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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#376048#6631. Maximum Bitwise ORschrodingerstomWA 100ms3992kbC++144.5kb2024-04-03 20:01:002024-04-03 20:01:00

Judging History

你现在查看的是最新测评结果

  • [2024-04-03 20:01:00]
  • 评测
  • 测评结果:WA
  • 用时:100ms
  • 内存:3992kb
  • [2024-04-03 20:01:00]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
bool memBeg;
template<typename T,typename TT> void chkmin(T &x,TT y) {if(x>y) x=y;}
template<typename T,typename TT> void chkmax(T &x,TT y) {if(x<y) x=y;}
constexpr int mod=998244353;
void inc(int &x,int y) {x+=y; x-=(x>=mod)*mod;}
void dec(int &x,int y) {x-=y; x+=(x<0)*mod;}
constexpr int add(int x,int y) {return (x+y>=mod)?x+y-mod:x+y;}
constexpr int sub(int x,int y) {return (x<y)?x-y+mod:x-y;}
constexpr int quick_pow(int x,ll times,int ret=1) {
    for(;times;times>>=1,x=1ll*x*x%mod) if(times&1) ret=1ll*ret*x%mod;
    return ret;
}
constexpr int D=30;
constexpr int maxD=D+5;
constexpr int maxn=1e5+5;
int n,Q,a[maxn];
struct info1 {
    int pos[maxD];
    int operator[](int x) const {return pos[x];}
    int& operator[](int x) {return pos[x];}
    info1 operator+(const info1 &o) const {
        info1 ret;
        for(int i=0;i<D;i++) {
            if(pos[i]==-1||o[i]==-1) ret[i]=-1;
            else if(pos[i]&&o[i]&&pos[i]!=o[i]) ret[i]=-1;
            else ret[i]=pos[i]|o[i];
        }
        return ret;
    }
};
struct info2 {
    int mx[maxD];
    int operator[](int x) const {return mx[x];}
    int& operator[](int x) {return mx[x];}
    info2 operator+(const info2 &o) const {
        info2 ret;
        for(int i=0;i<D;i++) ret[i]=max(mx[i],o[i]);
        return ret;
    }
};
struct info {
    int Or;
    info1 p;
    info2 q;
    info operator+(const info &o) const {
        info ret; ret.Or=Or|o.Or;
        ret.p=p+o.p; ret.q=q+o.q;
        auto flush=[&](int idx)->void {
            if(!a[idx]) return;
            for(int t=__lg(a[idx]);t>=0;t--) {
                chkmax(ret.q[t],a[idx]^(a[idx]-(1<<t)));
            }
        };
        static bool key[maxn];
        for(int i=0;i<D;i++) {
            if(ret.p[i]>0) key[ret.p[i]]=true;
        }
        for(int i=0;i<D;i++) {
            if(p[i]>0&&!key[p[i]]) flush(p[i]);
            if(o.p[i]>0&&!key[o.p[i]]) flush(o.p[i]);
        }
        for(int i=0;i<D;i++) {
            if(ret.p[i]>0) key[ret.p[i]]=false;
        }
        return ret;
    }
};
struct segment_tree {
    info tree[maxn<<2];
    void push_up(int cur) {
        tree[cur]=tree[cur<<1]+tree[cur<<1|1];
    }
    void build(int tl,int tr,int cur) {
        if(tl==tr) {
            for(int i=0;i<D;i++) {
                if(a[cur]&(1<<i)) tree[cur].p[i]=tl;
                else tree[cur].p[i]=0;
                tree[cur].q[i]=0;
            }
            tree[cur].Or=a[tl]; return;
        }
        int mid=(tl+tr)>>1;
        build(tl,mid,cur<<1);
        build(mid+1,tr,cur<<1|1);
        push_up(cur);
    }
    info query(int tl,int tr,int cur,int l,int r) {
        if(l<=tl&&tr<=r) return tree[cur];
        int mid=(tl+tr)>>1;
        if(l>mid) return query(mid+1,tr,cur<<1|1,l,r);
        else if(r<=mid) return query(tl,mid,cur<<1,l,r);
        else return query(tl,mid,cur<<1,l,r)+
                    query(mid+1,tr,cur<<1|1,l,r);
    }
}T;
void mian() {
    scanf("%d%d",&n,&Q);
    for(int i=1;i<=n;i++) scanf("%d",&a[i]);
    T.build(1,n,1);
    while(Q--) {
        int l,r;
        scanf("%d%d",&l,&r);
        static info tmp;
        tmp=T.query(1,n,1,l,r);
        if(!tmp.Or) {
            printf("0 0\n"); continue;
        }
        int mx=(1<<(__lg(tmp.Or)+1))-1;
        if(tmp.Or==mx) {
            printf("%d %d\n",mx,0); continue;
        }
        bool one=false;
        for(int i=0;i<D&&!one;i++) {
            if((tmp.Or|tmp.q[i])==mx) {
                one=true; break;
            }
        }
        for(int i=0;i<D&&!one;i++) {
            if(!tmp.p[i]) continue;
            int idx=tmp.p[i],must=0;
            for(int j=0;j<D;j++) {
                if(tmp.p[j]==idx) must|=1<<j;
            }
            if(must!=(1<<i)) continue;
            for(int j=0;j<D;j++) {
                if((1<<j)>a[idx]) break;
                int upd=a[idx]^(a[idx]-(1<<j));
                if(!(upd&must)) continue;
                if((tmp.Or|upd)==mx) {
                    one=true; break;
                }
            }
        }
        printf("%d %d\n",mx,one?1:2);
    }
}
bool memEn;
void fl() {
    freopen(".in","r",stdin);
    freopen(".out","w",stdout);
}
int main() {
    fprintf(stderr,"%.24lf\n",fabs(&memEn-&memBeg)/1024.0/1024.0);
    // fl();
    int _; scanf("%d",&_);
    while(_--) mian();
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 3980kb

