, int bit) {
    return mask & (1 << bit);
}

ll slow(int n, int k) {
    ll res = inf;
    for (int mask = 0; mask < (1 << n); mask++) {
        if (getbit(mask, 0) && getbit(mask, n - 1)) {
            vector<int> ord;
            ord.push_back(1);
            for (int i = 2; i <= n - 1; i++) {
                if (getbit(mask, i - 1)) {
                    ord.push_back(i);
                }
            }
            ord.push_back(n);
            do {
                ll cur = 0;
                int cnt_rot = 0;
                for (int i = 1; i < ord.size(); i++) {
                    cur += 1ll * s[ord[i - 1]] * abs(x[ord[i]] - x[ord[i - 1]]);
                }
                for (int i = 1; i + 1 < ord.size(); i++) {
                    if (1ll * (x[ord[i]] - x[ord[i - 1]]) * (x[ord[i + 1]] - x[ord[i]]) <= 0) {
                        cnt_rot++;
                    }
                }
                if (cnt_rot <= k) {
                    res = min(res, cur);
                }
            } while (next_permutation(ord.begin() + 1, ord.end() - 1));
        }
    }
    return res;
}

void stress() {
    mt19937 rnd;
    while (true) {
        int n = rnd() % 10 + 1;
        int k = rnd() % (n + 1);
        set<int> used_x;
        for (int i = 1; i <= n; i++) {
            do {
                x[i] = rnd() % 100 + 1;
            } while (used_x.count(x[i]));
            s[i] = rnd() % 100 + 1;
            used_x.insert(x[i]);
        }
        for (int i = 1; i <= n; i++) {
            x_init[i] = x[i];
            s_init[i] = s[i];
        }
        ll ans = solve(n, k);
        for (int i = 1; i <= n; i++) {
            x[i] = x_init[i];
            s[i] = s_init[i];
        }
        ll res = slow(n, k);
        if (ans == res) {
            cout << "OK" << endl;
        } else {
            cout << "WA\n";
            cout << "1\n";
            cout << n << " " << k << "\n";
            for (int i = 1; i <= n; i++) {
                cout << x[i] << " ";
            }
            cout << "\n";
            for (int i = 1; i <= n; i++) {
                cout << s[i] << " ";
            }
            cout << "\n\n";
            cout << ans << " " << res << "\n";
            break;
        }
    }
    exit(0);
}

void gen_big() {
    mt19937 rnd;
    int n = 3e5;
    int k = n;
    set<int> used_x;
    for (int i = 1; i <= n; i++) {
        do {
            x[i] = rnd() % 100000000 + 1;
        } while (used_x.count(x[i]));
        s[i] = rnd() % 100000000 + 1;
        used_x.insert(x[i]);
    }
    cout << solve(n, k) << "\n";
    cout << "\nTime elapsed: " << double(clock()) / CLOCKS_PER_SEC << " s.\n";
    exit(0);
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
#endif

    // stress();
    // gen_big();

//    for (int i = 1; i <= 3e5; i++) {
//        swap(dp_lef[0], dp_lef[1]);
//        dp_lef[0][123] += 45325;
//    }

    int t;
    cin >> t;
    while (t--) {
        int n, k;
        cin >> n >> k;
        for (int i = 1; i <= n; i++) {
            cin >> x[i];
        }
        for (int i = 1; i <= n; i++) {
            cin >> s[i];
        }
        cout << solve(n, k) << "\n";
    }

#ifdef LOCAL
    cout << "\nTime elapsed: " << double(clock()) / CLOCKS_PER_SEC << " s.\n";
#endif
}

詳細信息

Test #1:

score: 100
Accepted
time: 2ms
memory: 13740kb

input:

2
4 2
3 2 1 6
3 1 1 3
2 0
1 2
1 2

output:

7
1

result:

ok 2 number(s): "7 1"

Test #2:

score: -100
Time Limit Exceeded

input:

1
300000 204334
809492393 304618667 173130445 377106790 364888630 949045125 622060683 557772818 216607577 848817467 862855568 507840723 120816645 639713488 741781998 682531787 685261161 601686403 355792373 162819930 710057718 234560726 998604853 678957602 485413982 855985802 109303681 979706626 4822...

output:

31313390701066

result: