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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#370442#4233. ResetInfinityNSWA 1ms4028kbC++202.1kb2024-03-29 07:46:112024-03-29 07:46:11

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你现在查看的是最新测评结果

  • [2024-03-29 07:46:11]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:4028kb
  • [2024-03-29 07:46:11]
  • 提交

answer

#include<bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
typedef long long ll;
using namespace std;
typedef pair<int,int> pii;

const int mod=998244353;
inline int add(int x,int y){int ret=x+y;if(ret>=mod)ret-=mod;return ret;}
inline int sub(int x,int y){int ret=x-y;if(ret<0)ret+=mod;return ret;}
inline int mul(int x,int y){return ((ll)x*y)%mod;}
inline int step(int base,int pw){int ret=1;while(pw){if(pw&1)ret=mul(ret,base);base=mul(base,base);pw>>=1;}return ret;}
inline int invv(int x){return step(x,mod-2);}


const int maxn=2e5+10;

ll c,n,t[maxn],d[maxn];

using int128=__int128_t;
typedef pair<ll,ll> pll;
bool check(ll mid){

    int128 total=min(((int128)mid+1)*min(n,c),(int128)1e18);
    multiset<pair<pll,ll>>st;

    for(int i=1;i<=n;i++){
        st.insert({ {d[i],t[i]},0 });
    }

    ll sum=0;
    ll cpc=c;
    while(st.size() && total>0){

        pair<pll,ll>x=(*st.rbegin());
        st.erase(st.find(x));

        int128 d=min(min(total,(int128)x.ff.ss/x.ff.ff), (int128)mid+1-x.ss );

        ///printf("%lld %lld %lld\n",d,x.ff.ff,x.ff.ss);

        x.ss+=d;
        x.ff.ss-=d*x.ff.ff;
        total-=d;
        x.ff.ff=min(x.ff.ff,x.ff.ss);

        if(x.ss==mid+1 || x.ff.ss==0){
            sum+=x.ff.ss;
            ///printf("%lld CPC\n",cpc);
            ///if(x.ss==mid+1)cpc--;
            continue;
        }
        st.insert(x);
    }
    if(total>(int128)min(n,c)*mid)cpc-=c-total%min(n,c);
    while(st.size()){
        sum+=(*st.begin()).ff.ss;
        st.erase(st.begin());
    }

    ///printf("%lld %lld | %lld AA\n",sum,cpc,mid);

    return sum<=cpc;
}

int main(){

    ///freopen("test.txt","r",stdin);

    scanf("%lld %lld",&n,&c);

    for(int i=1;i<=n;i++){
        scanf("%lld %lld",&t[i],&d[i]);
    }

    //check(249);
    //return 0;

    ll l=0;
    ll r=3e15;
    ll sr,ret=0;
    while(l<=r){
        sr=(l+r)/2;
        if(check(sr)){
            r=sr-1;
            ret=sr;
        }
        else l=sr+1;
    }
    printf("%lld\n",ret);

    return 0;
}

Details

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Test #1:

score: 0
Wrong Answer
time: 1ms
memory: 4028kb

input:

3 5
17 5
5 2
15 4

output:

2

result:

wrong answer 1st lines differ - expected: '3', found: '2'