input:

1
3 2
10 10 5
1 2
1 3

output:

15 2
15 0

result:

ok 4 number(s): "15 2 15 0"

Test #2:

score: 0
Accepted
time: 100ms
memory: 3980kb

input:

100000
1 1
924704060
1 1
1 1
149840457
1 1
1 1
515267304
1 1
1 1
635378394
1 1
1 1
416239424
1 1
1 1
960156404
1 1
1 1
431278082
1 1
1 1
629009153
1 1
1 1
140374311
1 1
1 1
245014761
1 1
1 1
445512399
1 1
1 1
43894730
1 1
1 1
129731646
1 1
1 1
711065534
1 1
1 1
322643984
1 1
1 1
482420443
1 1
1 1
20...

output:

1073741823 2
268435455 2
536870911 2
1073741823 2
536870911 2
1073741823 2
536870911 2
1073741823 2
268435455 2
268435455 2
536870911 2
67108863 2
134217727 2
1073741823 2
536870911 2
536870911 2
268435455 2
536870911 2
536870911 2
536870911 2
268435455 2
268435455 2
1073741823 2
16777215 2
10737418...

result:

ok 200000 numbers

Test #3:

score: 0
Accepted
time: 95ms
memory: 3992kb

input:

50000
2 2
924896435 917026400
1 2
1 2
2 2
322948517 499114106
1 2
2 2
2 2
152908571 242548777
1 1
1 2
2 2
636974385 763173214
1 2
1 1
2 2
164965132 862298613
1 1
1 2
2 2
315078033 401694789
1 2
1 2
2 2
961358343 969300127
2 2
1 2
2 2
500628228 28065329
1 2
1 2
2 2
862229381 863649944
1 2
2 2
2 2
541...

output:

1073741823 2
1073741823 2
536870911 2
536870911 2
268435455 2
268435455 2
1073741823 2
1073741823 2
268435455 2
1073741823 2
536870911 2
536870911 2
1073741823 2
1073741823 2
536870911 2
536870911 2
1073741823 2
1073741823 2
1073741823 2
268435455 2
536870911 2
536870911 2
1073741823 2
1073741823 2
...

result:

ok 200000 numbers

Test #4:

score: -100
Wrong Answer
time: 98ms
memory: 3960kb

input:

33333
3 3
925088809 339284112 289540728
3 3
1 3
1 1
3 3
422399522 892365243 216341776
3 3
3 3
1 2
3 3
668932010 837523227 840095874
1 3
1 3
3 3
3 3
731584574 357877180 359063739
1 1
1 1
3 3
3 3
463358343 833924976 847087403
2 3
3 3
1 2
3 3
377154649 772000701 656357011
2 3
1 2
2 3
3 3
977492169 5540...

output:

536870911 2
1073741823 2
1073741823 2
268435455 2
268435455 2
1073741823 2
1073741823 2
1073741823 2
1073741823 2
1073741823 2
1073741823 2
536870911 2
1073741823 2
1073741823 2
1073741823 2
1073741823 2
1073741823 2
1073741823 2
1073741823 2
1073741823 2
1073741823 2
67108863 2
1073741823 2
1073741...

result:

wrong answer 5770th numbers differ - expected: '1', found: '2'