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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#372086#6396. Puzzle: KusabiQingyyxWA 16ms74284kbC++174.3kb2024-03-30 21:21:232024-03-30 21:21:25

Judging History

你现在查看的是最新测评结果

  • [2024-03-30 21:21:25]
  • 评测
  • 测评结果:WA
  • 用时:16ms
  • 内存:74284kb
  • [2024-03-30 21:21:23]
  • 提交

answer

#include <bits/stdc++.h>
#define ll long long
#define enl putchar('\n')
#define all(x) (x).begin(),(x).end()
#define debug(x) printf(" "#x":%d\n",x);
using namespace std;
const int MAXN = 1e6 + 5;
const int inf = 0x3f3f3f3f;
const ll INF = 0x3f3f3f3f3f3f3f3f;
const int mod = 998244353;
typedef pair<int, int> pii;
char buf[1 << 21], * p1 = buf, * p2 = buf, obuf[1 << 21], * o = obuf, of[35];
#define gc()(p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++)
inline ll qpow(ll a, ll n) { ll res = 1; while (n) { if (n & 1)res = res * a % mod; n >>= 1; a = a * a % mod; }return res; }
inline int read() { int s = 0, f = 1; char c = gc(); for (; !isdigit(c); c = gc())if (c == '-')f = -1; for (; isdigit(c); c = gc())s = s * 10 + c - '0'; return s * f; }
inline void read(int* a, int n) { for (int i = 1; i <= n; ++i)a[i] = read(); }
inline int inal(char* s) { int n = 0; for (s[0] = gc(); !isalpha(s[0]); s[0] = gc()); for (; isalpha(s[n]); s[++n] = gc()); return s[n] = 0, n; }
inline void outd(int* a, int n) { for (int i = 1; i <= n; ++i)printf("%d ", a[i]); enl; }
int n, m, q;
struct EG {
    int to, nxt;
}e[MAXN << 1];
int head[MAXN], etot;
inline void add(int u, int v) {
    e[etot] = EG{ v, head[u] };
    head[u] = etot++;
}
void clear(int n = MAXN - 1) { memset(head + 1, -1, sizeof(int) * n); etot = 0; }
int fa[MAXN], dep[MAXN];
vector<pii>ans;
struct FFF {
    int com;
    struct CMP { bool operator()(int a, int b) { return dep[a] < dep[b]; } };
    priority_queue<int, vector<int>, CMP> q1, q2;  // 短 长
    bool del() {
        int s1 = q1.size(), s2 = q2.size();
        if (!s1 && !s2)return true;
        if (abs(s1 - s2) > 1)return false;
        vector<int>v1, v2;
        while (!q1.empty())v1.push_back(q1.top()), q1.pop();
        while (!q2.empty())v2.push_back(q2.top()), q2.pop();
        int rst = -1;
        if (s2 > s1)reverse(all(v1)), reverse(all(v2));
        for (int i = 0, j = 0; i < s1 && j < s2; ++i, ++j) {
            if (dep[v1[i]] >= dep[v2[j]]) {
                if (s1 == s2)return false;
                if (rst != -1)return false;
                if (s1 > s2)rst = v1[i], --j;
                else rst = v2[j], --i;
            } else {
                ans.push_back({ v1[i], v2[j] });
            }
        }
        if (s1 > s2) {
            if (rst != -1)q1.push(rst);
            else q1.push(v1[s1 - 1]);
        } else if (s1 < s2) {
            if (rst != -1)q2.push(rst);
            else q2.push(v2[s2 - 1]);
        }
        return true;
    }
}f[MAXN];
bool bfs() {
    vector<int>path;
    queue<int>q;
    q.push(1);
    while (!q.empty()) {
        int u = q.front(); q.pop();
        path.push_back(u);
        for (int i = head[u]; ~i; i = e[i].nxt) {
            q.push(e[i].to);
            dep[e[i].to] = dep[u] + 1;
        }
    }
    reverse(all(path));
    for (auto u : path) {
        if (!f[u].del())return !printf("NO\n");
        if (f[u].com && (f[u].q1.size() || f[u].q2.size()))return !printf("NO\n");
        if (f[u].com) {
            if (f[fa[u]].com)ans.push_back({ f[u].com, f[fa[u]].com }), f[fa[u]].com = 0;
            else f[fa[u]].com = f[u].com;
        }
        if (!f[u].q1.empty())f[fa[u]].q1.push(f[u].q1.top());
        if (!f[u].q2.empty())f[fa[u]].q2.push(f[u].q2.top());
    }
    return true;
}
void solve() {
    string s;
    cin >> n;
    clear(n);
    for (int i = 1; i < n; ++i) {
        int u, v; cin >> u >> v >> s;
        add(v, u); fa[u] = v;
        if (s == "Tong")f[u].com = u;
        else if (s == "Duan")f[u].q1.push(u);
        else if (s == "Chang")f[u].q2.push(u);
    }
    if (bfs()) {
        printf("YES\n");
        for (auto& [x, y] : ans)
            printf("%d %d\n", x, y);
    }
}
signed main(signed argc, char const* argv[]) {
    clock_t c1 = clock();
#ifdef LOCAL
    freopen("in.in", "r", stdin);
    freopen("out.out", "w", stdout);
#endif
    //=============================================================
    ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    int TxT = 1;
    while (TxT--)
        solve();
    //=============================================================
#ifdef LOCAL
    end :
    cerr << "Time Used:" << clock() - c1 << "ms" << endl;
#endif
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 16ms
memory: 74176kb

input:

8
2 1 -
3 1 -
4 2 Tong
5 2 Tong
6 3 Duan
7 3 -
8 7 Chang

output:

YES
5 4
6 8

result:

ok Correct.

Test #2:

score: 0
Accepted
time: 8ms
memory: 74084kb

input:

10
2 1 Duan
3 2 Duan
4 2 -
5 4 Chang
6 2 Chang
7 1 Duan
8 6 Tong
9 6 Tong
10 3 Chang

output:

YES
9 8
3 10
2 6
7 5

result:

ok Correct.

Test #3:

score: -100
Wrong Answer
time: 7ms
memory: 74284kb

input:

2
2 1 Tong

output:

YES

result:

wrong answer Only odd number of marked vertices to match.