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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#379143 | #8576. Symphony in c++ major | ucup-team228# | ML | 0ms | 0kb | C++20 | 3.5kb | 2024-04-06 16:22:18 | 2024-04-06 16:22:19 |
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
template <typename T>
struct segment_tree {
static const int N = 5e5 + 10;
const T good_value = {}; // 0 for sum, -inf for max, and inf for min
T a[N], t[4 * N];
T merge(T x, T y) {
return x + y;
}
void build(int v = 1, int tl = 0, int tr = N - 1) {
if (tl > tr) return;
if (tl == tr) {
t[v] = a[tl];
return;
}
int tm = (tl + tr) / 2;
build(v + v, tl, tm);
build(v + v + 1, tm + 1, tr);
t[v] = merge(t[v + v], t[v + v + 1]);
}
void update(int pos, T val, int v = 1, int tl = 0, int tr = N - 1) {
if (tl > tr || tl > pos || pos > tr) return;
if (tl == tr) {
t[v] = val;
return;
}
int tm = (tl + tr) / 2;
update(pos, val, v + v, tl, tm);
update(pos, val, v + v + 1, tm + 1, tr);
t[v] = merge(t[v + v], t[v + v + 1]);
}
T get(int l, int r, int v = 1, int tl = 0, int tr = N - 1) {
if (tl > tr || l > r || tl > r || l > tr) return good_value;
if (l <= tl && tr <= r) {
return t[v];
}
int tm = (tl + tr) / 2;
return merge(get(l, r, v + v, tl, tm), get(l, r, v + v + 1, tm + 1, tr));
}
};
const int inf = 1e9;
const int C = 7;
const vector<string> all = {
"do",
"re",
"mi",
"fa",
"so",
"la",
"ti"
};
struct Node {
int dp[C + 1][C + 1];
Node() {
for (int i = 0; i <= C; i++) {
for (int j = 0; j <= C; j++) {
dp[i][j] = -inf;
}
}
dp[C][C] = 0;
}
Node(char ch) {
for (int i = 0; i <= C; i++) {
for (int j = 0; j <= C; j++) {
if ((i == C || all[i][1] == ch) && (j == C || all[j][0] == ch)) {
dp[i][j] = (i != C) + (j != C);
} else {
dp[i][j] = -inf;
}
}
}
}
friend Node operator+(const Node& a, const Node& b) {
Node res;
for (int i = 0; i <= C; i++) {
for (int j = 0; j <= C; j++) {
res.dp[i][j] = max(a.dp[i][j], b.dp[i][j]);
for (int k = 0; k <= C; k++) {
res.dp[i][j] = max(res.dp[i][j], a.dp[i][k] + b.dp[k][j]);
}
}
}
return res;
}
};
segment_tree<Node> tree;
void foo() {
const string s = "eldorado";
for (int i = 0; i < s.size(); i++) {
tree.update(i + 1, s[i]);
}
auto res = tree.get(1, 3);
cout << res.dp[C][C] << "\n";
exit(0);
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
#ifdef LOCAL
freopen("input.txt", "r", stdin);
#endif
// foo();
int n, q;
cin >> n >> q;
string s;
cin >> s;
for (int i = 1; i <= n; i++) {
tree.update(i, s[i - 1]);
}
while (q--) {
char type;
cin >> type;
int l, r;
cin >> l >> r;
if (type == '#') {
string cur;
cin >> cur;
for (int i = 0; i < cur.size(); i++) {
tree.update(l + i, cur[i]);
}
} else {
cout << (r - l + 1) - tree.get(l, r).dp[C][C] << "\n";
}
}
#ifdef LOCAL
cout << "\nTime elapsed: " << double(clock()) / CLOCKS_PER_SEC << " s.\n";
#endif
}
详细
Test #1:
score: 0
Memory Limit Exceeded
input:
8 10 eldorado ? 1 3 ? 1 8 # 6 7 it ? 1 8 # 3 3 t ? 1 8 # 1 8 streamer ? 1 8 # 1 8 symphony ? 1 8
output:
3 4 6 6 6 6