#include<bits/stdc++.h>
using namespace std;
const int N = 2e6 + 10;
int n, m;
int a[1505][1505], b[1505][1505];

int dfs(int x1, int y1, int x2, int y2) {
    int sum = 0;
    for (int i = x1 + 1; i < x2; i++) 
    {
        if (a[i][y2 - 1] - a[i][y1 - 1] == y2 - y1) 
            return dfs(x1, y1, i, y2) + dfs(i, y1, x2, y2);
        sum += a[i][y2 - 1] - a[i][y1 - 1];
    }
    for (int j = y1 + 1; j < y2; j++) 
    {
        if (b[x2 - 1][j] - b[x1 - 1][j] == x2 - x1) 
            return dfs(x1, y1, x2, j) + dfs(x1, j, x2, y2);
        sum += b[x2 - 1][j] - b[x1 - 1][j];
    }
    return sum;
}

void solve() {
    cin >> n >> m;
    for (int i = 2; i <= n; i++)
    {
        string s;
        cin >> s;
        for (int j = 1; j <= m; j++)
        {
            a[i][j] = a[i][j - 1];
            if (s[j - 1] == '1')
                a[i][j]++;
        }
    }
    for (int i = 1; i <= n; i++)
    {
        string s;
        cin >> s;
        for (int j = 2; j <= m; j++)
        {
            b[i][j] = b[i - 1][j];
            if (s[j - 2] == '1')
                b[i][j]++;
        }
    }
    int f = dfs(1, 1, n + 1, m + 1);
    if (f)
        cout << "NO\n";
    else
        cout << "YES\n";
    return;
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);
    int tt = 1;
    while (tt--)
        solve();
    return 0;
}