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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#378085 | #5058. Prof. Pang Earning Aus | InfinityNS | TL | 4ms | 3956kb | C++17 | 1.3kb | 2024-04-06 00:34:27 | 2024-04-06 00:34:28 |
Judging History
answer
#include<bits/stdc++.h>
#define f first
#define s second
#define ll long long
#define pb push_back
#define sz(x) (int)(x).size()
#define all(x) (x).begin(),(x).end()
using namespace std;
vector<ll> x(6);
vector<int> n(2),k(6);
ll ans;
void pok(){
x[0]=(n[0]-x[5]*k[5])/k[0];
if(x[0]<0)return;
x[1]=x[0]*k[0]+x[5]*k[5]-x[4];
if(x[1]<0)return;
x[2]=(n[1]-x[4]*k[4])/k[2];
if(x[2]<0)return;
x[3]=x[2]*k[2]+x[4]*k[4]-x[5];
if(x[3]<0)return;
if(x[0]==0&&x[2]==0)return;
if(x[1]+x[4]>n[0])return;
if(x[3]+x[5]>n[1])return;
ans=max(ans,x[1]*k[1]+x[3]*k[3]-x[0]-x[2]);
}
vector<int> x4,x5;
void test(){
for(int i=0;i<2;i++){
scanf("%i",&n[i]);
}
for(int i=0;i<6;i++){
scanf("%i",&k[i]);
}
ans=0;
const int L=100;
for(x[4]=0;x[4]<=L;x[4]++)x4.pb(x[4]);
for(x[5]=0;x[5]<=L;x[5]++)x5.pb(x[5]);
int mx4=min(n[1]/k[4],n[0]),mx5=min(n[0]/k[5],n[1]);
for(x[4]=mx4;x[4]>=0&&mx4-x[4]<=L;x[4]--)x4.pb(x[4]);
for(x[5]=mx5;x[5]>=0&&mx5-x[5]<=L;x[5]--)x5.pb(x[5]);
for(auto p:x4)for(auto q:x5){
x[4]=p;
x[5]=q;
pok();
}
printf("%lld\n",ans+1);
}
int main(){
int t;
scanf("%i",&t);
while(t--){
test();
}
}
Details
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Test #1:
score: 100
Accepted
time: 4ms
memory: 3956kb
input:
6 2 2 2 2 2 2 2 2 78 74 5 3 10 2 4 7 31 75 3 6 6 1 8 4 91 86 4 2 9 5 8 5 48 89 3 9 2 3 5 7 13 25 5 7 6 1 2 4
output:
7 355 239 571 637 109
result:
ok 6 numbers
Test #2:
score: -100
Time Limit Exceeded
input:
1000 10 10 7 9 8 3 3 10 3 7 3 10 3 3 6 5 8 1 4 7 1 10 1 5 7 7 3 10 4 7 2 9 7 9 6 7 3 3 4 6 9 2 4 4 9 5 2 4 8 1 9 1 2 3 7 3 6 4 7 9 8 5 6 2 10 2 4 8 6 9 6 1 9 7 2 10 10 4 7 1 5 4 5 6 8 7 10 5 4 4 7 7 1 5 3 8 4 5 8 9 5 10 1 7 2 6 10 9 2 4 10 6 7 3 8 9 3 9 5 4 2 7 6 1 5 8 5 6 3 5 9 3 6 2 9 9 9 9 8 3 6 ...