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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#372495 | #8340. 3 Sum | zzuqy# | TL | 400ms | 3940kb | C++14 | 1.0kb | 2024-03-31 14:11:55 | 2024-03-31 14:11:55 |
Judging History
answer
#include <bits/stdc++.h>
#define fep(A,B,C) for(int C=A;C>=B;--C)
#define rep(A,B,C) for(int C=A;C<=B;++C)
#define ll long long
#define sc(k) scanf("%d",&k)
#define put(A) printf("%d\n",A)
using namespace std;
const int MAXN=510;
int T,n;
int a[MAXN][10];
int k[10];
int mod[10];
char b[20010];
int main()
{
//freopen("1.in","r",stdin);
sc(n);
mod[1]=1000000007;
mod[2]=19260817;
mod[3]=998244353;
mod[4]=1000000009;
mod[5]=1004535809;
sc(T);
rep(1,5,j)k[j]=1;
rep(1,T,i)
{
rep(1,5,j)
k[j]=((ll)k[j]*10)%mod[j];
}
rep(1,5,j)k[j]=(k[j]-1+mod[j])%mod[j];
rep(1,n,ww)
{
scanf("%s",b+1);
int len=strlen(b+1);
rep(1,len,i)
{
rep(1,5,j)
a[ww][j]=((ll)a[ww][j]*10+(b[i]-'0'))%mod[j];
}
}
int ans=0;
rep(1,n,i)rep(i,n,j)rep(j,n,K)
{
int flag=1;
rep(1,5,cc)
{
if(k[j]==0)
{
if(((ll)a[i][cc]+a[j][cc]+a[K][cc])%mod[cc])flag=0;
}
else if(((ll)a[i][cc]+a[j][cc]+a[K][cc])%mod[cc]%k[j])flag=0;
}
ans+=flag;
}
put(ans);
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 3856kb
input:
4 1 0 1 10 17
output:
3
result:
ok 1 number(s): "3"
Test #2:
score: 0
Accepted
time: 400ms
memory: 3940kb
input:
500 859 7118711592236878297922359501613604144948355616986970837340677671376753603836852811886591300370143151943368529129749813118476151865844255212534355441611481420938483178075143062691345257288242460282715389758789648541099090735875617822348551942134616963557723055980260082230902505269975518146286...
output:
0
result:
ok 1 number(s): "0"
Test #3:
score: -100
Time Limit Exceeded
input:
500 17336 11871159223687829792235950161360414494835561698697083734067767137675360383685281188659130037014315194336852912974981311847615186584425521253435544161148142093848317807514306269134525728824246028271538975878964854109909073587561782234855194213461696355772305598026008223090250526997551814628...
output:
0