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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#373782 | #5201. Cactus Meets Torus | InfinityNS | WA | 7ms | 6364kb | C++14 | 2.7kb | 2024-04-02 05:46:24 | 2024-04-02 05:46:26 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define pb push_back
const int N=100050;
vector<int> E[N];
void AddEdge(int u,int v){
E[u].pb(v);
E[v].pb(u);
}
int par[N];
bool was[N];
vector<int> cycLca;
vector<pair<int,int>> cyc;
int cnt[N];
int lid[N],rid[N],tid;
void DFS(int u,int p){
par[u]=p;
was[u]=true;
lid[u]=++tid;
for(int v:E[u]){
if(v!=p){
if(was[v]){
if(lid[v]<lid[u]){
cycLca.pb(v);
cyc.pb({u,v});
for(int i=u;i!=par[v];i=par[i]){
cnt[i]++;
}
}
}else{
DFS(v,u);
}
}
}
rid[u]=tid;
}
bool In(int a,int b){
return lid[a]<=lid[b] && rid[a]>=lid[b];
}
int main(){
while(true){
int n,m;
scanf("%i %i",&n,&m);
if(n==0)break;
for(int i=1;i<=m;i++){
int sz;
scanf("%i",&sz);
vector<int> nodes(sz,0);
for(int&j:nodes)scanf("%i",&j);
for(int j=1;j<nodes.size();j++){
AddEdge(nodes[j-1],nodes[j]);
}
}
cycLca.clear();
DFS(1,0);
sort(cycLca.begin(),cycLca.end(),[&](int i,int j){return lid[i]<lid[j];});
sort(cyc.begin(),cyc.end(),[&](pair<int,int> a,pair<int,int> b){return lid[a.second]<lid[b.second];});
int lastCycNode=cyc.size()?cyc.back().first:0;
for(int i=1;i<=n;i++){
was[i]=false;
par[i]=0;
cnt[i]=0;
}
//printf("lastCycNode %i\n",lastCycNode);
if(!lastCycNode){
printf("Yes\n");
}else{
cycLca.clear();
cyc.clear();
DFS(lastCycNode,0);
//printf("lastCycNode %i\n",lastCycNode);
bool ok=true;
sort(cycLca.begin(),cycLca.end(),[&](int i,int j){return lid[i]<lid[j];});
int fir=cycLca.front();
int las=cycLca.back();
//for(int lca:cycLca)printf("cycLca %i (%i %i)\n",lca,lid[lca],rid[lca]);
for(int i=1;i<cycLca.size();i++){
//printf("cycLca %i\n",lca);
if(rid[cycLca[i-1]]<lid[cycLca[i]]){
ok=false;
}
}
if(ok){
ok=false;
bool good=true;
for(auto p:cyc){
int deg=0,sec=0;
for(int i=p.first;i!=par[p.second];i=par[i]){
deg+=cnt[i]-1;
if(cnt[i]>1)sec++;
}
if(deg==cyc.size()-1)ok=true;
//if(sec>2 || (sec>1 && cnt[par[p.second]]==0 && par[p.second]!=0))good=false;
//if(sec>1 && (p.second==fir || p.second==las))good=false;
}
sort(cyc.begin(),cyc.end(),[&](pair<int,int> a,pair<int,int> b){return lid[a.second]<lid[b.second];});
//for(auto p:cyc)printf("(%i %i)\n",p.first,p.second);
for(int i=2;i<cyc.size();i++){
if(In(cyc[i-2].second,cyc[i].second) && In(cyc[i].second,cyc[i-2].first))good=false;
}
if(ok || good)printf("Yes\n");
else printf("No\n");
}else{
printf("No\n");
}
}
for(int i=1;i<=n;i++){
was[i]=false;
par[i]=0;
E[i].clear();
cnt[i]=0;
}
tid=0;
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 6176kb
input:
6 1 8 1 2 3 1 4 5 6 4 10 2 9 1 2 3 1 10 4 5 6 4 5 7 8 9 7 10 0 0
output:
Yes No
result:
ok 2 token(s): yes count is 1, no count is 1
Test #2:
score: 0
Accepted
time: 2ms
memory: 6080kb
input:
15 3 9 1 2 3 4 5 6 7 8 3 7 2 9 10 11 12 13 10 5 2 14 9 15 10 15 7 3 1 2 3 3 4 2 5 3 6 2 7 3 8 2 9 3 10 2 11 3 12 2 13 3 14 2 15 1 0 2 1 2 1 2 2 1 2 2 1 3 1 4 1 3 2 1 4 2 3 1 2 3 2 2 4 6 2 5 1 2 3 4 5 2 4 6 7 3 5 1 2 3 4 5 2 4 6 2 4 7 7 2 6 1 2 3 4 5 6 2 5 7 8 3 6 1 2 3 4 5 6 2 5 7 2 5 8 9 4 5 1 2 3 ...
output:
Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes
result:
ok 18 token(s): yes count is 18, no count is 0
Test #3:
score: -100
Wrong Answer
time: 7ms
memory: 6364kb
input:
6 1 8 6 1 2 3 1 4 5 1 6 1 8 5 1 2 3 1 4 6 1 6 1 8 4 1 2 3 1 5 6 1 6 2 6 4 1 2 3 1 5 2 1 6 6 1 8 6 1 2 4 1 3 5 1 6 1 8 5 1 2 4 1 3 6 1 6 1 8 3 1 2 4 1 5 6 1 6 2 6 3 1 2 4 1 5 2 1 6 6 1 8 6 1 2 5 1 3 4 1 6 1 8 4 1 2 5 1 3 6 1 6 1 8 3 1 2 5 1 4 6 1 6 2 6 3 1 2 5 1 4 2 1 6 6 1 8 5 1 2 6 1 3 4 1 6 1 8 4 ...
output:
Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes ...
result:
wrong answer expected YES, found NO [8746th token]