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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#369947#7782. Ursa Minor1234huangTL 3ms14828kbC++204.3kb2024-03-28 19:55:242024-03-28 19:55:25

Judging History

你现在查看的是最新测评结果

  • [2024-03-28 19:55:25]
  • 评测
  • 测评结果:TL
  • 用时:3ms
  • 内存:14828kb
  • [2024-03-28 19:55:24]
  • 提交

answer

#include <bits/stdc++.h>
#define ull unsigned long long
using namespace std;

inline int read() {
	int x = 0, f = 0; char ch = getchar();
	while (ch < '0' or ch > '9') f |= (ch == '-'), ch = getchar();
	while (ch >= '0' and ch <= '9') x = (x << 1) + (x << 3) + (ch ^ 48), ch = getchar();
	return f ? -x : x;
}

int __stk[128], __top;
inline void write(int x) {
    if(x < 0) putchar('-'), x = -x;
	do { __stk[++__top] = x % 10, x /= 10; } while (x);
	while (__top) putchar(__stk[__top--] + '0');
}

const int mod = 998244353;

void Min(int &x, int y) { y < x and (x = y); }
void Max(int &x, int y) { y > x and (x = y); }

void inc(int &x, int y) { (x += y) >= mod and (x -= mod); }
void mul(int &x, int y) { x = 1ll * x * y % mod; }

int q_pow(int x, int k) { int res = 1; for (; k; k >>= 1, mul(x, x)) if (k & 1) mul(res, x); return res; }

bool stmer;

const int N = 2e5 + 10, M = 500, BL = 447;
const ull base = 127;

int n, m, q;

ull a[N], b[N], s[N];

namespace ST {
    const int LG = 20;

    int lg[N], st[LG][N];

    void init() {
        for (int i = 2; i <= m; i++) lg[i] = lg[i >> 1] + 1;
        for (int i = 1; i < LG; i++) for (int j = 1; j + (1 << i) - 1 <= m; j++)
            st[i][j] = __gcd(st[i - 1][j], st[i - 1][j + (1 << i - 1)]);
    }

    int ask(int l, int r) {
        int h = lg[r - l + 1];
        return __gcd(st[h][l], st[h][r - (1 << h) + 1]);
    }
}

namespace Block1 {
    ull S1[M][M], S2[M][M];

    void init() {
        for (int bl = 1; bl < BL; bl++) for (int i = 1; i <= n; i++) {
            int id = i / BL; ull w = a[i] * b[i % bl];
            S1[bl][id] += w, S2[bl][id] += (i % bl ? 0 : w);
        }
    }

    void modify(int p, ull v) {
        for (int bl = 1; bl < BL; bl++) {
            int id = p / BL; ull w = (v - a[p]) * b[p % bl];
            S1[bl][id] += w, S2[bl][id] += (p % bl ? 0 : w);
        }
    }

    bool query(int l, int r, int k) {
        int L = l / BL + 1, R = r / BL - 1; ull res = 0, s0 = 0, w;
        for (int i = L; i <= R; i++) res += S1[k][i], s0 += S2[k][i];
        while (l <= min(L * BL - 1 , r)) res += (w = a[l] * b[l % k]), s0 += (l++ % k ? 0 : w);
        while (r >= max(R * BL + BL, l)) res += (w = a[r] * b[r % k]), s0 += (r-- % k ? 0 : w);
        return res == s0 * s[k - 1];
    }
}

namespace Block2 {
    ull S1[M][M], S2[M];

    void init() {
        for (int i = 1; i <= n; i++) {
            int id = i / BL;
            S2[id] += (S1[id][i % BL] = a[i] * b[i]);
        }
        for (int i = 0; i <= n / BL; i++) {
            for (int j = 1; j < BL; j++) S1[i][j] += S1[i][j - 1];
            if (i) S2[i] += S2[i - 1];
        }
    }

    void modify(int p, ull v) {
        int id = p / BL; ull w = v * b[p] - a[p] * b[p];
        for (int i = p % BL; i < BL; i++) S1[id][i] += w;
        for (int i = id; i <= n / BL; i++) S2[i] += w;
    }

    ull ask(int l, int r) {
        return S2[r / BL - 1] - S2[l / BL - 1] + S1[r / BL][r % BL] - (l % BL ? S1[l / BL][l % BL - 1] : 0); 
    }

    bool query(int l, int r, int k) {
        ull res = 0, s0 = 0;
        while (l <= r) {
            res = res * b[k] + ask(l, l + k - 1);
            s0 += a[l], l += k;
        }
        return res == s0 * s[k - 1] * b[l - k];
    }
}

bool edmer;
signed main() {
	// freopen("gym104869F.in", "r", stdin);
	// freopen("gym104869F.out", "w", stdout);
	cerr << "[Memory] " << (&stmer - &edmer) / 1024 / 1024 << " MB\n";
	
    n = read(), m = read(), q = read();
    for (int i = 1; i <= n; i++) a[i] = read();
    for (int i = 1; i <= m; i++) ST :: st[0][i] = read();
    
    ST :: init(), b[0] = s[0] = 1;
    for (int i = 1; i < N; i++) s[i] = s[i - 1] + (b[i] = b[i - 1] * base);

    Block1 :: init(), Block2 :: init(), getchar();
    while (q--) {
        if (getchar() == 'U') {
            int p = read(), v = read();
            Block1 :: modify(p, v), Block2 :: modify(p, v), a[p] = v;
        }
        else {
            int l = read(), r = read(), s = read(), t = read();
            int k = __gcd(r - l + 1, ST :: ask(s, t));
            if (k < BL) puts(Block1 :: query(l, r, k) ? "Yes" : "No");
            else puts(Block2 :: query(l, r, k) ? "Yes" : "No");
        }
    }

    cerr << "[Runtime] " << (double) clock() / CLOCKS_PER_SEC << " seconds\n";
	return 0;
} 

詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 14828kb

input:

6 4 5
1 1 4 5 1 4
3 3 2 4
Q 1 5 1 2
Q 2 5 3 4
U 5 2
Q 1 6 1 2
Q 2 5 3 4

output:

Yes
No
No
Yes

result:

ok 4 tokens

Test #2:

score: 0
Accepted
time: 0ms
memory: 14100kb

input:

1 1 1
0
1
Q 1 1 1 1

output:

Yes

result:

ok "Yes"

Test #3:

score: -100
Time Limit Exceeded

input:

2000 2000 200000
1 1 2 0 0 2 0 2 0 0 0 0 0 2 2 1 2 0 0 2 2 2 1 0 1 2 1 2 0 0 1 1 1 2 0 0 2 2 2 2 0 2 0 0 2 1 2 0 0 1 2 2 1 0 2 0 0 0 1 2 2 1 2 2 0 0 1 1 1 0 0 2 0 0 1 1 0 2 2 2 1 0 0 1 0 1 2 2 2 1 1 2 2 1 2 1 0 2 2 3 1 3 2 3 1 0 1 2 0 1 1 1 0 2 2 3 2 0 3 2 3 3 1 2 3 1 2 0 1 0 3 1 0 0 2 0 1 2 1 3 2 2...

output:

Yes
Yes
Yes
No
Yes
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
No
Yes
Yes
No
No
No
No
No
Yes
No
No
No
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
No
Yes
Yes
Yes
No
No
Yes
No
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Ye...

result: